Please help me!!!! So confused

Answers

Answer 1

Answer:
Question:

The area of the kite is 48 cm². What are the lengths of the diagonals PR and QS?

________

Solution:

You can split the kite into two isosceles triangles:   PSR and PQR.

Assume that both diagonals intersect each other at the point O.

•   Area of the triangle PSR:

   m(PR) · m(OS)
A₁ = ————————
   2

   (x + x) · x
A₁ = ——————
        2

   2x · x
A₁ = ————
      2

A₁ = x² (i)

•   Area of the triangle PQR:

      m(PR) · m(PQ)
A₂ = ————————
         2

       (x + x) · 2x
A₂ = ——————
      2

   2x · 2x
A₂ = ————
   2

   4x²
A₂ = ———
   2

A₂ = 2x² (ii)

So the total area of the kite is

A = A₁ + A₂ = 48

Then,

x² + 2x² = 48

3x² = 48

      48
x² = ———
      3

x² = 16

x = √16

x = 4 cm

•   Length of the diagonal PR:

m(PR) = x + x

m(PR) = 2x

m(PR) = 2 · 4

m(PR) = 8 cm

•   Length of the diagonal SQ:

m(SQ) = x + 2x

m(SQ) = 3x

m(SQ) = 3 · 4

m(SQ) = 12 cm

I hope this helps. =)

Tags: polygon area triangle plane geometry

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What percentage of the shape is purple

Answers

the answer is going to be: 75%

Answer:

75% of the circle is purple

Step-by-step explanation:

this circle is split into 4ths, meaning each piece is equivalent to 25%. And since 3 pieces are purple, you multiply 25x3 to get 75. Leaving 25% of the circle white.

A pencil at a stationery store costs $1, and a pen costs $1.50. Shawn spent $12 at the store. He bought a total of 9 items. Which system of equations can be used to find the number of pencils (x) and pens (y) he bought?1.5x + y = 12
x = 9y

x + 1.5y = 12
x + y = 9

x + 9y = 12
x = 1.5y

9x + y = 12
x = 1.5y

Answers

The system of equations that represents the given statements is

x + 1.5y = 12

x + y = 9

Where x is the number of pencils and y is the number of pens that Shawn bought.

How to write an equation for a statement?

To write an equation:

Observe the variableterms from the given statement
Add/subtract required terms according to the word's 'total or difference' given in the statements
Multiply/divide required terms according to the words 'more or less given the statements
Equate with the respective values related to the variable term.

Calculation:

Given that,

A pencil at a stationery store costs - $1

and A pen costs - $1.50

Shawn spent $12 at the store. He bought a total of 9 items.

So,

Consider number of pencil = x and number of pens = y

Since he bought a total of 9 items, we can add the number of pencils and pens and equate the sum with 9

I.e., x + y = 9 ...(i)

We have cost for a single pencil and a single pen

So, to get the cost for the total number of pencils and pens that he bought, multiply the cost of a single one by the number of pencils and pens. I.e.,

1 × x and 1.50 × y

Since it is given that he spent $12 for both pencils and pens, we can write

x + 1.5 y = 12 ...(ii)

Thus, from equations (i) and (ii), the system we can write

x + 1.5 y = 12

x + y = 9

So, option 2 is the correctset of equations for the given system.

Learn more about writing equations from words here:

brainly.com/question/11567221

#SPJ2

I would go with the second answer

Write in decimal form fourteen and eighty-Four hundredths

Answers

Hundredths is to numbers to the right of the decimal:

fourteen = 14
eighty-four hundredths = 0.84

All together:

14.84

Writing in decimal form fourteen and eighty-four hundredths you get 14.84

Formula of trigonometric ratios

Answers

$\huge \boxed{\mathfrak{Question} \downarrow}$

Formula for trignometric ratios.

$\huge \boxed{\mathfrak{Answer} \downarrow}$

The trignometric ratios are $\downarrow$ $\downarrow$

$\begin{gathered}\begin{gathered}\begin{array}{||c|c|c||} \n \rm sin \: A & (\sf\:Opposite\: side\: of\: angle\: A )/(\sf\:Hypotenuse \: ) & (\sf\:BC)/(\sf\:AC) \n \n \rm cos \: A & ( \sf\: Adjacent \:side \:of\: angle \:A )/(\sf\: Hypotenuse) & (\sf\: AB)/( \sf\: AC) \n \n \rm tan A & (\sf\: Opposite \:side \:of \:angle\: A)/( \sf\: Adjacent \:side \:of \:angle \:A ) & (\sf\:BC)/( \sf\: AB)\n \n \rm cosec A & (\sf\: Hypotenuse)/(\sf\: Opposite\: side \:of\: angle\: A)& (\sf\:AC)/( \sf\:BC ) \n \n \rm sec A & (\sf\: Hypotenuse)/( \sf\: Adjacent \:side\: of\: angle \:A)& (\sf\:AC)/(\sf\:AB)\n \n \rm cot A & (\sf\: Adjacent \:side\: of \:angle \:A)/(\sf\: Opposite\: side \:of\: angle\: A) & (\sf\:AB)/( \sf\: BC) \end{array}\end{gathered}\end{gathered} \n \n - \bf \: Lucazz \: (brainly.com)$