Describe the results of Ernest Rutherford's gold-foil experiment and explain how his results changed ideas about the distribution of positive charge within the atom.

Answers

Answer 1
Answer: Ernest Rutherford applies alpha particle towards an atom, some atom showed deflection by smaller angle, very few through large angle and many just passed without any deflection.

His results changed the idea for distribution of positive charges as he concluded almost all the positive charge is in center of the atom (inside nucleus) and it is very heavy than electrons which revolves outside the nucleus

Hope this helps!
Answer 2
Answer: Physicist Ernest Rutherford established the nuclear theory of the atom with his gold-foil experiment. When he shot a beam of alpha particles at a sheet of gold foil, a few of the particles were deflected. He concluded that a tiny, dense nucleus was causing the deflections.

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Select all that apply. The requirements for one type of atom to substitute for another in a solid solution are:a. All substitutions must be limited to the same element.b. An atom must be identical in size.c. An atom must be similar in size.d. The substituting atom must be from the same period. E) The substituting atom must be from the same group.

A metal melts at 450 degrees celsius. Is this property of the metal classified as chemical or physical?

Answers

Answer:

physical

Explanation:

because if you let it cool down it will turn back into its original form

When 50. milliliters of an HNO3 solution isexactly neutralized by 150 milliliters of a 0.50 M
solution of KOH, what is the concentration of
HNO3?
(1) 1.0 M (3) 3.0 M
(2) 1.5 M (4) 0.5 M

Answers

Answer : The correct option is, (2) 1.5 M

solution :

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of HNO_3 solution = ?

V_1 = volume of HNO_3 solution =  50 ml

M_2 = molarity of KOH solution = 0.50 M

V_2 = volume of KOH solution = 150 ml

Now put all the given values in the above law, we get the volume of HNO_3 solution.

M_1* (50ml)=(0.50M)* (150ml)

M_1=1.5M

Therefore, the concentration of HNO_3 is, 1.5 M

The reaction formula is HNO3 + KOH = KNO3 + H2O. The mole number of HNO3 and KOH is the same. So the concentration of HNO3 is 150*0.5/50=1.5 M. So the answer is (2).

What holds solid sodium together?A. hydrogen bonding
B. metallic bonding
C. ionic bonding
D. dipole forces
E. van der Waals forces (London dispersion forces)

Answers

I'm pretty sure it's Metallic bonding

Descreva as principais caracteristícas dos compostos ionicos

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a) They are solid at ambient temperatures of 25 ° C and pressure of 1 atm.

b) Ionic compounds represent high temperature melting and boiling.

 c) They are hard and brittle and then subjected to the impact, break easily, creating planar faces.

d) When dissolved in water, or pure liquid, carry electrical current due to the existence of ions that move freely and can be attracted by the electrodes, closing the electric circuit.

e) His solvent is water. 

Determime the number of moles in the following compounds; a. 125 g of H2SO4 b. 35 g of CuSO4 × 5H2O

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Mr of H2SO4 = 2+32+64= 98g No. Of moles = 125/98= 1.28 moles. B) Mr of CuSO4 = 64+32+64=160 Mr of 5H2O = 18x5=90 CuSO4.5H2O = 160+ 90 = 250g No. Of moles = 35/250= 0.14 moles

A gas that extinguishes a flame is hydrogen. true or false

Answers


This is true because it reacts with oxygen