How many times does 5 go into 100

Answers

Answer 1
Answer: I believe in this item, we are asked to determine how many 5's should be added together in order to form 100. This is calculated by dividing 100 by 5. The answer by completing the operation would be equal to 20. Hence, the answer is 20.

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Suppose theta= 11pi/12. How do you use the sum identity to find the exact value of sin theta?

Answers

The better way is, first we have to find the equivalent in degrees

2\pi=360\º

(11\pi)/(12)=345\º

now we can change this value to -15\º

how do we get an angle like this?!

30\º-45\º=-15\º

then

sin(30\º-45\º)=sin(30\º)*cos(45\º)-sin(45\º)*cos(30\º)

\begin{Bmatrix}sin(30\º)&=&(1)/(2)\n\nsin(45\º)&=&cos(45\º)&=&(√(2))/(2)}\end{matrix}\n\ncos(30\º)&=&(√(3))/(2)\end{matrix}

now we replace this values

sin(-15\º)=(1)/(2)*(√(2))/(2)-(√(2))/(2)*(√(3))/(2)

sin(-15\º)=(√(2))/(4)-(√(6))/(4)

\boxed{\boxed{sin(-15\º)=sin(345\º)=(√(2)-√(6))/(4)}}

Simplify fully
a) 8c²d^5 ÷ 2c³d³
b) 9a³b^5 ÷ 3ab²

Answers

Answer:

Step-by-step explanation:

In exponent division, if base are same , subtract the exponents.

(a^(m))/(a^(n))=a^(m-n) , m>n\n\n (a^(m))/(a^(n))= (1)/(a^(n-m)), m<n

a) 8c²d⁵ ÷ 2c³d³ = (8)/(2)* (d^(5-3))/(c^(3-2))=  4*(d^(2))/(c)= (4d^(2))/(c)

b) 9a³b⁵ ÷ 3ab² = (9)/(3)* a^(3-1)*b^(5-2) = 3a^(2)b^(3)

Answer:

A) 8d^2/3c

B) 3a^2b^3

Step-by-step explanation:

Find the slope, if it exists, of the line containing the pair of points. (-17,-9) and (-19-18) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The slope is (write an integer or a simplified fraction.)_________ B. The slope is undefined.________

Answers

Answer:

the slope is (9)/(2)

Step-by-step explanation:

calculate the slope m using the slope formula

m = (y_(2)-y_(1) )/(x_(2)-x_(1) )

let (x₁, y₁ ) = (- 17, - 9 ) and (x₂, y₂ ) = (- 19, - 18 )

substitute these values into the formula for m

m = (-18-(-9))/(-19-(-17)) = (-18+9)/(-19+17) = (-9)/(-2) = (9)/(2)

A rectangle is twice as long as it is wide. it's width is 5 1/2 cm. find the area of the rectangle.

Answers

Area of rectangle having length 11 cm and breadth 11/2 cm is 121/2 cm² .

Given, that length of rectangle is double that of its width.

Area of rectangle = l × b
l = Length of rectangle .

b = Breadth of rectangle .

As length of rectangle is double of width.

Width = 11/2 cm

Length = 2 × (11/2) cm

Length = 11 cm

Substitute the values in the area formula,

Area of rectangle = l × b

Area of rectangle = 11 * (11)/(2)

Area of rectangle = (121)/(2)  cm^2

Therefore the area of rectangle is (121)/(2)  cm^2 .

Know more about rectangle,

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  A rectangle is twice as long as it is wide. it's width is 5 1/2 cm. find the area of the rectangle.   
 
answer: 60 1/2 cm.

What is 32 over 64 reduced too

Answers

so 32/64
divide the top and bottom by 32
1/2
the answer is 1/2

Assume that you deposit $833 into an account that pays 7 percent per annum. How much money will be in the account 15 years from today?

Answers

Answer:

$2,676.46

Step-by-step explanation: