If (x − 2)^2=49, then x could be ?

Answers

Answer 1

Answer: $(x - 2)^2=49\n \n x^2-4x +4 -49=0\n \nx^2-4x -45 = 0\n \n\Delta = b^(2)-4ac = (-4)^(2)-4*1* (-45)= 16+180=196 \n \nx_(1)=(-b-√(\Delta ))/(2a) =(4-√(196))/(2)=(4-14)/(2)=(-10)/(2)=-5 \n \nx_(2)=(-b+√(\Delta ))/(2a) =(4+√(196))/(2)=(4+14)/(2)=(18)/(2)=9 \n \nAnswer : \ x=-5 \ or \ x= 9$

Answer 2

Answer: (x-2)(x-2)
x^2 -2x -2x +4 =49 (-49 from both sides)
X^2-4x-45
(x+5)(x-9)
x=-5, x=9

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Solve
Sin(2theta)=1/2

Answers

Just change the fraction into an equivalent in the sine function.

$sin(2\theta)= (1)/(2) \n sin(2\theta)=sin( ( \pi )/(6)+2k \pi ) \n 2\theta=( \pi )/(6)+2k \pi \n \theta=( \pi )/(12)+k \pi \n \n sin(2\theta)= (1)/(2) \n sin(2\theta)=sin( ( 15\pi)/(18)+2k \pi ) \n 2\theta=( 15\pi )/(18) +2k \pi \n \theta=( 15\pi )/(36)+k \pi$

Therefore:

$\boxed {S=(\theta \epsilon R | \theta=( \pi )/(12)+k \pi ~or~ \theta=( 15\pi )/(36)+k \pi, k \epsilon Z)}$

If you notice any mistake in my english, please let me know, because i am not native.

sin(2theta)=1/2

sin(x)=α
x=(-1)^k arcsin α+πk

2theta=(-1)^k arcsin 1/2 + πk k∈Z
arcsin 1/2= π/6
2theta=(-1)^k π/6 + πk k∈Z
theta=(-1)^k π/12 + πk/2 k∈Z

Write the missing value above the variable. M-9=7

Answers

If you're for the value of "m" then follow these steps to see what the answer is

m - 9 - 7 = ?
? = 0

Now, let's add the number 16 to the sides that you're working with
Here's what I am talking about in case you don't know what I am talking
m - 16 = 0
+ 16
-------
16

So, the value of m is 16 ;
$m=16$

This is basic mathematics.Just practice your addition and subtraction facts in the problem like this

m=16
16-9=7
hope this helped:)

13.A student wishes to determine the percentage of students in his school that bring a sack lunch. He decides to poll every student in his grade level. It is found that 30 percent on the students polled bring a sack lunch. The student concludes that 30 percent of the students in the school bring a sack lunch. Identify the abuse of statistics.

bad sample

small sample

nonresponse

loaded question

Answers

Answer:

The answer is Bad sample.

Step-by-step explanation:

The student polls every student in his grade level. It is found that 30 percent on the students polled bring a sack lunch.

The student concludes that 30 percent of the students in the school bring a sack lunch.

Firstly, students of a single grade do not represent the entire school population. The student here asked every student of his class, so the sample was not random. It was biased and bad.

The collected data is not representative of the population, so it is a bad sample or bad sampling.

I would say this is considered small sample, because there is nothing really wrong with his survey in terms of quality. it's not like he only survey boys or girls, or like only survey rich or poor people. In other words, his survey is from a random pool, assuming the kids in his grade are mostly normal people. Therefore, I would say that if this person surveyed more people, then he'll get much better data.

One group of people purchased 10 hot dogs and 5 soft drinks for $35. Another group purchased 7 hot dogs and 4 soft drinks for $25.25. What is the cost of a single hot dog? A single soft drink?

Answers

10 H + 5 D = $35    times all by 4 40 H + 20 D = $140.00
7 H + 4 D = $25.25 times all by 5 - 35 H - 20 D    = -126.25 and subtract
Subtract 5 H = $13.75
Divide by 5 to find price of one hot dog H = $2.75

10 ($2.75) + 5 D = $35 input cost of one hot dog into first equation
   $27.50 + 5 D = $35.00
- $27.50 = -$27.50
   5 D = $ 7.50 divide by 5 so one drink is $1.50 then go back and check

Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = -1.

Answers

$(x;\ y)-the\ coordinates\ any\ point\ on\ the \ parabola.\n\nDistance\ between\ the\ point\ (x;\ y)\ and\ the\ focus\ (-5;\ 5)\nand\ distance\ between\ the\ point\ (x;\ y)\ and\ a\ direct\ are\ equal.\n\nDistance\ between\ (x;\ y)\ and\ (-5;\ 5):\n√((x-(-5))^2+(y-5)^2)=√((x+5)^2+(y-5)^2)\n\nDistance\ between\ (x;\ y)\ and\ y=-1:\n|y-(-1)|=|y+1|\n\nWe\ equate\ the\ two\ expressions:\n√((x+5)^2+(y-5)^2)=|y+1|$

$Square\ both\ sides:\n(x+5)^2+(y-5)^2=(y+1)^2\n\nUse:(a\pm b)^2=a^2\pm2ab+b^2\n\nx^2+2\cdot x\cdot5+5^2+y^2-2\cdot y\cdot5+5^2=y^2+2\cdot y\cdot1+1^2\nx^2+10x+25+\not y^2-10y+25=\not y^2+2y+1\nx^2+10x-10y+50=2y+1\n2y+1=x^2+10x-10y+50\ \ \ \ |subtract\ 1\ from\ both\ sides\n2y=x^2+10x-10y+49\ \ \ \ |add\ 10y\ to\ both\ sides\n12y=x^2+10x+49\ \ \ \ |divide\ both\ sides\ by\ 12\n\n\boxed{y=(1)/(12)x^2+(5)/(6)x+(49)/(12)}$

Which one is it , help me on this please please please please please please please

Answers

Answer:

Step-by-step explanation:

7^-2 = 1/7^2

The negative means you flip it

1/7^2 times 7^6 is 7^6/7^2 (just multiply).

using rules of exponents, 7^6/7^2 is 7^4 (just subtract 2 from 6)

D is the only one that equals 7^4, as 2 times 2 is 4.

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