The bond between Br atoms in a Br2 molecule is(1) ionic and is formed by the sharing of two valence electrons
(2) ionic and is formed by the transfer of two valence electrons
(3) covalent and is formed by the sharing of two valence electrons
(4) covalent and is formed by the transfer of two valence electrons

Answers

Answer 1
Answer: The bond between Br atoms in an Br2 molecule is concealment and is formed by sharing of two valence electrons.
Answer 2
Answer:

Final answer:

The bond between Br atoms in a Br2 molecule is covalent and is formed by the sharing of two valence electrons.

Explanation:

The bond between Br atoms in a Br2 molecule is covalent and is formed by the sharing of two valence electrons.

In a covalent bond, atoms share electrons to complete their outer electron shell. In the case of a Br2 molecule, each Br atom has 7 valence electrons and needs 1 more electron to achieve a stable octet arrangement, so they share one pair of electrons to achieve this.

The bond between Br atoms in a Br2 molecule is covalent and is formed by the sharing of two valence electrons.

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What is the name for the following compound ​

Answers

Answer: Phosphorus trioxide

Explanation: it is a chemical compound with molecular formula of P4O6. The suggested name for it is tetraphosphorus hexoxide.

1. Plants use energy from sunlight, water, and carbon dioxide to produce 10 pointssugar. Which structure is found only in plant cells and helps plants capture
energy from sunlight?
A. Vacuole
B. Nucleus
C. Chloroplast
D. Cell Membrane

Answers

The answer is c chloroplast

Answer:

Chloroplast

Explanation:

Which of these is a typical property of a substance that is composed of atoms that are held together by covalent bonds?a. It conducts electricity when in solid form.
b. It conducts electricity when in molten form.
c.It conducts electricity when it is dissolved in water.
d.It does not conduct electricity in any form.

Answers

electricity is conducted by free electrons or ions, such as delocalised electrons in metallic compounds or free moving cations and anions in aqueous solutions of ionic compounds.

atoms held together by covalent bonds do not contain free moving electrons or ions, so they do not conduct electricity in any state.

Answer:

D) It does not conduct electricity in any form.

Explanation:

Edge 2020 Trust

Carbon-11 is used in medical imaging. The half-life of this radioisotope is 20.4 min. What percentage of a sample remains after 60.0 min?34.013.05.2871.22.94

Answers

Answer:

Percentage of a sample remains after 60.0 min is 13.03%.

Explanation:

  • It is known that the decay of isotopes of C-11 obeys first order kinetics.
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
  • Half-life time (t1/2) in first order reaction = 0.693/k, where k is the rate constant.

k = 0.693/(t1/2) = 0.693/(20.4 min) = 0.03397 min⁻¹.

  • The integrated law for first order reaction is:

kt = ln[A₀]/[A],

where, k is the rate constant (k = 0.03397 min⁻¹).

t is the time of the reaction (t = 60.0 min).

[A₀] is the initial concentration of C-11 ([A₀] = 100.0 %).

[A] is the remaining concentration of C-11 ([A] = ???%).

∵ kt = ln[A₀]/[A]

∴ (0.03397 min⁻¹)(60.0 min) = ln(100%)/[A]

∴ 2.038 = ln(100%)/[A]

  • Taking e for both sides:

∴ 7.677 = (100%)/[A]

∴ [A] = (100%)/(7.677) = 13.03%.

So, percentage of a sample remains after 60.0 min is 13.03%.

Final answer:

The half-life of Carbon-11 is 20.4 minutes, meaning the quantity reduces by half every 20.4 minutes. So, after approximately 60.0 minutes (roughly three half-lives), approximately 12.5% of the original sample would remain.

Explanation:

Carbon-11 is a radioisotope that's widely used in medical imaging due to its radioactive properties. It has a half-life of 20.4 minutes, which means that the quantity of Carbon-11 reduces to half in every 20.4 minutes.

If we denote one half-life as t, after three half-lives (60.0 min or 3t), the ratio of the remaining sample of Carbon-11 would be 1/2 * 1/2 * 1/2 = 1/8. In other words, approximately 12.5% of the original sample would be remaining. This percentage changes a bit due to the fact that 20.4 min is slightly less than 22.2 min (which would be the exact 3 half lives).

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A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate. 2KClO3 mc019-1.jpg 2KCI + 3O2 What is the percent yield of oxygen in this chemical reaction?

Answers

The balanced equation that describes the reaction of heatinf potassium chlorate to produce potassium chloride and oxygen is expressed 2KClO3 = 2KCI + 3O2. For a 400 g potassium chloride, using stoichiometry, the mass oxygen produced is 156.67 grams oxygen. The actual product weighed 115.0 grams. Yield is equal to 115/156.67 or 73.74%

Answer:

The percent yield of oxygen in this chemical reaction is 73.71 %.

Explanation:

Experimental yield of oxygen gas = 115.0 g

Theoretical yield:

2KClO_3rightarrow 2KCI + 3O_2

Mass of potassium chlorate = 400.0 g

Moles of potassium chlorate = (400 g)/(122.5 g/mol)=3.2653 mol

According to reaction, 2 moles of potassium chlorate gives 3 moles of oxygen gas.

Then 3.2653 mol of potassium chlorate will give:

(3)/(2)* 3.2653 mol=4.89795 mol

Mass of oxygen gas :

32 g/mol* 4.89795 mol=156.73 g

Percentage yield:

\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100

\%=(115.0 g)/(156.73 g)* 100=73.71\%

The percent yield of oxygen in this chemical reaction is 73.71 %.

What volume do 4.96 moles of O2 occupy at STP?

Answers

Answer: Step 1: List the known quantities and plan the problem. Known. 4.96 moles O2; 1 mol = 22.4

Explanation: I hope that helped.