Round the following number to three significant figures: 156.5021 L

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Answer 1
Answer: you round the 6 to a seven because there is a five following the decimal157

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What have you observed when you fill in a basin with water? how do you do it?​

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When you fill a basin with liquid water, you can see that the water takes the shape of the container in which it is contained. This is because in the liquid state, water has molecules farther apart than in the solid state.

You can notice this property when performing an experiment with liquid and solid water.

When filling a glass, liquid water takes on the shape of a glass, and solid water, such as an ice cube, remains the same shape when placed in a glass.

Therefore, when filling a basin with water we perceive a property of the physicalstate of water, in liquid form. Water is one of the few substances that can be found naturally in liquid, solid and gaseous states.

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Answer:

Cautiously and avoiding filling in the central area so that it does not overflow when filling, since being very beach makes filling difficult.

Explanation:

The basins are shallow, that is why filling is difficult, the filling must be slow, low intensity and at the edges not placing the water filling in the center of the basin.

Describe the range of radii of most atoms in nanometers (nm)

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Final answer:

The range of radii of most atoms is typically in the nanometer scale (nm) and can be measured using the covalent radius. The size of an atom's nucleus is much smaller than the atom itself. The Bohr model provides a formula to calculate the radius of hydrogen-like atoms.

Explanation:

The range of radii of most atoms is typically in the nanometer scale (nm). The covalent radius, which is defined as half the distance between the nuclei of two identical atoms when they are joined by a covalent bond, provides a practical way to measure the size of atoms. As we move down a group in the periodic table, the covalent radius generally increases, indicating a larger size of the atom. For example, the covalent radius of the halogens increases as we move from fluorine to iodine.

The size of an atom's nucleus, on the other hand, is much smaller than the atom itself. The nucleus has a diameter of about 10-15 meters, while the typical atom has a diameter of the order of 10-10 meters. This difference in size illustrates the emptiness of atoms, with the distance from the nucleus to the electrons being typically 100,000 times the size of the nucleus.

The Bohr model provides a formula to calculate the radius of hydrogen-like atoms, which depends on the principal quantum number (n) and the atomic number (Z). The calculated radii of the orbits of the hydrogen atom have been experimentally verified to have a diameter of a hydrogen atom.

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Final answer:

The range of radii of most atoms is typically measured in nanometers (nm). Covalent radius and hydrogen-like orbits are two methods used to estimate the size of atoms. The size of an atom can vary depending on the element and measurement technique, but most atoms have radii on the order of nanometers (nm).

Explanation:

The range of radii of most atoms is typically measured in nanometers (nm). The size of an atom can be estimated using various techniques. One commonly used measure is the covalent radius, which is defined as one-half the distance between the nuclei of two identical atoms when they are joined by a covalent bond. The covalent radii of different elements can be found in tables and can vary depending on the element and its position in the periodic table.

Another way to estimate the size of atoms is by looking at the sizes of their orbits in hydrogen-like atoms. These orbits are given in terms of their radii by a mathematical expression that includes a constant called the Bohr radius, which is approximately 5.292 × 10-11 m.

Overall, the size of an atom can vary depending on the element and the specific measurement technique used, but most atoms have radii on the order of nanometers (nm).

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I need help!! ASAP please..

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Answer:

164 g

Explanation:

PLZZZZZZZZZZZZ HELPPPPPPPPP BRAINLIEST FOR WHO GETS IT RIGHTTTTTTWhat is the mass of reactants in the following equation?N2 + 3H2 ----> 2NH3
Question 3 options:


34.05 amu


31.03 amu


30.02 amu


15.01 amu

Answers

Answer: 34.05

Explanation:

2N and 6H = abt 34

Need help I don't remember what to do?

Answers

I'm just doing the ones that you don't have numbers already for.
2.) just leave it alone and it's correct
3.) Mg + 2AgNo3 --> Mg(No3)2 + 2Ag
5.) just leave it alone and it's correct
8.) 10C3H8O3 + 15O2 --> 30CO2 + 4H2O
10.) P4 + 6Br2 --> 4PBr3
12.) 2FeCl3 + 6NaOH --> 2Fe(OH)3 + 6NaCl
13.) 2CH3OH + 3O2 --> 2CO2 + 4H2O
14.) 2Al + 3Cu(NO3)2 --> 2Al(NO3)3 + 3Cu
15.) 3CaCl2 + 2K3AsO4 --> Ca3(AsO4)2 + 6KCl
16.) 2NH3 --> N2 + 3H2
17.) 2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O
19.) Mg3N2 + 6H2O --> 3Mg(OH)2 + 2NH3
I hope this helps you!!

Consider the dissolution of AB(s):AB(s)⇌A+(aq)+B−(aq)Le Châtelier's principle tells us that an increase in either [A+] or [B−] will shift this equilibrium to the left, reducing the solubility of AB. In other words, AB is more soluble in pure water than in a solution that already contains A+ or B− ions. This is an example of the common-ion effect.The generic metal hydroxide M(OH)2 has Ksp = 1.05×10−18. (NOTE: In this particular problem, because of the magnitude of the Ksp and the stoichiometry of the compound, the contribution of OH− from water can be ignored. However, this may not always be the case.)What is the solubility of M(OH)2 in pure water?

Answers

Answer:

S = 6.40 × 10⁻⁷ M

Explanation:

In order to calculate the solubility (S) of M(OH)₂ in pure water we will use an ICE Chart. We recognize 3 stages: Initial, Change and Equilibrium, and we complete each row with the concentration or change in concentration.

            M(OH)₂(s) ⇄ M²⁺(aq) + 2 OH⁻(aq)

I                                   0                  0

C                                 +S               +2S

E                                   S                 2S

The solubility product (Kps) is:

Kps = 1.05 × 10⁻¹⁸ = [M²⁺].[OH⁻]²=S.(2S)²

1.05 × 10⁻¹⁸ = 4S³

S = 6.40 × 10⁻⁷ M