How Do I Find The Domain & Range Of
y=2x-4 ?

Answers

Answer 1
Answer:

Both the domain and range of the function is in range -

( - ∞ , + ∞ )

We have the following function -

y = f(x) = 2x - 4

We have to identify its Domain and Range.

What do you mean by domain and range of a function?

For any function y = f(x), Domain is the set of all possible values of y that exists for different values of x. Range is the set of all values of x for which y exists.

Consider the equation given -

y = 2x - 4

If we compare it with the general equation of line -

y = mx + c

We get -

m = 2 and c = - 4

Now this graph of the equation y = mx + c represents a straight line.

Hence, both the domain and range of the function are-

( - ∞ , + ∞ )

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Answer 2
Answer: The domain is how far left and right it goes on a graph, and the range is how far up and down it goes on a graph. Because this equation is linear (if you graphed it, it would be in a straight line), both the domain and range are infinity, because it keeps going up and to the right, the larger X gets, and smaller and to the left, the more negative X gets.

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If grades in QMET are normally distributed with a mean of 8 and a standard deviation of 19, what proportion of students will score 86 or lower?

Answers

Answer:

c and b

Step-by-step explanation:

If f(x) is 4x-3 what is (f^-1of) (10)

Answers

f(x)=4x-3\n y=4x-3\n 4x=y+3\n x=(1)/(4)y+(3)/(4)\n f^(-1)(x)=(1)/(4)x+(3)/(4)\n\n f^(-1) \circ f=(1)/(4)(4x-3)+(3)/(4)\n f^(-1) \circ f=(4x)/(4)-(3)/(4)+(3)/(4)\n f^(-1) \circ f=x
f(x)=4x-3\ \ \ \ and\ \ \ D_f=R\n\ny=4x-3\ \ \ \Rightarrow\ \ \ y+3=4x\ /:4\ \ \ \Rightarrow\ \ \ (1)/(4)y+ (3)/(4)=x\n\nf^(-1)(x)= (1)/(4)x+ (3)/(4) \ \ \ \ and\ \ \ \ D_(f^(-1))=R\n\n (f^(-1)\circ f) (10)=f^(-1)\bigg( f (10)\bigg)=\n=f^(-1)\bigg( 4\cdot10-3\bigg)=f^(-1)(37)=(1)/(4)\cdot37+ (3)/(4) =(37)/(4) +(3)/(4) = (40)/(4) =10

P(A) = 0.44 What are the odds for A?

Answers

P(A)=0.44=(44)/(100)=(11)/(25)\n\n11\ odds\ on\ 25
0,44 = 44 / 100

44 odds on 100

Find a rational number and an irrational number that are between 5.2 and 5.5. Include the decimal approximation of the irrational number to the nearest hundredth.

Answers

A rational number is a number that can be expressed in a ratio between two numbers while an irrational number cannot. An example of rational between 5.2 and 5.5 is 5.3. An example of an irrational number between 5.2 and 5.5 is √28 which approximately equal to 5.29

A math teacher’s midterm is worth 200 points. The mean of the test is 143 and the standard deviation is 15.7. If the scores have a bell shaped distribution, what percentage of the scores are between 111.6 and 174.4?A. About 99.7%
B. About 68%
C. About 62.8%
D. About 95%

Answers

If the scores have a bell shaped distribution, percentage of the scores are between 111.6 and 174.4 would be D. About 95%

How to find the percentage ?

The given values 111.6 and 174.4 are one standard deviation away from the mean

= 143 - 15.7 = 127.3

and

143 + 15.7 = 158.7

So 111.6 and 174.4 are even farther away from the mean.

In a bell-shaped distribution (normal distribution), about 68% of the data falls within one standard deviation of the mean, about 95% falls within two standard deviations, and about 99.7% falls within three standard deviations.

Since 111.6 and 174.4 are more than one standard deviation but less than two standard deviations from the mean, the percentage of scores between 111.6 and 174.4 would be about 95%.

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The answer is D: about 95%.

There are 6 rotten mangoes and 24 good mangoes in a bag. What fraction of the mangoes is rotten?

Answers

\sf \bf {\boxed {\mathbb {Given:}}}

Total number of rotten mangoes in the bag = 6

Total number of good mangoes in the bag = 24

\sf \bf {\boxed {\mathbb {To\:find:}}}

Fraction of the rotten mangoes to the total mangoes.

\sf \bf {\boxed {\mathbb {Solution:}}}

\implies {\blue {\boxed {\boxed {\purple {\sf { (1)/(5) }}}}}}

\sf \bf {\boxed {\mathbb {Step-by-step\:explanation :}}}

Total number of mangoes in the bag = Total number of rotten mangoes + Total number of good mangoes

\:6 + 24

\:30

Now,

Fraction = (Total \: \:   number  \:  \: of \:  \:  rotten \:  \:  mangoes)/(Total  \:  \: number  \:  \: of \:  \:   mangoes)

\:  (6)/(30)

\:  (1)/(5)

Therefore, the fraction of the rotten mangoes to the total mangoes is \sf\pink{(1)/(5)}.

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

Answer:

6/24

Step-by-step explanation:

It is 1/4 in simplest form