if I have a 71 percent in a class and I take a final worth 10 percent of my grade and fail. what would my grade be? thanks in advance.

Answers

Answer 1

Answer:
I think you're asking for a numerical answer, but you didn't mention
your score on the final.

Since the final is worth 10% (one tenth) of the grade, that 71 that you
have going into the final is worth 9/10 of the grade. So the way you
calculate your overall average is

      Overall score = 1/10 of [ (71 x 9) + score on the final ] .

If you scored absolute zero on the final, your overall average would be

Overall score = (1/10) x [ (71 x 9) + 0 ] = (1/10) (639) = 63.9% .

That's the lowest overall score for the class that you can have.

The highest overall score you could have would be if you got 100% on the final.
Then
   Overall = (1/10) x (639 + 100) = (1/10) x (739) = 73.9% .

If you got a 50% on the final, your overall would be

   (1/10) x (639 + 50) = (1/10) x (689) = 68.9% .

In general, your overall score for the class, after the final, is going to be

   63.9% plus (1 tenth) of your score on the final.

Good luck !

Answer 2

Answer:
61 percent that's the answer

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The ratio of D's to A's in the school was 4 to 72. If there were 1080 A's in the school this term, how many D's were there? Write your answer in a complete sentence.

Answers

Answer:

To find the number of D's in the school, we can use the given ratio of D's to A's and the number of A's provided.

The ratio of D's to A's is given as 4 to 72. This means that for every 4 D's, there are 72 A's.

We are also given that there are 1080 A's in the school this term.

To find the number of D's, we can set up a proportion using the ratio:

4 D's / 72 A's = X D's / 1080 A's

Cross-multiplying, we get:

4 * 1080 = 72 * X

Simplifying further:

4320 = 72X

Dividing both sides by 72:

X = 4320 / 72

X = 60

Therefore, there were 60 D's in the school.

Step-by-step explanation:

Determine the type and number of solutions of 4x^2-5x+1=0.A. Two real solutions
B. One real solution
C. Two imaginary solutions

Answers

4x² - 5x + 1 = 0
a = 4; b = - 5, c = 1
Δ = b² - 4.a.c
Δ = (-5)² - 4.4.1
Δ = 25 - 16
Δ = 9

x = - b ± √Δ / 2.a
$x = (-5\± √(9) )/(2*4)$
$x = (-5\±3)/(8)$
$x' = (-5-3)/(8) = (-8)/(8) = -1$
$x' = (-5+3)/(8) = (-2)/(8) (/2) = (-1)/(4)$

A. Two real solutions (x' = -1 and x'' = -1/4)

A share of stock in the Lofty Cheese Company is quoted at 25 1/4. Suppose you hold 30 shares of that stock, which you bought at 20 1/4. If you sell your stock at 25 1/4, which one of the following statements would be true? A: you'll suffer a loss of $15
B: you'll make a profit of $15
C: you'll make a profit of $150
D: you'll suffer a lose if $150

Answers

Since each share was purchased when it was still quoted at 20 1/4, then when the stock value increases, it gains (25 1/4 - 20 1/4) = $5.00 for each stock.Since you're to sell 30 shares of your stock, that means you'll be making a profit of (30 x 5 ) = $150.00.Thus, the answer is C.

The true statement is that you'll make a profit of $150 which is option C.

Given that,

A share of stock in the Lofty Cheese Company is quoted at 25 1/4.

Suppose you hold 30 shares of that stock, which you bought at 20 1/4.

If you sell your stock at 25 1/4, we have to know if they suffer profit or loss and by what amount.

Cost of the stock which you bought is,

Cost = 30 × 20 1/4

= 30 × 20.25

= 607.5

If you sell your stock at 25 1/4,

Selling price = 30 × 25 1/4

= 30 × 25.25

= 757.5

Difference = 757.5 - 607.5

= 150

Hence you have a profit of $150.

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How is the process of finding equivalent ratios like the process of finding equivalent fractions?

Answers

It's generally the same, because each ratio can be written as a fraction and each fraction can be written as a ratio. For example:

1 : 2 = 1/2
5 : 7 = 5/7
3.5 : 4.3 = 3.5/4.3 = 35/43
etc.

Finding equivalent ratios is just multiplying or dividing both sides by the same number. Finding equivalent fractions is multiplying or dividing both numerator and denominator by the same number, so it's the same. For example:

1 : 2 = 2 : 4
1/2 = 2/4

5 : 7 = 10 : 14
5/7 = 10/14

3.5 : 4.3 = 7 : 8.6
35/43 = 70/86

etc.

HELP PLEASE!!The cross sections shown above are from a rectangular prism.

Cross section A is from a plane that is parallel to the base cutting through the prism. Cross section A has an area of 90 units squared.

Cross section B is from a plane that is perpendicular to the base and parallel to the sides of the prism cutting through the prism. Cross section B has an area of 50 units squared.

Cross section C is from a plane that is perpendicular to the base and parallel to the front of the prism cutting through the prism. Cross section C has an area of 45 units squared.

The prism in which the cross sections were taken has a length of
units, width of
units, and a height of
units.

Answers

The rectangular prism has a length of 9 units, a width of 10 units (since width = 90 / length), and a height of 5 units (since height = (5/9) length).

What is the area of a rectangle?

A rectangle is a quadrilateral with four right angles (90-degree angles) and opposite sides that are parallel and congruent (equal in length). The area of a rectangle is defined as the amount of space that is enclosed by its two-dimensional shape, and it can be calculated by multiplying the length of the rectangle by its width. The formula for the area of a rectangle is:

Based on the given information, we can determine the dimensions of the rectangular prism as follows:

Cross section A has an area of 90 square units, which is equal to the area of the base of the prism. Since the base of the prism is a rectangle, we can use the formula for the area of a rectangle to find its dimensions:

90 = length x width

Cross section B has an area of 50 square units, which is equal to the area of one of the sides of the prism. Since the sides of the prism are also rectangles, we can use the formula for the area of a rectangle to find its dimensions:

50 = height x width

Cross section C has an area of 45 square units, which is equal to the area of the front of the prism. Since the front of the prism is also a rectangle, we can use the formula for the area of a rectangle to find its dimensions:

45 = length x height

We now have three equations with three unknowns, which we can solve for to find the dimensions of the prism:

90 = length x width

50 = height x width

45 = length x height

Solving for width in the first equation gives us:

width = 90 / length

Substituting this into the second equation gives us:

50 = height x (90 / length)

Solving for height gives us:

height = 50 x (length / 90) = (5/9) length

Substituting this into the third equation gives us:

45 = length x (5/9) length = (5/9) length²

Solving for length gives us:

length² = (9/5) x 45 = 81

length = √(81) = 9

Therefore, the rectangular prism has a length of 9 units, a width of 10 units (since width = 90 / length), and a height of 5 units (since height = (5/9) length).

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Rewrite 2 4/5 as an improper fraction