A cone has a circular base with a diameter of 18 inches. the height of the cone is 40 inches. what is the approximate lateral area of the cone? use 3.14 for π and round to the nearest whole number. 565 square inches 580 square inches 1,131 square inches 1,159 square inches
Answers
Lateral surface area of a cone: L = πrs = πr√(r^2 + h^2)
L = π(9)√(9^2 + 40^2)
L = 1159.248
Therefore, the correct answer is the last option. Hope this answers the question. Have a nice day.
To solve this problem, we have to use the formula of lateral surface area of a cone and substituting the values into the formula and then solve.
The lateral surface area of this cone is 2260.8in^2
Lateral Surface Area of a Cone
The lateral surface area of a cone is calculated using
The data in the question are
- diameter = 18in
- radius = 9in
- height = 40
- π = 3.14
Let's substitute the values into the equation and solve
The lateral surface area of this cone is 2260.8in^2
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The value of 3.6 - 2.4 ÷ (-0.8) is _____. 6.6 0.6 -1.5 3
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The corresponding point for the function f(x) - 4 is (2, -1)
What is a function?
A function in mathematics set up a relationship between the dependent variable and independent variable. on changing the value of the independent variable the value of the dependent variable also changes.
given that (2,3) is on the graph of f(x)
So, for x = 2, f(x) = f(2) = 3
Now, define another function g(x) such that
g(x) = f(x) - 4
g(2) = f(2) - 4
g(2) = 3 - 4 = -1
Hence, corresponding point for the function f(x) - 4 is (2, -1)
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So, for x = 2, f(x) = f(2) = 3
Now, define another function g(x) such that
g(x) = f(x) - 4
So g(2) = f(2) - 4 = 3 - 4 = -1
Hence, corresponding point for the function f(x) - 4 is (2, -1)
2x+y=19
2) 4x+8y=20
-4x+2y=-30
4) -6x+5y=1
6x+4y=-10
what are the answer to these three questions
Answers
For example, in number one.
x - y = 11
2x + y = 19
Both equations contain a variable expressed in the same numbers of negative and positive in each of them, one positive y and negative y. This lets us add the equations together.
x + 2x = 3x
11 + 19 = 30
3x = 30
x = 10
Now that we know that x = 10, we can plug it into the first equation, x - y = 11 to find y.
x - y = 11
10 - y = 11
y = -1
For the second one,
4x + 8y = 20
-4x + 2y = 30
Negate the x's since there is the same and opposite amount, while adding the rest of the equations together.
8y + 2y = 10y
20 + 30 = 50
10y = 50
y = 5
Plug it into the initial equation to find x
4x + 8(5) = 20
4x + 40 = 20
Subtract 40 from both sides
4x = -20
x = -5
For the third equation,
-6x + 5y = 1
6x +4y = -10
Negate the x's, add the rest together
5y + 4y = 9y
1 - 10 = -9
9y = -9
y = -1
Plug it into the first equation to find x
-6x + 5y = 1
-6x + 5(-1) = 1
-6x - 5 = 1
Add five to both sides
-6x = 6
Divide both sides by negative 6
x = -1
When the problems do not have the same value of opposite versions of current numbers, for example:
3x + 4y = 6
-6x +g = 6
You can multiply an entire equation to get similar numbers of a variable.
For example, you can multiply the first equation entirely by 2 to get the same number of positive x's to the negative x's in the second one, changing it to 6x x 8y = 12.
Hope I helped.
Answers
y=1/4 x-12
x=1/4 y -12 (exchange x and y)
1/4y=x+12
y=4(x+12) solve for y
y=4x+48
(3b − 4x)(3a − 2)
(3b + 4x)(3a − 2)
(3b + 4x)(3a + 2)
Answers
into two 2-term polynomials
+ 12ax + 9ab and - 6b - 8x
doesn't look that good to me so lest try other one :
9ab + 12ax and - 6b - 8x
looks good for now
Pull out from each binomial separately
9ab + 12ax = 3a • (3b + 4x)
- 6b - 8x = - 2 • (3b + 4x)
Add up to arrive at the desired factorization so now you have
(3a - 2) • (3b + 4x)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope that Helped!
Answer:
C: (3b + 4x)(3a − 2) is the correct answer.
Step-by-step explanation:
14/30
Answers
Divide both numbers by 2.
14 ÷ 2 = 7
30 ÷ 2 = 15
Your answer is 7/15
Answers
-3|6-x|<-15
==>|6-x|>5
1) if 6-x<0 then |6-x|=-6+x
==>-6+x>5==>x>11
2) if 6-x>0 then |6-x|=6-x
==>6-x>5==>6-5>x==>x<1
Solution is x<1 or x>11
---- -1 ------- 0 1 ----------- 11 ------------------------------
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