A car depreciate $2000 each year it was owned and driven. What type of depreciation is this?

Answers

Answer 1
Answer:

Answer:

Straight-line depreciation

Step-by-step explanation:

APE X

Answer 2
Answer: This would be an exponential decay model.

Related Questions

What 6/8 turned into a decimal
Help please !Write a rule to describe the function shown.x y−3 9−1 30 03 −9y = 3xy = −3xy equals start fraction one over three end fraction xy equals negative start fraction one over three end fraction xQuestion 2 (Multiple Choice Worth 5 points)(04.03 MC)What is the slope of the line joining (10, 9) and (40, 3)?−5−4negative start fraction one over five end fractionstart fraction one over five end fraction
Maya earns $6.36 for each hour of work. She worked 7.5 hours yesterday. Find how much she earned yesterday.
Solve the equation 4n-7=-23
For two weeks, Mario recorded the color of the traffic light at the intersection of Main Street and North Avenue as his bus approached the intersection. He created this frequency table. What data did he collect to create this frequency table? A. green, red, red, red, red, red, green, red, red, yellow B. red, red, red, yellow, red, red, green, red, red, yellow C.red, red, red, red, red, red, green, red, red, yellow D.red, red, green, red, red, red, green, red, red, yellow frequency table: Red: 7 Green: 2 Yellow: 1 Total: 10

Among the 10 most popular sports, men include competition-type sports - pool and billiards, basketball, and softball - whereas women include aerobics, running, hiking, and calisthenics. However, the top recreational activity for men was still the relaxing sport of fishing, with 41% of those surveyed indicating that they had fished during the year. Suppose 180 randomly selected men are asked whether they had fished in the past year. Suppose 180 randomly selected men are asked whether they has fished in the past year.a. What is the probability that fewer than 50 had fished?
b. What is the probability that between 50 and 75 (inclusive) had fished?
c. If the 180 men selected for the interview were selected by the marketing department of a sporting-goods company based on information obtained from their mailing lists, what would you conclude about the reliability of their survey results?

Answers

Answer:

(a) The probability that fewer than 50 had fished is 0.0002.

(b) The probability that between 50 and 75 (inclusive) had fished is 0.6026.

(c) The survey results are not reliable.

Step-by-step explanation:

Let X = number of men who had fished during the year.

The probability of the random variable X is, p = 0.41.

A random sample of n = 180 men are selected.

The random variable X follows a Binomial distribution with parameters n = 180 and p = 0.41.

A Normal approximation to Binomial is applied when the following conditions are met,

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check:

np=180*0.41=73.8>10\nn(1-p)=180* (1-0.41)=63.72>10

Thus, the distribution of x can be approximated by a Normal distribution with:

Mean = np=180*0.41=73.8

Standard deviation = √(np(1-p))=√(180*0.41*(1-0.41))=6.599

(a)

Compute the probability that fewer than 50 had fished as follows:

P(X<50)=P((X-\mu)/(\sigma)>(50-73.8)/(6.599))\n=P(Z<-3.61)\n=1-P(Z<3.61)\n=1-0.9998\n=0.0002

Thus, the probability that fewer than 50 had fished is 0.0002.

(b)

Compute the probability that between 50 and 75 (inclusive) had fished as follows:

P(50\leq X\leq 75)=P(49.5<X<75.5)\n=P((49.5-73.8)/(6.599)<(X-\mu)/(\sigma)<(75.5-73.8)/(6.599))\n=P(-3.68<Z<0.26)\n=P(Z<0.26)-P(Z<-3.68)\n=0.6026-0\n=0.6026

Thus, the probability that between 50 and 75 (inclusive) had fished is 0.6026.

(c)

If the sample of 810 men are selected from mailing list then it is highly probable that the sample is not a representative of the true population, i.e. sports men.

Because the people interested in sports are less likely to be interested in fishing.

Thus, it could be concluded that the survey results are not reliable.

If ST = 3, TU = 1, and SU= 9, what is ST?

Answers

Answer:

ST = 3

Step-by-step explanation:

it tells you that ST is 3

Select all that apply.Which of the following expressions could you use to estimate 47% of 89?


1/2 · 90
0.5 · 90
0.47 · 89
90/2

Answers

Given: 
47% of 89

Exact solution is : 0.47 * 89 = 41.83

Estimates: you round the number to the nearest tens.
47% can be 50% ; 89 can be 90

0.50 * 90 = 45

50% is the same as 1/2
1/2 * 90 = 45

90/2 is also applicable to estimate for the above figure. 90/2 = 45

Answer:

The first and second one

Step-by-step explanation:

Wha t is the world largest punctuation mark

Answers


That's the period at the end of the sentence written in
million-point font across the Sahara.

(It's an ad placed there by McDonald's to attract the
18-30 alien demographic.)

What is 480 divided by 60

Answers

The given number 480 divided by 60 equals 8.

The division process involves successive subtraction of the divisor from the dividend until the remainder becomes less than the divisor.

To 480 divided by 60, to perform this division by dividing 480 by 60, resulting in a quotient of 8.

Division is an arithmetic operation that separates a number into equal groups, in this case, 480 is divided into 60 groups of equal size, and each group contains 8 items.

Dividing 480 by 60 can also be represented as 480 ÷ 60 = 8.

Hence, divide the given number 480 by 60 is equal to 8.

Learn more about Divided here:

brainly.com/question/15381501

#SPJ6

Answer:

8

Step-by-step explanation:

Verify csc^4 - cot^4= 2cot^2 +1

Answers

  you can factor the left side of the equation to 

(csc^2 + cot^2)(csc^2 - cot^2) 

then, since cot^2 + 1 = csc^2, you can replace the csc^2 in the left parentheses with cot^2 + 1, and the cot^2 in the right parentheses with csc^2 - 1 (which equals cot^2) 

then, youll end up with 

(cot^2 + 1 - cot^2)(csc^2 + csc^2 - 1) 

combine like terms, and the left parentheses becomes 1 (cot^2 - cot^2 = 0), and the right parentheses becomes 2csc^2 - 1. 

1(2csc^2 - 1) = 2csc^2 - 1