While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the speed of the tennis ball is km/h.

Answers

Answer 1

Answer:

the answer is 11 km/h ... i just took the test

Answer 2

Answer: 8 km/h I think good luck if it's wrong

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Saturn has a radius of 60,330,000 meters and a mass of 5.7 × 10^26 kilograms. Calculate the strength of itsgravitational field.

Answers

g=Gm/(r^2)
=[(6.67*10^-11)(5.7*10^26)]/(60330000)
=630183988.1N/kg

How dense the medium is in the compression part of the wave, and how

Answers

How dense the medium is in the compression part of the wave and how rare the medium is in the rarefaction part of the wave is a measure of the longitudinal wave's amplitude.

A light ray traveling in air enters a secondmedium and its speed slows to 1.71 × 10^8 meters
per second. What is the absolute index of
refraction of the second medium?
(1) 1.00 (3) 1.75
(2) 0.570 (4) 1.94

Answers

Light travels at 300,000,000 meters per second, in scientific notation 3 * 10^8 meters per second. Note that in the medium it travels at 1.71 * 10^8. Taking the ratio of these two numbers with the final speed over the initial speed, we get (1.71*10^8)/(3*10^8) = 1.71/3 = 0.57

Your answer is (2) 0.570

Energy in the atom can be absorbed or released only in quanta of energy.

Answers

Released in quanta of energy

What is the frequncy of a wave that has a speed of 8m/s and a wave length of 2?

Answers

v = f \times λ

v = 8m/s

λ = 2

f = v \div λ

f = 8 \div 2

f = 4hz

a car accelerates for 5 seconds at 2.1 m/s squared if the car intentionally has a speed of 10 m/s what is its new speed

Answers

Answer:

final velocity will be

$v_f = 20.5 m/s$

Explanation:

As we know that initial speed of the car will be

$v_i = 10 m/s$

acceleration of the car is

$a = 2.1 m/s^2$

time taken is

$t = 5 s$

now we know that

$v_f = v_i + at$

$v_f = 10 + (2.1* 5)$

$v_f = 10 + 10.5 = 20.5 m/s$

Hey - for this problem you will find out your new velocity (similar to speed)

You take your Initial Velocity and add to it all the gained velocity you get during this process (which is the Acceleration multiplied by the amount of Time you are accelerating for)

So we get (Final Velocity) = (Initial Velocity) + (Time)(Acceleration)

In your equations, thats (Final Velocity) = (10 meters/second) + (5 seconds)(2.1 meters/second/second)

Which is 10 + 10.2 = 20.2 meters/second

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