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A weight of 12. 0 n hangs motionless from a spring, with a spring constant of 10. 0 n/m. How far is the spring stretched from its original length? 0. 120 m 0. 220 m 0. 833 m 1. 20 m.

Answers

Answer 1
Answer:

The extension of this spring from its original length is equal to 1.2 meter.

Given the following data:

  • Weight = 12 Newton
  • Spring constant = 10 N/m

To calculate the extension of this spring from its original length:

How to solve for extension.

Mathematically, the force acting on a spring is given by the formula:

F=ke

Where:

  • K is the spring constant.
  • e is the extension.

Making e the subject of formula, we have:

e=(F)/(k)

Substituting the given parameters into the formula, we have;

e=(12)/(10)

Extension, e = 1.2 meter.

Read more on spring constant here: brainly.com/question/14372859

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