Which substance can not be decomposed by a chemical change?(1) AlCl3 (3) HI
(2) H2O (4) Cu

Answer:

To balance the chemical equation, I'll assume the reaction is carried out under standard conditions. Here's the balanced equation:

2 N2 (g) + 5 O2 (g) → 4 H2O (l) + 4 NO3- (aq)

Explanation:

To balance the number of nitrogen (N) atoms, we need 2 nitrogen molecules (N2) on the left side. This gives us a total of 4 nitrogen atoms on the left side.

To balance the number of oxygen (O) atoms, we need 5 oxygen molecules (O2) on the left side. This gives us a total of 10 oxygen atoms on the left side.

On the right side, we need 4 water molecules (H2O) to balance the hydrogen (H) atoms. This gives us a total of 8 hydrogen atoms on the right side.

Finally, to balance the oxygen (O) atoms on the right side, we need 4 nitrate ions (NO3-) since each nitrate ion contains one nitrogen and three oxygen atoms. This gives us a total of 12 oxygen atoms on the right side.

Now the equation is balanced with 4 nitrogen atoms, 10 oxygen atoms, 8 hydrogen atoms, and 4 nitrate ions on both sides.

Answer:

See explanation

Explanation:

The question is incomplete. However, base on the given information, one likely question could be that, we calculate the the volume of the nitrogen gas after heating it.

So, we have that:

Initial Volume, V1 = 200mL

Initial Temperature, T1 = 24k

Final Temperature, T2 = 47k

To solve the final volume of the gas, we apply the following ideal gas law equation

V1 * T1 = V2 * T2

Substitute values for V1, T1 and T2

200mL * 24K = V2 * 47K

200mL * 24 = V2 * 47

4800mL = 47V2

Solve for V2

V2 = 4800/47

V2 = 102.13 mL ------- Approximated

Hence, the volume of nitrogen gas after heating is 102.13mL

Answer: Compounds having the same empirical formula are:

Explanation:

Empirical formula tells us about the proportion of the elements present in the compound but it do not tells us about the actual numbers of atoms of the elements present in the compound.

In given empirical formula that is proportion of  C:H:O = 1:2:1

In the proportion of C:H:O =2:4:2= 1:2:1

In the proportion of C:H:O =3:6:3= 1:2:1

In the proportion of C:H:O =1:2:2= 1:2:2

In the proportion of C:H:O =5:10:5= 1:2:1

In the proportion of C:H:O =6:12:6= 1:2:1

Compounds having the given empirical formula are:

The chemical compounds that have the empirical formula are:

A.C2H4O2

B.C3H6O3

D.C5H10O5

E.C6H12O6

An empirical formula can be defined as a formula that gives the smallest and simplest whole number ratio of the atoms of a chemical element found in a chemical compound.

The simplest whole number ratio of the atoms of   is:

= 1:2:1

• 1 atom of carbon.

• 2 atoms of hydrogen molecule.

• 1 atom of oxygen.

For :

= 2:4:2 = 1:2:1

For :

= 3:6:3 = 1:2:1.

For :

= 1:2:2 = 1:1:1  (Incorrect)

For :

= 5:10:5 = 1:2:1

For :

= 6:12:6 = 1:2:1

Note:

• C is the chemical symbol of carbon.

• H is the chemical symbol of hydrogen.

• O is the chemical symbol of oxygen.

Read more: brainly.com/question/21280037