A load of 600 N is lifted using a first-class lever applying an effort of 350 N. If the distance between the fulcrum and the effort is 60 cm, calculate load distance

Answers

Answer 1

Answer:

Explanation:

Hope it will help you a lot.

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The cloud of interstellar dust and gas that forms a star is known as a A. protostar.
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15. With an average surface temperature of about 737 K, _______ is the hottest planet.
A. Mars
B. Mercury
C. Earth
D. Venus

Answers

Correct answer choice for question 1 is:

D) Nebula.

Explanation:

A nebula is an interstellar cloud of dust, hydrogen, helium and other ionized vapors. Basically, the nebula was a sign for any distributed enormous object, including galaxies behind the Milky Way. Most nebulae are of a large size, some are numbers of light years in diameter. A nebula that is almost visible to the human eye from Earth would appear larger, but no flashing, from close by. The Orion Nebula, the glowing nebula in the sky that controls a region twice the diameter of the full Moon, can be observed with the naked eye but was dropped by early scientists.

Correct answer choice for question 2 is :

D) Venus

Explanation:

Venus is the second planet from the Sun, revolving it every 224.7 Earth days. It has the largest revolution time of any planet in the Solar System and turns in the different direction to most other planets. It does not have any real satellites. It is the second glowing natural object in the night sky after the Moon, leading an obvious magnitude of 4.6 bright quite to throw shadows at night and, unusually, obvious to the naked eye in full daylight.

The cloud of interstellar dust and gas that forms a star is known as a nebula. With an average surface temperature of about 737K, venus is the hottest planet. Hope this helps, and sorry your question didn't get answered in time.

The active sections that are located along fault lines are called A. seismic gaps.
B. seismic risks.
C. stress accumulations.
D. recurrence gaps

Answers

B. seismic risks.

The active sections that are located along fault lines are called seismic risks.
NOT:

A. seismic gaps.
C. stress accumulations.
D. recurrence gaps

If you walk with a speed of 2.0m/s for 2.0h how far would you travel

Answers

Answer:

14,400 meters

Explanation:

yes

The power expended when a 10 N barbell is raised 2. 0 m in 2s is

Answers

Work done = (force) x (distance)
   = (10 N) x (2 m) = 20 joules .

Power = (work done) / (time to do the work)
   =       (20 J) / (2 sec)
   = 10 joules/sec = 10 watts .

Element found in most of the compounds in ur body except for

Answers

Except for water, most of the compounds in your body contain carbon.

A puck moves 2.35 m/s in a -22° direction. A hockey stick pushes it for 0.215 s, changing its velocity to 6.42 m/s in a 50.0° direction. What was the direction of the acceleration?

Answers

The puck starts with velocity vector

$\vec v_0=\left(2.35(\rm m)/(\rm s)\right)(\cos(-22^\circ)\,\vec\imath+\sin(-22^\circ)\,\vec\jmath)=(2.18\,\vec\imath-0.880\,\vec\jmath)(\rm m)/(\rm s)$

Its velocity at time $t$ is

$\vec v=\vec v_0+\vec at$

Over the 0.215 s interval, the velocity changes to

$\vec v=\left(6.42(\rm m)/(\rm s)\right)(\cos50.0^\circ\,\vec\imath+\sin50.0^\circ\,\vec\jmath)=(4.13\,\vec\imath+4.92\,\vec\jmath)(\rm m)/(\rm s)$

Then the acceleration must have been

$\vec v=\vec v_0+(0.215\,\mathrm s)\vec a\implies\vec a=(\vec v-\vec v_0)/(0.215\,\rm s)=(9.06\,\vec\imath+27.0\,\vec\jmath)(\rm m)/(\mathrm s^2)$

which has a direction of about $71.4^\circ$ .

Final answer:

The direction of the acceleration is determined by the direction of the change in velocity. This would be calculated by subtracting the initial velocity vector from the final velocity vector. However, the calculation would involve complex trigonometric functions.

Explanation:

In order to find the direction of the acceleration, we need to calculate the direction of the change in velocity and that direction will be the direction of the acceleration.

To calculate the change in velocity, we subtract the initial velocity from the final velocity: (6.42 m/s, 50.0°) - (2.35 m/s, -22°). We then calculate the angle of this vector which represents the change in velocity, and hence the direction of acceleration.

However, this calculation is not straightforward because it involves vector operations and would require the use of trigonometric functions to solve. This is due to the fact that velocity is a vector, meaning it has both a magnitude and a direction. Consequently, this becomes a multi-step process involving trigonometry and physics.

Learn more about Direction of Acceleration here:

brainly.com/question/33720661

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