7 times as much as the sum of 1/3 and 4/5

Answers

Answer 1
Answer: 7( (1)/(3) +  (4)/(5) )

=7( (1(5))/(3(5)) +  (4(3))/(5(3)) )

=7( (5)/(15) +  (12)/(15) )

=7( (17)/(15))

=(7)/(1) ( (17)/(15))

=(119)/(15)

= 7(14)/(15)≈ 7.93
Answer 2
Answer:

¹¹⁹/₁₅ or 7¹⁴/₁₅ or 7.93

Further explanation

The Problem:

  • 7 times as much as the sum of (1)/(3) and (4)/(5)
  • Write an expression to match, and then solve it.

The Process:

Here are some early expressions that need attention.

  • one-third is \boxed{(1)/(3)}
  • four-fifth is \boxed{(4)/(5)}
  • the sum of (1)/(3) \ and \ (4)/(5) is \boxed{(1)/(3) + (4)/(5)}

Let us write an expression to match for 7 times as much as the sum of (1)/(3) and (4)/(5)

\boxed{\boxed{ \ 7 * \bigg((1)/(3) + (4)/(5) \bigg) \ }}

Let us calculate the operation in parentheses at first.

\boxed{(1)/(3) + (4)/(5)}

A least common multiple of 3 and 5 is 15. We use to equate the denominator.

\boxed{(1 * 5)/(3 * 5) + (4 * 3)/(5 * 3)}

\boxed{(5)/(15) + (12)/(15)}

\boxed{(17)/(15)}

And now we solve the full expression.

\boxed{ \ = 7 * \bigg((1)/(3) + (4)/(5) \bigg) \ }

\boxed{ \ = 7 * (17)/(15) \ }

We do not cross out 7 and 15 because they both cannot be divided.

\boxed{ \ = (119)/(15) \ }

\boxed{\boxed{ \ = (119)/(15) \ }}

In mixed fraction:

\boxed{ \ (119)/(15) = \ ? \ }

\boxed{ \ = (105)/(15) + (14)/(15) \ }

\boxed{ \ = 7 + (14)/(15) \ }

\boxed{\boxed{ \ = 7(14)/(15) \ }}

In decimal:

\boxed{ \ 7(14)/(15) = \ ? \ }

\boxed{ \ (14)/(15) = 0.93 \ }

\boxed{ \ = 7 + (14)/(15) \ }

\boxed{ \ = 7 + 0.93 \ }

\boxed{\boxed{ \ = 7.93 \ }}

\boxed{\boxed{ \ Thus, \ the \ result \ is \ (119)/(15) \ or \ 7(14)/(15) \ or \ 7.93 \ }}

- - - - - - - - - -

Quick Steps:

\boxed{ \ = 3 * \bigg((1)/(3) + (4)/(5) \bigg) \ }

\boxed{ \ = 3 * \bigg((5 + 12)/(15) \bigg) \ }

\boxed{ \ = 3 * \bigg((17)/(15) \bigg) \ }

\boxed{\boxed{ \ = (119)/(15) \ }}

\boxed{\boxed{ \ = 7(14)/(15) \ }}

\boxed{\boxed{ \ = 7.93 \ }}

Learn more  

  1. 7 copies of the sum of 8 fifths and 4 brainly.com/question/961462
  2. (2)/(3) of the product of (3)/(8) and 16 brainly.com/question/961462
  3. 15 times as much as 1 fifth of 12 is brainly.com/question/348151

Keywords: 7 times, as much as, the sum of 1/3 and 4/5, write an expression to match, and then solve, the result, in mixed fraction, decimal, ¹³/₄ or 3¹/₄ or 3.25


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What is the slope of a line that is perpendicular to the line y=-1/3x-6OA. 3
OB. 1/3
OC. -1/3
O D. 3​

Answers

Answer:

3

Step-by-step explanation:

3 is the complete oposite of -1/3 in terms of slopes, therefore they are perpendicular to each other.

Each participant in a certain study was assigned a sequence of 3 different letters from the set {a, b, c, d, e, f, g, h}. if no sequence was assigned to more than one participant and if 36 of the possible sequences were not assigned, what was the number of participants in the study? (note, for example, that the sequence a, b, c is different from the sequence c, b,a.) 20

Answers

Number of possible sequence of 3 in 8  = 8P3 = 8! / (8-3)! =  336
36  were not assigned so  number participants = 300 (answer).

Pls help it will mean alot!!
due rn!!

Answers

Answer:

f(x) = 4^x

f(4) = 4^4 = 256

Hope this helps!

:)

the answer is 256 but i am not sure

hope this helps and be safe :)

Which sequence is modeled by the graph below?coordinate plane showing the points 2, 1; 3, 3; and 4, 9

an = one third(27)n − 1

an = 27(one third)n − 1

an = one third(3)n − 1

an = 3(one half)n − 1

Answers

Answer:

a_n=(1)/(3)\cdot (3)^(n-1)

C is correct.

Step-by-step explanation:

We need to choose correct model by the graph which passes through the points (2,1) (3,3) and (4,9)

Option 1: a_n=(1)/(3)\cdot (27)^(n-1)

Put n=2 and to get a₂=1

a_2=(1)/(3)\cdot (27)^(2-1)

a_2=9

9\neq 1

False

Option 2: a_n=27\cdot ((1)/(3))^(n-1)

Put n=2 and to get a₂=1

a_2=27\cdot ((1)/(3))^(2-1)

a_2=9

9\neq 1

False

Option 3: a_n=(1)/(3)\cdot (3)^(n-1)

Put n=2 and to get a₂=1

a_2=(1)/(3)\cdot (3)^(2-1)

a_2=1

1= 1

TRUE

Similarly, we will check (3,3) and (4,9)

and we will get true

Hence, The sequence is a_n=(1)/(3)\cdot (3)^(n-1)

Answer:

the answer is C. an = one third (3)n − 1

i just took the test.

Step-by-step explanation:

billy and Ryan had a competition at the batting cage. billy hit 7 balls for every 4 balls Ryan hit. billy and Ryan hit a total of 99 balls. how many balls did each boy hit?

Answers

We are to find the number of hits Billy and Ryan had in this game. We are then to find 2 thing or in other words there are 2 variables that we have to solve. As a rule we need to find 2 relationships. The 2 relationships or equations are: 

B + R = 99

(B)/(R) = (7)/(4) or 4B - 7R = 0 
where B- Billy's hit and R - Ryan's hit. 

B= 63
R=36


What's y in: 21y=(-205) +75+47y

Answers

The Answer Is A Fraction y= 151/47
21y=−205+75+47ySimplify: (Show steps)21y=(47y)+(−205+75)(Combine Like Terms)21y=47y+−13021y=47y−130Step 2: Subtract 47y from both sides.21y−47y=47y−130−47y−26y=−130Step 3: Divide both sides by -26.26y−26=−130−26y=5