In 1989, the Exxon Valdez spilled nearly 42,000,000 liters of oil into Prince William Sound, Alaska. How would this spill be classified?Abiotic environmental
Biotic environmental
Genetic
Pathogenic

Answers

Answer 1
Answer:

In biology and ecology, abiotic componentsor abiotic factorsare non-living chemical and physical parts of the environment thataffect living organisms and the functioning of ecosystems. Abiotic factorsand phenomena associated with them underpin all biology. So the oilspill is a non-living chemical

Answer 2
Answer:

Correct Answer:

A. Abiotic environmental

3 of 3 points


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Are all elements abbreviated with one or two letters? If not, name some that aren't.

Answers

Answer:

Some elements are abbreviated with more than two letters such as the Ununtrium (Uut), Ununpentium (Uup), Ununseptum (Uus) and Ununoctio (Uuo).

Explanation:

Some elements have intuitive symbology, such as Chlorine (Cl), among others, which are represented by the first letters that make up the name. However, there are others who receive symbols that do not remember the name of the element, such as Lead (Pb). Regardless of the similarity between the names and the symbol of the elements, most of them have the symbol composed of one or two letters, except for the elements Ununtrium (Uut), Ununpentium (Uup), Ununseptum (Uus) and Ununoctio (Uuo).

Some elements that are not abbreviated with one or two letters on the periodic table are Ununoctium (Uuo) and Ununtrium (Uut).

A substance is tested and is found to have the following physical properties: high electrical conductivity malleability high luster The substance is most likely a _____.

Answers

The substance is likely to be a metal. Many metals, such as gold, are extremely malleable (meaning that they can be pounded into thin sheets), have high conductivity due to free electrons, and are very shiny (high luster). 

Metal is most likely to be correct

How many total atoms are in 3(SO)4

Answers

Answer:

17 atoms are in 3(SO)4

Explanation:

Final answer:

There are 15 total atoms in 3(SO)4.

Explanation:

To find the total number of atoms in a chemical formula like 3(SO)4, you need to multiply the subscripts (the numbers outside the parentheses) by the number of atoms represented by each element within the parentheses and then multiply that by the coefficient (the number outside the formula).

In this case, you have:

3(SO)4.

Now, let's break it down:

The subscript for sulfur (S) is 1.

The subscript for oxygen (O) is 4.

So, for each (SO4) unit, you have 1 sulfur atom and 4 oxygen atoms.

Now, multiply this by the coefficient of 3:

3(SO)4. = 3 * (1 sulfur atom + 4 oxygen atoms)

= 3 sulfur atoms + 12 oxygen atoms

So, in 3(SO)4., there are a total of 3 sulfur atoms and 12 oxygen atoms, for a combined total of 15 atoms.

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Which polyatomic ion contains the greatest number of oxygen atoms?(1) acetate (3) hydroxide
(2) carbonate (4) peroxide

Answers

Carbonate ion contains the greatest number of oxygen atoms. So, the correct option is (2).

 

Polyatomic ion: refers to a charged chemical ion or species made up of two or more covalently joined atoms, or a metal complex that can be considered to behave as a single unit.

Acetate(C2H3O−) has two atoms of oxygen, carbonate has three oxygen atoms(CO_3^(2-)), hydroxide(OH)^(-) has one, and peroxide (H_2O_2)has two atoms of oxygen. Thus, carbonate has the highest number of oxygen atoms.  

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Answer:

The correct answer is option 2, that is, carbonate.

Explanation:

A molecular ion, also known as a polyatomic ion, refers to a charged chemical ion or species comprising two or more atoms that are combined covalently, or of a complex of a metal, which can be regarded to be functioning as a single unit.  

Of the given options, acetate has two atoms of oxygen, carbonate has three oxygen atoms, hydroxide has one, and peroxide has two atoms of oxygen. Thus, carbonate has the highest number of oxygen atoms.  

Which of the following is a physical or chemical characteristic of a mineral?

Answers

Minerals physical characteristics are hardness,luster,the way it’s solid and chemical would be the way the color changes and it’s density

Use the born-haber cycle to calculate the lattice energy of kcl. (δhsub for potassium is 89.0 kj/mol, ie1 for potassium is 419 kj/mol, ea1 for chlorine is −349 kj/mol, the bond energy of cl2 is 243 kj/mol, δh∘f for kcl is −436.5 kj/mol .)

Answers

Given data:

Sublimation of K

K(s) ↔ K(g)                            ΔH(sub) = 89.0 kj/mol

Ionization energy for K

K(s) → K⁺ + e⁻                         IE(K) = 419 Kj/mol

Electron affinity for Cl

Cl(g) + e⁻ → Cl⁻                      EA(Cl) = -349 kj/mol

Bond energy for Cl₂

1/2Cl₂ (g) → Cl                        Bond energy = 243/2 = 121.5 kj/mol

Formation of KCl

K(s) + 1/2Cl₂(g) → KCl(s)        ΔHf = -436.5 kJ/mol

To determine:

Lattice energy of KCl

K⁺(g) + Cl⁻(g) → KCl (s)                   U(KCl) = ?

Explanation:

The enthalpy of formation of KCl can be expressed in terms of the sum of all the above processes, i.e.

ΔHf(KCl) = U(KCl) + ΔH(sub) + IE(K) + 1/2 BE(Cl₂) + EA(Cl)

therefore:

U(KCl) = ΔHf(KCl) - [ΔH(sub) + IE(K) + 1/2 BE(Cl₂) + EA(Cl)]

         = -436.5 - [89 + 419 + 243/2 -349] = -717 kJ/mol

Ans: the lattice energy of KCl = -717 kj/mol



Final answer:

The lattice energy of KCl is calculated using the Born-Haber cycle by considering the energies of several steps including the sublimation of potassium, ionization of potassium, dissociation of Cl bond, electron affinity of Cl, and formation of KCl. The given values are plugged into a formula resulting in a lattice energy of -718 kJ/mol.

Explanation:

To calculate the lattice energy of KCl using the Born-Haber cycle, we need to follow several thermochemical steps. The steps include, first sublimation of potassium, the ionization of potassium, bond dissociation enthalpy to produce Cl, the electron affinity of Cl, and formation of KCl (s). Combining energy changes associated with all these steps would give us energy change for the formation of KCl from individual K and Cl2, it is called as enthalpy of formation (ΔH°f) for KCl.

Using the given values for each step, we use the formula: ΔH°f = ΔHsub + IE1 + 1/2* DCl2  - EA1 + lattice energy.

Substituting the given values, -436.5 = 89 + 419 + 1/2*243 -349 + lattice energy. Solving gives the lattice energy as -718 kJ/mol.

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