Explain it - compare 3 3/22 & 3 2/33. which is greaterI Know:
 Multiply the denominator by the whole number then add numerator to that.
 Now I have 69/66 & 101/99

 THe LCM is 66


what next, which is greater. Thank you

Answers

Answer 1
Answer: 3 3/22 isn't 69/66.
3 3/22 is like 3+3/22. To sum them,you have to have the same denominator. So 3=66/22. Know you can add them, so 3 3/22=3+ 3/22= 66/22+3/22=69/22.
Same way, 3 2/33= 3+2/33=99/33+2/33=101/33.
Know you have to compare 69/22 with 101/33. For this, you need to get them to the same denominator. So you multiply 69/22 with 3, and 101/33 with 2. Know you have to compare 207/66 with 202/66. Obviously, the first one is bigger, because 207>202. So in the end, 3 3/22> 3 2/33

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A lawn sprinkler spins in a circle. The sprinkler covers a radius of 4 feet. Which choice is the closest to the area of lawn that the sprinkler can cover? 13 25 50 or 200..

Answers

The required area that the sprinkler will cover is 50 square feet. Option C is correct.

As mentioned in the question, a lawn sprinkler spins in a circle. The sprinkler covers a radius of 4 feet.

What is surface area?

The surface area of any shape is the area of the shape that is faced or the Surface area is the amount of area covering the exterior of a 3D shape.

Here,
Area of the sprinkler,
=  area of the circle
= πr²
= 3.14 × 4²
= 50.24
≈50
                               

Thus, the required area that the sprinkler will cover is 50 square feet. Option C is correct.

Learn more about the surface area here: brainly.com/question/2835293

#SPJ2

When you are trying to cover something,it would be AREA not Circumference since Circumference is the outside of a circle.Area is inside of a circle,so the formula for area is:pix4² which will equal,16pi or 50.26548246 so the closest area of lawn that the sprinkler can cover is 50.

A teacher needs 256 lengths of string cut to 40cm each. If balls of string are 30M long, how many balls are needed?

Answers

First you need to work out how much string is needed -
256 pieces needed x 40cm each:
256 x 40 = 10240cm

Then, convert to metres (100cm = 1m)
10240 / 100 = 102.4m

Then, you work out how many balls are needed:
30 can fit into 102.4 3 times with .41m to spare. So, you need three balls of string, PLUS another one to cover the 41cm

So to conclude: 4 balls of string are needed.

If sin 0 = 4/5 then what is cos(90-0)

Need answer in fraction

Answers

The result would be back to 4/5.

You can test this by finding the solving for theta when sin(theta) = 4/5. Then, enter that value into the expression cos(90 - theta). You will be back to just 4/5.

A sphere has a radius of 6 meters. A second sphere has a radius of 3 meters. What is the difference of the volumes of the spheres?

Answers

Answer:

791. 28 m^3\n

Step-by-step explanation:

Volume of sphere with 6 meter radius

= (4)/(3) \pi r^3\n= (4)/(3) (3.14) ( 6^3)\n= 904.32 m^3\n

Volume of sphere with 3 meter radius

= (4)/(3) \pi r^3\n= (4)/(3) (3.14) ( 3^3)\n= 113.04 m^3\n

Difference between the volume of two sphere

= (904 .32 m^3)- ( 113.04 m^3)\n= 791.28 m^3\n

∆volume = 4/3 *pi * (R^3 -r^3 )
= 4/3 *pi*((6)^3 -(3)^3)
= 252*pi
= 791.68 m^3

3x+y=9 and 3x=9-y solve each system by elimination to prove your answer, I am stuck on this one

Answers

Infinitely many solutions.I will try to solve your system of equations.3x+y=9;3x=−y+9Step: Solve3x+y=9for y:3x+y+3x=9+3x(Add -3x to both sides)y=3x+9Step: Substitute3x+9foryin3x=−y+9:3x=−y+93x=(3x+9)+93x=3x(Simplify both sides of the equation)3x+3x=3x+3x(Add -3x to both sides)

so ur answer is
Infinitely many solutions.


How much money should be invested now (rounded to the nearest cent), called the initial investment, in a Municipal Bond investment that yields 6% per year, compounded monthly for 10 years, if you wish it to be worth $20,000 after 10 years?

Answers

The formula for annual compound interest, including principal sum, is:
A = P (1 + r/n)ⁿˣ

A = the future value = $ 20,000
P = the principal investment amount = Not given
r = the annual interest rate (decimal) = 0.06
n = the number of times that interest is compounded per year = 12
x = the number of years = 10

$ 20,000 = P (1 + 0.06/12)¹²⁰
$ 20,000 = P (1 +0.005 )¹²⁰
$ 20,000 = P (1.005 )¹²⁰
$ 20,000 = 1.81·P
P = $ 20,000÷1.81
P = $ 11,049.72