Ronnie kicks a playground ball with an initial velocity of 16 m/s at an angle of 40° relative to the ground. What is the approximate horizontal component of the initial velocity?

Answers

Answer 1

Answer: The horizontal component is calculated as:
Vhorizontal = V · cos(angle)

In your case Vhoriontal = 16 · cos(40) = 12.3 m/s

Answer: 12.3 m/s

Answer 2

Answer:

The approximate horizontal component of the initial velocity is 12.3 m/s

What is projectile?

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.

Given is Ronnie kicks a playground ball with an initial velocity of 16 m/s at an angle of 40° relative to the ground.

The horizontal component of the projectile is

Vx= V cosθ

Substitute the values, we get

Vx = 16 cos(40) =

Vx =12.3 m/s

Thus, approximate horizontal component of the initial velocity is 12.3 m/s.

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Force and Distance are Required to calculate which of the following

A fast car (Car A) and a slow car (Car B) both travel the same distance. Which car takes more time to do this? Explain.

Answers

Answer:

Input work is the work done on a machine as the input force acts through the input distance. This is in contrast to output work which is a force that is applied by the body or system to something else. Output work is the work done by a machine as the output force acts through the output distance.Jan 15, 2020 whhdbd dhd dvd s bs sbs shs shs sh s

Explanation:

avsvsyxsgzvs zvx shs dhx xbx dhd dvd dj

A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b and outer radius c. The outer cylinder is mounted on insulating supports and has no net charge. The inner cylinder has a uniform positive charge per unit length λCalculate the electric field
(a) At any point between the cylinders a distance r from the axis and
(b) At any point outside the outer cylinder.
(c) Graph the magnitude of the electric field as a function of the distance r from the axis of the cable, from r = 0 to r = 2c.
(d) Find the charge per unit length on the inner surface and on the outer surface of the outer cylinder.

Answers

Answer:

Part a)

$E = (\lambda)/(2\pi \epsilon_0 r)$

Part b)

$E = (\lambda)/(2\pi \epsilon_0 r)$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Explanation:

Part a)

By Guass law we know that

$\int E. dA = (q)/(\epsilon_0)$

$E. 2\pi rL = (\lambda L)/(\epsilon_0)$

$E = (\lambda)/(2\pi \epsilon_0 r)$

Part b)

Outside the outer cylinder we will again use Guass law

$\int E. dA = (q)/(\epsilon_0)$

$E. 2\pi rL = (\lambda L)/(\epsilon_0)$

$E = (\lambda)/(2\pi \epsilon_0 r)$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Final answer:

The electric field between the cylinders is given by E = λ / (2πε₀r). The electric field outside the outer cylinder is zero due to the absence of net charge. Graph the electric field magnitude using the equation E = λ / (2πε₀r). The inner surface charge of the outer cylinder is -λ and the outer surface charge is 0.

Explanation:

To calculate the electric field between the cylinders at a distance r from the axis, you can use Gauss's Law. Since the charging is uniform, the electric field will also be uniform. Therefore, the electric field at any point between the cylinders is given by E = λ / (2πε₀r), where ε₀ is the permittivity of free space.

To calculate the electric field at any point outside the outer cylinder, you can use the principle of superposition. The electric field due to the outer cylinder is zero because it has no net charge. The electric field due to the inner cylinder can be calculated using the same formula as before.

To graph the magnitude of the electric field as a function of the distance r from the axis, you can plot the equation E = λ / (2πε₀r) for values of r ranging from 0 to 2c.

The charge per unit length on the inner surface of the outer cylinder is -λ, while the charge per unit length on the outer surface of the outer cylinder is 0. This is because the outer cylinder has no net charge and the inner cylinder has a uniform positive charge per unit length λ.

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Distinguish between the positive and negative influences scientific knowledge can have on society

Answers

The positive influence of scientific knowledge can help to develop the society while the negative influence of scientific knowledge can harm the society through pollution.

Positive influence of scientific knowledge

The positive influence of scientific knowledge includes the followings;

Discovery of cure to diseases
Construction of roads
Generation of electricity, etc

Negative influences of scientific knowledge

The negative influence of scientific knowledge includes the followings;

Pollution of the environment
Deforestation, etc

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Answer:

The negative influences that scientific knowledge can have on a society is deforestation, pollution, animal suffering (in animal testing), biological weapons, and genetically altered foods.

Explanation:

An object placed in water will float if the weight of the object is MORE THAN the buoyant force of the water.True
False

Answers

False

If the object weighs more than the buoyant force then the object will sink.

This is because the buoyant force "pushes" the object upwards and the weight of the object "pushes" the object downwards. Since the force downwards is greater than the force upwards the item will sink, so this statement is False.

~~~Brainliest would be appreciated~~~

I think the answer is true

Irina rode her bike to work at an average speed of 16 miles per hour. It started to rain, so she got a ride home along the same route in her coworker’s car at an average speed of 27 miles per hour. If Irina’s ride home in the car took 24 minutes (0.4 of an hour), how many hours was her bike ride to work, to the nearest tenth of an hour?

Answers

Answer:

0.7 hours

Explanation:

From the way back, we can calculate the distance between Irina's work and Irina's home. In fact, we know that the car takes 0.4 hourse traveling at 27 mph, so the distance covered should be

$d=vt=(27 mph)(0.4 h)=10.8 mi$

When Irina rides to work with her bike, she travels at a speed of 16 mph. So we can find the time she takes by dividing the total distance (10.8 miles) by her speed:

$t=(d)/(v)=(10.8 mi)/(16 mph)=0.7 h$

Average speed of Irina riding home in her coworkers car = 27 miles per hour
Time taken by Irina to reach home = 0.4 hour.
Then
In 1 hour the car traveled for a distance = 27 miles
So in 0.4 hour, the distance traveled by the car = 27 * 0.4 miles
= 10.8 miles
Now
While traveling to office, Irina travels 16 miles in = 1 hour
So
Irina travels 10.8 miles in = (16/10.8) hours
= 1.48 hours.]
So Irina takes 1.48 hours of bike riding to reach her place of work.

How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?

Answers

It will take a car, 2.59 s to accelerate from 15.2 to 23.5 m/s.

What is Speed?

speed is described as. the pace at which an object's location changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it just has a direction and no magnitude.

Given, the car has an average acceleration of 3.2 m/s².

To solve this problem, we can use the following kinematic equation:

v = u +at

where:

v is the final velocity (23.5 m/s)

u is the initial velocity (15.2 m/s)

a is the acceleration (3.2 m/s^2)

t is the time

We can rearrange this equation to solve for t:

t = (v -u)/a

substituting the values we have:

t = (23.5 - 15.2 ) / 3.2

t = 2.59375 seconds

Therefore, it will take approximately 2.59 seconds for the car to accelerate from 15.2 m/s to 23.5 m/s with an average acceleration of 3.2 m/s².

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Hello!

How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s² ?

We have the following data:

Vf (final velocity) = 23.5 m/s

Vi (initial velocity) = 15.2 m/s

ΔV (speed interval) = Vf - Vi → ΔV = 23.5 - 15.2 → ΔV = 8.3 m/s

ΔT (time interval) = ? (in s)

a (average acceleration) = 3.2 m/s²

Formula: