What is the value of 36x - 8y to the power of 2, when x=3 and y= -6

Answers

Answer 1
Answer: 36x-8y^2 \hbox{ when } x=3 \hbox{ and } y=-6 \n \n36 * 3 -8 * (-6)^2=3 * 36 - 8 * 36=(3-8) * 36= -5 * 36=\n =\boxed{-180}
Answer 2
Answer: (36x-8y)^(2)

[36(3)-8(-6)]^2

(108+48)^2

156 ^(2)

=24336

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Twice the sum of a number and three

Answers

the answer will be 2(x+3)

The product of 8 and the sum of a number m and 6 is 12.

Answers

8 (m+6) =12 is the way to write it

The Johnsons own a home whose market value is $93,000. Their municipality taxes at 80% and the rate is 65 mills or $65 per thousand. What will the Johnsons pay in taxes?

Answers

Answer: He paid $ 4836 in taxes.

Step-by-step explanation:

Here, the total value of the house = $ 93,000

And, the amount on which municipal taxes imposed = 80% of the value of house

= 80% of 93000

=  0.8 × 93000

= $ 74,400

Now, the tax rate is $65 per thousand,

\text{The amount of tax for 1000 dollars }= \$ 65,

\text{The amount of tax for 1 dollar}=(65)/(1000)

⇒  \text{The amount of tax for 74400 dollars}=(74400* 65)/(1000)

=(4836000)/(1000)

=\$ 4836

Thus, he paid $ 4836 in taxes.

Answer:

6760

Step-by-step explanation:

80% x 93000 = 74400

74.4 x 65 = 6760

Formula of trigonometric ratios​

Answers

\huge \boxed{\mathfrak{Question} \downarrow}

  • Formula for trignometric ratios.

\huge \boxed{\mathfrak{Answer} \downarrow}

The trignometric ratios are \downarrow\downarrow

\begin{gathered}\begin{gathered}\begin{array}{||c|c|c||} \n \rm sin \:  A &  (\sf\:Opposite\: side\: of\: angle\: A )/(\sf\:Hypotenuse \: )   & (\sf\:BC)/(\sf\:AC) \n \n \rm cos \: A &  ( \sf\: Adjacent \:side \:of\: angle \:A )/(\sf\: Hypotenuse) & (\sf\: AB)/( \sf\: AC)  \n \n \rm tan A &  (\sf\: Opposite \:side \:of \:angle\: A)/( \sf\: Adjacent \:side \:of \:angle \:A ) & (\sf\:BC)/( \sf\: AB)\n \n \rm cosec A & (\sf\: Hypotenuse)/(\sf\: Opposite\: side \:of\: angle\: A)&  (\sf\:AC)/( \sf\:BC ) \n \n \rm sec A  & (\sf\: Hypotenuse)/( \sf\: Adjacent \:side\: of\: angle \:A)& (\sf\:AC)/(\sf\:AB)\n \n \rm cot A & (\sf\: Adjacent \:side\: of \:angle \:A)/(\sf\: Opposite\: side \:of\: angle\: A) & (\sf\:AB)/( \sf\: BC)  \end{array}\end{gathered}\end{gathered}  \n  \n  -  \bf \: Lucazz \: (brainly.com)

~~~

  • Refer to the picture for better understanding.

Answer:

Basic Formulas

sin θ = Opposite Side/Hypotenuse.

cos θ = Adjacent Side/Hypotenuse.

tan θ = Opposite Side/Adjacent Side.

sec θ = Hypotenuse/Adjacent Side.

cosec θ = Hypotenuse/Opposite Side.

cot θ = Adjacent Side/Opposite side.

Hope this helps :)

Square root of 64 over 25

Answers

**Refresh page if you see [ tex ]**

Knowing that 64 = 8^2\quad\text{and}\quad25 = 5^2, we have

\sqrt{(64)/(25)} = (√(64))/(√(25)) = \boxed{(8)/(5)}
so \sqrt{(64)/(25) }

that is equal to  ( √(64))/( √(25)) = (8)/(5)

A vat of milk has spilled on a tile floor. The milk flow can be expressed with the function r(t) = 4t, where t represents time in minutes and r represents how far the milk is spreading.The spilled milk is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2.

Part A: Find the area of the circle of spilled milk as a function of time, or A[r(t)]. Show your work. (6 points)

Part B: How large is the area of spilled milk after 4 minutes? You may use 3.14 to approximate π in this problem. (4 points)

Answers

Part A

Area = π[r(t)^]2 = π[(4t)^2] =16π(t)^2

Part B

t = 4 min

Area = 16(3.14)(4)^2= 803.84