What are the variables of Boyle's law?pressure and number of molecules of gas
volume and temperature
pressure and temperature
volume and number of molecules of gas
pressure and volume

Answers

Answer 1

Answer: pressure and number of molecules of gas,volume and number of molecules of gas.

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A car climbs 10.0 kilometers up a hill that inclines 8.0 degrees. What is the car's vertical displacement?

Answers

The correct answer to the question is : $1.392\ Km$

CALCULATION:

The angle of inclination of the hill with the horizontal ground $\theta =\ 8^(0)$ .

The magnitude of displacement or the distance travelled by the car up that hill is given as -

distance S = 10.0 Km.

We are asked to calculate the vertical displacement.

Applying vector resolution process, we get-

(a) $Scos\theta$ is the horizontal component

(b) $Ssin\theta$ is the vertical component.

Hence, the vertical displacement is calculated as -

Vertical displacement $S_(y) =\ S\sin\theta$

$=\ 10* sin8^(0)$

= 1.392 Km.

Hence, the vertical displacement of the car is $1.392\ Km$

If you mix 40.0 ml of a 0.200 m solution of k2cro4 with an aqueous solution of agno3, what mass of solid forms? (hint: most chromates are insoluble.)

Answers

The mass of solid formed is 2.654 g

calculation

step 1: write the balanced molecular equation

=2AgNO3(aq) + k2CrO4(aq)→ Ag2CrO4(s) + 2 KNO3(aq)

step 2: calculate the moles of K2CrO4

moles = molarity x volume in liters

molarity = 0.200 M = 0.200 mol/L

volume = 40 .0 ml in liters = 40/1000 = 0.04 liters

moles is = 0.200 mol/l x0.04 L =0.008 moles

Step 3: use the mole ratio to determine the moles of solid formed( Ag2CrO4)

K2CrO4 :Ag2CrO4 is 1:1 therefore the moles of Ag2CrO4 is also

0.008 moles

step 4: calculate the mass of Ag2CrO4

mass = moles x molar mass

from periodic table the molar mass of Ag2Cro4

=(107.87 x2) + 52 +(16 x4) =331.74 g/mol

mass = 0.008 moles x 331.74 = 2.654 g

paperclips are more dense than water. however, it's possible to make them float. what property of water allows this? how does this property relate to the molecular structure of water

Answers

is it surface tension?

Why is most space exploration accomplished with spacecraft that do not have astronauts on board

Answers

Because of the enormous expense of creating conditions aboard
a spacecraft in which astronauts can survive, and the huge extra
weight and expense of guaranteeing their safety.

Answer:

Explanation:

so people dont have to risk their lives to discover space. They want to test its safety out by using rovers and other robots.

Calculate the speed of the ball, vo in m/s, just after the launch. A bowling ball of mass m = 1.5 kg is launched from a spring compressed by a distance d = 0.21 m at an angle of θ = 32° measured from the horizontal. It is observed that the ball reaches a maximum height of h = 4.4 m, measured from the initial position of the ball. Let the gravitational potential energy be zero at the initial height of the bowling ball.

Answers

Answer:

$v_0=17.3m/s$

Explanation:

In this problem we have three important moments; the instant in which the ball is released (1), the instant in which the ball starts to fly freely (2) and the instant in which has its maximum height (3). From the conservation of mechanical energy, the total energy in each moment has to be the same. In (1), it is only elastic potential energy; in (2) and (3) are both gravitational potential energy and kinetic energy. Writing this and substituting by known values, we obtain:

$E_1=E_2=E_3\n\nU_e_1=U_g_2+K_2=U_g_3+K_3\n\n(1)/(2)kd^2=mg(d\sin\theta)+(1)/(2)mv_0^2=mgh+(1)/(2)m(v_0\cos\theta)^2$

Since we only care about the velocity $v_0$ , we can keep only the second and third parts of the equation and solve:

$mgd\sin\theta+(1)/(2)mv_0^2=mgh+(1)/(2)mv_0^2\cos^2\theta\n\n(1)/(2)mv_0^2(1-\cos^2\theta)=mg(h-d\sin\theta)\n\nv_0=\sqrt{(2g(h-d\sin\theta))/(1-\cos^2\theta)}\n\nv_0=\sqrt{(2(9.8m/s^2)(4.4m-(0.21m)\sin32\°))/(1-\cos^232\°)}\n\nv_0=17.3m/s$