How many moles of H2O are produced from 6.23g of C2H6 in the following reaction? 2C2H6+7O2 -> 4CO2+6H2O

Answers

Answer 1
Answer:

Answer:

0.623 moles of H₂O.

Explanation:

  • balanced equation: 2C₂H₆ + 7O₂ -> 4CO₂+ 6H₂O

Given:

  • 6.23g of C₂H₆
  • C₂H₆ molar mass is 30

solve for moles of C₂H₆

  • moles = mass/mr
  • moles = 6.23/30
  • moles = 0.2077

solve for moles of H₂O using molar ratio

  • 2C₂H₆ : 6H₂O
  • 2 : 6
  • 0.2077 : 0.623

Therefore, found that 0.623 moles of H₂O is produced.


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The chemical formula for potassium bromide is KBr.A chemist determined by measurements that 0.0250 moles of potassium bromide participate in a chemical reaction. Calculate the mass of potassium bromide that participates.

Round your answer to 3 significant digits.

Answers

A chemist determined by measurements that 0.0250 moles of potassium bromide participate in a chemical reaction is 0.002 moles

What are moles?

The moles are the smallest unit of an atom ion molecule or substance which is used to count the number which is taking part in a chemical reaction and is equal to 2.303 ×10²³ moles of that.

To calculate the participant in a chemical reaction number of moles is 0.0250 moles so the mass will be,

                number of moles = mass/ molar mass

substituting the value,

               0.0250 moles = mass / 119.002

               mass = 119.002  ×  0.0250 moles

                mass = 0.002 moles

Therefore, 0.002 moles determined by measurements that 0.0250 moles of potassium bromide participate in a chemical reaction.

Learn more about moles, here:

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My solution

39.0983+126.90447=166.00277

x/166.002277=.06

x=9.96g

Explanation:

How much energy (in J) is lost when a sample of iron with a mass of 26.4 g cools from 74.0 ∘C to 26.0 ∘C?

Answers

Answer:

Q=-526.6J

Explanation:

Hello,

In this case, for the computation of the energy loss when the cooling process is carried out, we use the shown below equation:

Q=mCp\Delta T

Whereas we need the mass, specific heat and change in temperature of iron within the process. Thus, the only value we need is the specific heat that is 0.444 J/(g°C), therefore, we compute the heat loss:

Q=26.4g*0.444(J)/(g\°C)*(26.0\°C-74.0\°C)\n \nQ=-526.6J

Negative sign points out the loss due to the cooling.

Regards.

Juan noticed that a door that sticks on hot days does not stick when it cools off at night. This is because the metal contracts as it cools. The reason for this is that, as the metal cools, the atoms:become smaller and take up less space .

slow down and move closer together.


merge together to form fewer atoms.


speed up and move further apart.

Answers

The atoms in the metal slow down and move closer together. So the answer is B.

Of the following, which element has the highest first ionization energy?Li
Cs
At
F​

Answers

There are free tutor on my website just got to freetutor.com
I think it’s Li but I don’t totally know

Is 3.5:Aqueous solutions of iron(III) bromide and ammonium carbonate react to form a precipitate. Answer the follwing
questions with regards to this reaction.
a) Write the molecular equation for this reaction by
Translating the two reactants into their chemical formulae.
Predict the products.
Label all the states.
Balance the reaction.

Answers

Answer:

2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)

Explanation:

Aqueous solutions of iron(III) bromide and ammonium carbonate react. This is a double displacement reaction that gives place to ammonium bromide and iron (III) carbonate. Iron (III) carbonate is insoluble so it precipitates. The corresponding molecular equation is:

2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)

A particular refrigerant cools by evaporating liquefied CCl 2F 2. How many kg of the liquid must be evaporated to freeze a tray of water to ice (at zero degrees C)? The tray contains 525 grams water. Molar heat of fusion of ice = 6.01 kJ/mol. Molar heat of vaporization of CCl 2F 2 = 17.4 kJ/mole

Answers

Answer : The mass of CCl_2F_2 evaporated must be, 1.217 kg

Explanation :

First we have to calculate the moles of water.

\text{Moles of water}=\frac{\text{Mass of water}}{\text{Molar mass of water}}

Molar mass of water = 18 g/mol

\text{Moles of water}=(525g)/(18g/mol)=29.17mol

Now we have to calculate the heat released.

Heat released = Moles of water × Molar heat of fusion of ice

Heat released = 29.17 mol × 6.01 kJ/mol

Heat released = 175.3 kJ

Now we have to calculate the moles of CCl_2F_2

Heat = Moles of CCl_2F_2 × Molar heat of vaporization of CCl_2F_2

175.3 kJ = Moles of CCl_2F_2 × 17.4 kJ/mol

Moles of CCl_2F_2 = 10.07 mol

Now we have to calculate the mass of CCl_2F_2

\text{Mass of }CCl_2F_2=\text{Moles of }CCl_2F_2* \text{Molar mass of }CCl_2F_2

Molar mass of CCl_2F_2 = 120.9 g/mol

\text{Mass of }CCl_2F_2=10.07mol* 120.9g/mol=1217.463g=1.217kg

Thus, the mass of CCl_2F_2 evaporated must be, 1.217 kg