What two factors determine the thermal energy in a substance

Answers

Answer 1

Answer: the answer to that is mass and chemical

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A chemical manufacturer sells sulfuric acid in bulk at a price of $100 per unit. If the daily production cost in dollars for x units is: C(x)=100,000+50x+0.0025x^2, and if the daily production capacity is at most 7000 units, how many units of sulfuric acid must be manufactured and sold daily to maximize the profit?

Which of the following elements would be classified as a nonmetal? sulfur aluminum silicon calcium

Answers

sulfur is a non metal

Sulfur is considered a non-metal. Thanks for posting your question. Feel free to ask me any question. I might not always know the answer. Although i'll try to answer correctly. Have a good day love.

When converting an acid salt dissolved in water to its acid form, you are instructed to adjust the pH well into the acidic range (pH = ~2). Why don’t you just take the pH to neutral? You do the same for adjusting the pH of a solution containing an amine salt taking it well into the basic range rather than neutral. Why are you instructed to do this?

Answers

Answer:

The answer lays in logD.

Explanation:

So when you end up with neutral pH amine or either carboxylic acid can still be in a salt form. So for every compound the pH level of unionized form is different and for the best extraction experience is better to perform and extraction at as low as possible pH for acids and for amines as high as possible.

What does a mid ocean ridge record?

Answers

Explanation:

A mid-ocean ridge is a geological feature that records several important aspects of Earth's history and processes:

1. **Seafloor Spreading:** Mid-ocean ridges are where tectonic plates are moving apart. As new oceanic crust forms at these ridges through volcanic activity, it records the process of seafloor spreading. This process is a key component of plate tectonics, which explains the movement of Earth's lithospheric plates.

2. **Magnetic Reversals:** The seafloor at mid-ocean ridges contains bands of magnetic minerals that align with the Earth's magnetic field at the time the rock solidified. These bands provide a record of past magnetic field reversals, which is essential for understanding Earth's magnetic history.

3. **Geological History:** The rocks and formations found along mid-ocean ridges contain valuable information about the geological history of the ocean floor. This includes details about the composition of the Earth's crust and the minerals present in the oceanic lithosphere.

4. **Evidence of Hydrothermal Activity:** Mid-ocean ridges often host hydrothermal vent systems, where superheated water emerges from the seafloor. These vent systems record evidence of extreme environments and unique ecosystems that thrive in these conditions.

In summary, mid-ocean ridges record information about plate tectonics, magnetic field reversals, geological history, and hydrothermal activity, making them crucial sites for understanding Earth's dynamic processes and history.

What is added within the Shielded Twisted Pair Cable (STP) to reduce the incident of crosstalk?

Answers

Answer:

Shielded Twisted Pair (STP) cable includes an additional layer of shielding to reduce the incidence of crosstalk, which is electromagnetic interference or signal bleed between adjacent pairs of twisted cables. This shielding is usually made of metal foil or braided wire and is wrapped around the individual twisted pairs or the entire cable. Here are the key components added within STP to reduce crosstalk:

Explanation:

1.Shielding: STP cables have a metal shield that surrounds the twisted pairs or the entire cable. This shield acts as a barrier to block external electromagnetic interference (EMI) and also reduces the emission of electromagnetic interference from the cable itself.

2.Metal Foil or Braided Wire: The shielding material can be a thin metal foil or a braided wire mesh. These materials are highly conductive and capable of efficiently diverting and grounding any electromagnetic interference that may affect the cable.

3.Grounding: To be effective, the shield in STP cables needs to be properly grounded at both ends of the cable. This grounding helps in dissipating any unwanted electrical noise or interference that is captured by the shield.

4.Aluminum or Mylar Tape: Sometimes, STP cables may also have an additional layer of aluminum or Mylar tape between the shield and the twisted pairs. This tape adds an extra level of protection against interference.

The shielding in STP cables significantly reduces crosstalk and makes them suitable for environments where EMI is a concern, such as industrial settings or areas with a high concentration of electronic equipment. However, STP cables tend to be thicker and less flexible compared to Unshielded Twisted Pair (UTP) cables, which are more commonly used for standard Ethernet connections in office and home networks.

Final answer:

In a Shielded Twisted Pair Cable (STP), a shielding composed of an insulating material and a conductive layer is added. This shielding contains the electromagnetic fields within the cables thus reducing the incident of crosstalk.

Explanation:

In a Shielded Twisted Pair Cable (STP), a shielding is added to reduce the incident of crosstalk. This shielding is typically composed of an insulating material and a conductive layer, which is often made of metal foil or a braid. The shielding serves to contain the electromagnetic fields within the cables, protecting the internal wires from external influences, thereby significantly reducing the likelihood of crosstalk. For instance, in a network setting, shielding can help prevent data transmitted along one wire from being picked up by another, thus improving the quality of the transmitted signal. It's important to know that while shielding helps reduce crosstalk, it also makes the cable bulkier, and somewhat more difficult to install and manage compared to Unshielded Twisted Pair (UTP) cables.

Learn more about STP Cable Shielding here:

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Carbon disulfide (CS2) undergoes a single displacement reaction with O2 to form CO2. If 100 grams of CS2 reacts with 38 grams of O2, what will the limiting reagent be?CS2 + O2 CO2 + 2S

Answers

The balanced chemical reaction is:

CS2 + O2 = CO2 + 2S

We are given the amounts of the reactants. These amounts will be the starting point for the calculations. First, we convert these amounts into moles.

100 g CS2 (1 mol / 76.15 g ) = 1.3132 mol CS2
38 g O2 (1 mol / 32 g) = 1.1875 mol O2

From the reaction, the mole ratio of the reactants is 1:1. Therefore, the limiting reactant is CS2.

Answer: $O_2$

Explanation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of $CS_2=(100g)/(76g/mol)=1.3moles$

Moles of $O_2=(38g)/(32g/mol)=1.2moles$

For the given chemical reaction, the equation follows:

$CS_2+O_2\rightarrow CO_2+2S$

By Stoichiometry:

1 mole of oxygen reacts with 1 mole of carbon disulphide

So, 1.2 moles of oxygen reacts with = $(1)/(1)* 1.2=1.2moles$ of carbon disulphide

As, the required amount of carbon disulphide is more than the required amount. Hence, it is considered as the excess reagent. (1.3-1.2)= 0.1 mole will be left unused.

Oxygen is considered as a limiting reagent because it limits the formation of product.

Which statement correctly compares an atom of an alkali metal with an atom of the alkaline earth metal next to it on the periodic table?The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion.
The alkali metal atom forms a +2 ion, while the alkaline earth metal atom forms a +1 ion.
The alkali metal atom has one less shell of electrons than the atom of the alkaline earth metal.
The alkali metal atom has one more shell of electrons than the atom of the alkaline earth metal.

Answers

Answer: The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion.

Explanation: Group 1 elements are called as alkali metals and group 2 elements are called as alkaline earth metals.

For example, Li is an alkali metal and Be is an alkaline earth metal.

Lithium(Li) has an atomic number of 3 and the electronic configuration is:

Li: $1s^22s^1$

Thus lithium has to lose 1 electron and acquire 1+ charge to attain nearest noble gas configuration.

$Li^+:1s^2$

Berrylium(Be) has an atomic number of 4 and the electronic configuration is:

Be: $1s^22s^2$

Thus berrylium has to lose 2 electrons and acquire 2+ charge to attain nearest noble gas configuration.

$Be^(2+):1s^2$

Answer:

Explanation:

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