Given that the molar mass of naoh is 40.00 g/mol, what mass of naoh is needed to make 2.500 l of a 2.000 m naoh solution? use molarity equals startfraction moles of solute over liters of solution endfraction.. 0.1250 g 5.000 g 32.00 g 200.0 g

Answers

Answer 1
Answer:

The mass of Sodium hydroxide which is needed to make 2.500 L of a 2.000 M NaOH solution is 200 grams.

How do we calculate mass from moles?

Mass of any substance will be calculated by using their moles as:

n = W/M, where

W = required mass

M = molar mass

Given that, molarity of NaOH = 2M

Volume of NaOH solution = 2.5L

Moles of NaOH will be calculated by using the below equation as:

M = n/V

n = (2)(2.5) = 5 moles

Now we calculate the mass of NaOH of 5 moles as:

W = (5mol)(40g/mol) = 200g

Hence option (4) is correct.

To know more about moles, visit the below link:

brainly.com/question/15303663

Answer 2
Answer:

Answer:

d

Explanation:


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Answers

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The bond between F and Cl would be:A) nonpolar covalent
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C) ionic
D) metallic

Answers

 It would be a polar covalent bond. The two atoms have different electronegativities, and I'm pretty sure they are sufficiently different to classify the bond as polar.
i belive the answer is C) ionic

Please help1. What is the correct formula for magnesium cyanide?
A.MgCy
B.MnCN
C.Mg(CN)2
D.MgCN

2. What is the correct formula for dinitrogen pentoxide?
A.2NO5
B.N2O5
C.DnPo
D.NO2.5

3. What is the correct formula for titanium (III) perchlorate?
A.TiPc
B.Ti3(ClO)4
C.Ti3ClO4
D.Ti(ClO4)3

4. What is the correct formula for nickel (III) nitrate?
A.Ni(NO3)3
B.Ni3NO3
C.Ni3N
D.NiN3

5. What is the correct name for Co(C2H3O2)3
A.carbon oxide hydride
B.cobalt acetate
C.cobalt triacetate
D.cobalt (III) acetate

6. What is the correct name for NiSO4?
A.nickel (I) sulfide
B.nickel (II) sulfate
C.nickel sulfide tetraoxide
D.nickel sulfate

7. What is the correct name for N2F4?
A.dinitrogen fluoride (IIII)
B.nitrogen (II) fluoride
C.dinitrogen tetrafluoride
D.nitrofluorine

8. What is the correct name for PCl5?
A.phosphorus pentachloride
B.phosphorus (V) chloride
C.chlorophosphorus (V)
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9. Which type of bond (ionic, covalent or metallic) would Sr and Sc make?
A.ionic
B.covalent
C.metallic
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10. Which type of bond (ionic, covalent or metallic) would Ba and Br make?
A.ionic
B.covalent
C.metallic
D.none of the above

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A.ionic
B.covalent
C.metallic
D.none of the above

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A.ionic
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Answers

1. C : Mg(CN)2
2. B : N2O5
3. D : Ti(ClO4)3
4. A : Ni(NO3)3
5. D : Cobalt (III) Acetate
6. B : Nickel(II) sulfate
7. C : Dinitrogen Tetrafluoride
8. A : Phosphorus pentachloride
9. C : Metallic (<!> This is the only one I'm not 100% sure of)
10. A : Ionic
11. C : Metallic
12. B : Covalent
#1 : C. Mg(CN)2

#2: B. N205

#3: D. Ti(CIO4)3

#4: A. But you maked a little mistake. It's Ni(NO3)2

#5: D. Cobalt (III) Acetate.

#6: B.

#7: C.

# 8: A.

# 9: C.

# 10: A.

# 11: C.

# 12: B.

What is the difference in the beginning between primary succession and secondary succession?a. secondary succession has water
b. secondary succession has soil
c. primary succession has soil
d. primary succession has water

Answers

Option B. secondary succession has soil


At sea level, where the pressure was 104 kPa and temperature 21.1 ºC, a certain mass of air occupies 2.0 m3 . To what volume will the region expand when it has risen to altitude where the pressure and temperature are (a) 52 kPa, -5.0 ºC ( True or False )

Answers

Answer:

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

Explanation:

The combined gas equation is,

(P_1V_1)/(T_1)=(P_2V_2)/(T_2)

where,

P_1 = initial pressure of gas = 104 kPa

P_2 = final pressure of gas = 52 kPa

V_1 = initial volume of gas = 2.0m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 21.1^oC=273+21.1=294.1K

T_2 = final temperature of gas = -5.0^oC=273+(-5.0)=268 K

Now put all the given values in the above equation, we get:

(104 kPa* 2.0m^3)/(294.1 K)=(52 kPa* V_2)/(268 K)

V_2=3.64 m^3

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.