What fraction of 1 liter is 1 milliliter?

Answers

Answer 1
Answer: 15 x 5 = 75
35/75 + 30/75 = 65/75
(65/75) / 5 = 13/15

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Elimination method-2x+y=-82x+4y=18

Can someone answer please? i will give brain-list

Answers

Answer:

x=5

Step-by-step explanation:

9x=4x+25

-4x  -4x

5x=25

x=5

What is the answer to this problem and how do u solve it. -8 - 9 =

Answers

Answer:

not possible

Step-by-step explanation:

Answer:

-17

Step-by-step explanation:

(I originally posted this as a comment because Brainly was not allowing me to answer).

-8 is a negative number, which means many operations don't work the same on it. Subtracting a positive number from a negative number will give you the same result as adding the two positive numbers (in this case, 8 + 9), though the answer will also be negative. Hope this helps!

$2.50 per square foot. how much is that per square yard?

Answers

1 yard is 3ft, so just multiply 2.5 with 3 and that gives u 7.5.
Hello,

1yd=3ft ==>(1yd)²=(3ft)²=9ft² cost $2.5*9=$22.5

Franks electric bill for the month of March was $85.78. The electric company charged a flat monthly fee of $20.00 for service plus $0.14 per kilowatt-hour of electricity used. Approximately how many kilowatt-hours of electricity did frank use in March?

Answers

The power utilised by frank in the month of march is 470 kilowatts - per hour.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that Franks's electric bill for the month of March was $85.78. The electric company charged a flat monthly fee of $20.00 for service plus $0.14 per kilowatt-hour of electricity used.

The equation will be written as,

B = 20 + 0.14K

85.78 = 20 + 0.14k

k = ( 80.78 - 20 ) / 0.14

K = 65.78 / 0.14

K = 470 Kilowatt-hour

Therefore, the power utilised by frank in the month of march is 470 kilowatts - per hour.

To know more about an expression follow

brainly.com/question/17489069

#SPJ5

Answer:

I got 469.8 kilowatt-hours. I got this by taking the total of Frank's bill, which was $85.78, and subtracting the flat monthly fee of $20.00. I did this because I need to find out the number of kilowatt-hours Frank used. Then, I divided $65.78 by $0.14 since that is the price per kilowatt-hour and got about 469.8 kilowatt-hours used by Frank.

jens motorboat travels at a speed of 15mph in still water, the river flows at a speed of 2pmh, how long will it take jen to travel 20mi upstream? 20mi downstream?

Answers

The speed of the motorboat travelling up stream will be 13mph, therefore it will take 20/13 hours to travel 20 miles upstream. This is about 1 and a half hours. The speed of the motorboat travelling downstream will be 17mph, therefore it will take 20/17 hours to travel 20 miles downstream. This is about 1 hour 10 minutes.

What are two solution to x<8

Answers

Answer:

1 and 4

Step-by-step explanation:

All you need is 2 numbers that are less than 8