You are experiencing issues when trying to transfer files between two computers using FTP. What could be the potential cause(s) of the issue

Answer:

C.system prototyping

Explanation:

Prototyping produces a quickly constructed working version of the proposed information system.

Planning

↓

Analysis

↓

Design

↓

System prototyping

↓

Implementation

Answer:

c. system prototyping

Explanation:

system prototyping  produces a full-featured, working model of the information system.

Answer:

A decoder is a circuit which has n inputs and 2n outputs, and outputs 1 on the wire corresponding to the binary number represented by the inputs. For example, a 2-4 decoder might be drawn like this:

and its truth table (again, really four truth tables, one for each output) is:

i1  i0  d3  d2  d1  d0

0 0 0 0 0 1

0 1 0 0 1 0

1 0 0 1 0 0

1 1 1 0 0 0

Explanation:

The following circuit generates all four minterms from two inputs, and implements the 2-4 decoder.

Answer:

I am writing a Python program:

def string_finder(target,search): #function that takes two parameters i.e. target string and a search string

   position=(target.find(search))# returns lowest index of search if it is found in target string

   if position==0: # if value of position is 0 means lowers index

       return "Beginning" #the search string in the beginning of target string

   elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings

       return "End" # returns end

   elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1

       return "Middle" #returns middle        

   else: #if none of above conditions is true return not found

       return "not found"

#you can add an elif condition instead of else for not found condition as:

#elif position==-1    

#returns "not found"

#tests the data for the following cases      

print(string_finder("Georgia Tech", "Georgia"))

print(string_finder("Georgia Tech", "gia"))

print(string_finder("Georgia Tech", "Tech"))

print(string_finder("Georgia Tech", "Idaho"))

Explanation:

The program can also be written in by using string methods.

def string_finder(target,search):  #method definition that takes target string and string to be searched

       if target.startswith(search):  #startswith() method scans the target string and checks if the (substring) search is present at the start of target string

           return "Beginning"  #if above condition it true return Beginning

       elif target.endswith(search):  #endswith() method scans the target string and checks if the (substring) search is present at the end of target string

           return "End"#if above elif condition it true return End

       elif target.find(search) != -1:  #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string

           return "Middle"  #if above elif condition it true return End

       else:  #if none of the above conditions is true then returns Not Found

           return "Not Found"

Answer:

Algorithm:

1.Create a variable N.

2.Read the value of N from user.

3.for i=1 to N.

 3.1 Print value of i.

4.end program.

Implementation in C++:

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variable

int N;

cout<<"Enter value of N:";

// read the value of N

cin>>N;

cout<<"Natural number from 1 to "<<N<<" are:";

for(int i=1;i<=N;i++)

{

// print the numbers

   cout<<i<<" ";

}

return 0;

}

Output:

Enter value of N:6                                                                                                        

Natural number from 1 to 6 are:1 2 3 4 5 6

2 < 3 and 5 < 1 is false because 5 is not less than 1.

3 < 3 or 1 <= 1 is true because 1 is less than or equal to 1.

Not (2 = 3) is true because the opposite of 2 = 3 is true