A student earned a grade of 80% on a math test that had 20 problems.how many problems in this test did he student answer correctly (ROUND TO THE NEAREST WHOLE NUMBER)

Answers

Answer 1

Answer: Multiply 20 by.80 to find the number of correct answers, which is 16.

Answer 2

Answer:

Answer- 80 – 60 = 20, so 100 – 60 = 40 students

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Find the next term in the
sequence.
-31,-22,-13,-4,[ ? ]

Answers

$\text{First, we have to find the pattern of the sequence}\n\n\text{You would noticed that the pattern of the sequence is +9}\n\n\text{This means that the sequence is growing by 9 each time}\n\n\text{In order to find the next number, add 9 to -4}\n\n-4+9=5\n\n\boxed{\text{The next number in the sequence is 5}}$

The next sequence is 5

Simplify: 2^12/2^1 Thank you

Answers

$(2^(12))/(2^1)=2^(12-1)=2^(11)$

$(2^(12))/(2^1)=2^(11)$

If the measure of an angle is 13, find the measure of its supplement

Answers

An angle added with it's supplement is 180.

Knowing this: 180 - 13 = 167

It's supplement is 167

The correct answer would be 167.

A supplement means when added with another angle it will equal 180. Therefore,

180 - 13 = 167.

Hope this helps! Have a good day/night! c:

Write the nunber 0.035 as a percent

3.5%
0.35%
35%
0.035%

Answers

you bring the decimal point 2 places to the right.

answer is A

We want to write the decimal number 0.035 in percent form. So, to convert this value to percent, we just multiply it by 100.
In this example multiplying 0.035 by 100, we get 3.5 (the value in percent).

Step 1: Move the decimal point two places to the right: 0.035 → 0.35 → 3.5.
Step 2: Add a % sign: 3.5%So, 0.035 is equivalent to 3.5% in percent form.
Hope this helps :)

A spoon is 5ml or 5 l

Answers

A spoon is 5ml.
5l is a large amount (more than 2 containers of orange juice!)

A spoon is 5 milliliter because 5 liters is exaggeratedly to much for 1 spoon to hold.

The first five terms of a sequence are 7,10, 13 , 16 and 19. which of the following functions define this sequence for all integers n>or equal to 1?A. f[n]= 3n=7
B.f[n]= 4+3n
C. f[n]= 4[3]^n-1
D.f[n]=7[3]^n-1