Answer: He cut 6 slices of bread.
Step-by-step explanation:
Given : Jared ate of a loaf of bread.
Then , the reaming portion of the bread will be .
The size of each slice = of a bread.
N ow , the number of slices he cut the remaining portion =
Hence, the number of slices of bread he cut = 6.
t÷13
t-13
13+t
13t
Answer:
13t
Step-by-step explanation:
The fractions is solved and the improper fraction is A = 29/8
Given data ,
To change 3 5/8 into an improper fraction, we need to combine the whole number and the fraction part.
The fraction part, 5/8, can be expressed as an improper fraction by multiplying the whole number, 3, by the denominator of the fraction, 8, and then adding the numerator, 5. This gives us:
3 * 8 + 5 = 24 + 5 = 29
The denominator remains the same, so the improper fraction is:
A = 29/8
Therefore , the value of A = 29/8
Hence , 3 5/8 can be expressed as the improper fraction 29/8
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Answer:
The improper fraction 29/8 is equal to the mixed number 3 5/8.
Step-by-step explanation:
Answer:
The correct options are 1, 3 and 4.
Step-by-step explanation:
It is given that Lupe has 14 stickers that she wants to give to 2 friends.
Total number of stickers Lupe has is 14.
The number of friends is 2.
She wants each friend to have the same number of stickers. It means each friend will get half of 14.
The number stickers Lupe should give to her friends is 14 divided by 2.
Write this value in fraction form.
It means the correct statements are
1. Each friend gets 14÷2 stickers.
3. Each friend gets (14)/2 stickers.
4. Each friend gets 7 of the 14 stickers.
Hence correct options are 1, 3 and 4.
Answer:
Speed = distance / time
= 6/3 =2 ft/sec
Time = distance / speed
= 60/2
= 30 seconds
²-1
We will investigate the behavior of
both the numerator and denominator of h(x) near the point where x = 1. Let
f(x)= x³ + x -2 and g(x)=x²-1. Find the local linearizations of f and g at a = 1,
and call these functions Lf(x) and Lg(x), respectively.
Lf(x) =
L₂(x) =
Explain why h(x) ≈
Lf(x)
Lg(x)
for a near a = 1.
The local linearizations of f(x) and g(x) at a = 1 are Lf(x) = 4x - 5 and Lg(x) = 2x - 2 respectively. The function h(x) ≈ Lf(x)/Lg(x) because the local linearizations provide a good approximation of the numerator and denominator of h(x) near x = 1.
The local linearization of a function at a given point is an approximation of the function using a linear equation. To find the local linearization of a function f at a = 1, we need to find the slope of the tangent line at a = 1, which is equivalent to finding the derivative of f at x = 1. By taking the derivative of f(x) = x³ + x - 2, we get f'(x) = 3x² + 1. Evaluating f'(1), we find that the slope of the tangent line at a = 1 is 4. Therefore, the local linearization of f at a = 1, denoted as Lf(x), is given by Lf(x) = f(a) + f'(a)(x - a), which becomes Lf(x) = -1 + 4(x - 1) = 4x - 5.
Similarly, to find the local linearization of g(x) = x² - 1 at a = 1, we need to find the slope of the tangent line at a = 1. The derivative of g(x) is g'(x) = 2x. Evaluating g'(1), we find that the slope of the tangent line at a = 1 is 2. Therefore, the local linearization of g at a = 1, denoted as Lg(x), is given by Lg(x) = g(a) + g'(a)(x - a), which becomes Lg(x) = 0 + 2(x - 1) = 2x - 2.
When investigating the behavior of the function h(x) = (f(x))/(g(x)) near the point x = 1, we can approximate h(x) using the local linearizations of f and g at a = 1. Near the point a = 1, h(x) ≈ Lf(x)/Lg(x) because Lf(x) and Lg(x) provide a good approximation of the numerator and denominator, respectively, of h(x). This approximation holds as long as x is close to 1.