When I'm with my factor 5 , my product is 20 . what number am I ? explain ..
plzz helpp !

Answers

Answer 1

Answer: The answer is 4.

The reason is that 5 times 4 is 20.

Answer 2

Answer: Your answer Would be four because 4 times 5 is 20

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Many of the obstacles an immigrant might need to overcome would include: (Select all that apply)leaving friends leaving family member sembracing a new religion learning a new language marrying a stranger finding the way around a new city

Answers

Well, it really depends on the person. But generally, I'd say that the obstacles an immigrant might need to overcome would include leaving friends, leaving family members, learning a new language, and perhaps the last option, but I'm not sure about that one.
I don't think they would be forced to embrace a new religion or marry somebody, but those things may happen as well.

Immigration is the transfer of individuals from one country to another. This is different from emigration in which the transfer of the locality just takes place. In this case, leaving family and friends will take place as well as finding a way around a new city will also happen. It is also possible of learning a new language. It is not necessary to find a new religion or a stranger to marry.

Can anyone answer this PLSSSSSSS I NEED IT!!!

Answers

Answer:

Step-by-step explanation:

Find the absolute value of each rational number |3.7|

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$|a|=a \hbox{ if } a \geq 0 \n|a|=-a \hbox{ if } a \leq 0 \n \n|3.7|=3.7$

The correct answer is:

3.7

Explanation:

Absolute value is the distance a number is from 0. The number 3.7 is 3.7 units away from 0 on a number line; this means the absolute value is 3.7.

What property is illustrated by each statement? 7+(4+4)=(7+4)+4A. Inverse property of addition B. Associative property of addition C. Commutative property of addition

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B
This property dictates that you can add regardless of how the numbers are grouped.

Find the domain and range of function y = √(−x^{2} −6x+2)

Answers

$y=√(-x^2-6x+2)\n\nD:-x^2-6x+2\geq0\n\na=-1;\ b=-6;\ c=2\n\n\Delta=b^2-4ac;\ iff\ \Delta \geq0\ then\ x_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\n\n\Delta=(-6)^2-4\cdot(-1)\cdot2=36+8=44;\ \sqrt\Delta=√(44)=√(4\cdot11)=2√(11)\n\nx_1=(6-2√(11))/(2\cdot(-1))=-3+√(11);\ x_2=(6+2√(11))/(2\cdot(-1))=-3-√(11)\n\nlook\ at\ the\ picture\n\nD:x\in\left<-3-√(11);-3+√(11)\right>$