Name the compound of AuO

Answers

Answer 1

Answer: If it existed it would be gold(II) oxide. The stable gold oxide is gold(III) oxide Au2O3

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Aluminum chloride and cesium undergo a single replacement reaction. What is the correct chemical equation for this reaction?a. AlCl3 + 3Cs yields No Reactionb. AlCl2 + 2Cs yields 2CsCl + Alc. AlCl3 + 3Cs yields 3CsCl + Ald. 2AlCl3 + 6Cs yields 2AlCs3 + 3Cl2
Scientists think the earth is approximately _____ years old.2 billion3 billion4 ½ billion6 ½ billion

What is the name of the flower part that elevates the stigma

Answers

The style raises the stigma above the base of the flower and separates it from the ovary.

Calculate the density of argon gas at a pressure of 753 mmHg and a temperature of 35 °C

Answers

The density of Argon gas at a pressure of 753 mmHg and a temperature of 35 °C is equal to 1.59 g/L.

What is the ideal gas equation?

The state of a quantity of gas is calculated by its pressure, volume, and temperature. The ideal gas law can be explained as the product of the volume and pressure of gas is equal to the multiplication of the universal gas constant and absolute temperature.

The mathematical equation for an ideal gas can be written as follows:

PV = nRT

PV =(m/M) RT

PM/RT = m/V

d = PM/RT

Where n is the moles of gas, T is the temperature of the gas, V is the volume of the gas, and R is the gas constant.

Given, the temperature of argon gas, T = 35 °C = 35 +273 = 308 K

The pressure of the argon gas, P = 753 mmHg = 1.01 atm

The molar mass of the Argon gas, M = 40 g/mol

Substitute V, R, P, and T in the ideal gas equation, we get:

The density of Argon gas, d = PM/RT

d= 1.01 ×40/(0.082 × 308)

d = 1.59 g/L

Therefore, the density of Ar gas is 1.59 g/L.

Learn more about ideal gas equation, here:

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PV=nRT
PV= (m/M)RT
PM=(m/v)RT
PM =dRT
d= (PM) ÷(RT)

substitute the the given data to the above equation. d-density, p-pressure, M- molar mass of argon gas, T- temperature. and R is a constant. make sure to substitute its value too.. :)

The value of the equilibrium constant for the combination of nitrogen and oxygen to make NO is 2 x 10-9. What does this tell you about the concentrations of materials in the equilibrium mixture?

Answers

Answer: The reaction must proceed in the reverse direction.

Explanation:

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

The expression of $K_p$ for above equation follows:

$K_p=((p_(NO))^2)/(p_(N_2)* p_(O_2))$

We are given:

$K_p=2* 10^(-9)$

There are 3 conditions:

When $K_(p)>1$ ; the reaction is product favored.

When $K_(p)<1$ ; the reaction is reactant favored.

When $K_(p)=1$ ; the reaction is in equilibrium.

As, $K_p<1$ , the reaction will be favoring reactant side or the reaction must proceed in the reverse direction.

Hence, the reaction must proceed in the reverse direction.

Select the three types of cells in the blood.blue
red
black
white
platelets
round

Answers

Red white and plantelets hope it helps =)

Three selected types of cells in blood are Red White Round

Which role of water is significant for most living things in a biological system?a. It prevents many life processes from occurring.b. It slows down the transportation of nutrients.c. It provides temperature regulation.d. It does not freeze in cells at very cold temperatures.

Answers

I am pretty sure the correct answer is C. Water has large heat capacity meaning it can absorb a lot of energy before changing temperature. That helps the body regulate heat since it can be exposed to different environments and experience small temperature changes.

I hope this helps. Let me know if anything is unclear.

Answer:

The answer is C!

Explanation:

I took the test ;)

Consider the balanced chemical equation for the combustion of methane (CH4).mc026-1.jpg

Given that the molar mass of CO2 is 44.01 g/mol, how many liters of oxygen is required at STP to produce 88.0 g of CO2 from this reaction?
44.8 L
45.00 L
89.55 L
89.6 L