You would predict that iodized salt would have no effect on any cases of ____________.

Answers

Answer 1
Answer: The body's main requirement of iodine is in the thyroid gland. Therefore, iodized salt would have no effect on any cases of Graves' disease as the thyroid gland is already overactive in this disease.
Answer 2
Answer: Iodized salt does not have any effect on any cases of Graves' diseases.

Related Questions

The two most abundant elements in earth's core are ?
What is the volume of a tank of nitrogen if it contains 17 moles of nitrogen at 34 C under 12,000 Pa?
Help me please I really need this tomorrow
Studies suggest that consumption of large amounts of red and processed meats, along with low intake of fiber and phytochemicals, may be responsible for which one of the following forms of cancer?A. Liver B. Kidney C. Colorectal D. Stomach
Given the reaction: S(s)+ O2(g)- SO2(g)+ energy which diagram best represents the potential energy changes for this reaction

What element has 3 electrons in its Lewis dot structure and is in the 2p orbital

Answers

I think the element with 3 electrons in its lewis dot and a 2p orbital will be Boron

How many atoms are in 3.75 moles of Phosphorus? A) 136 atoms
B) 35 atoms
C) 6.23x10^-24 atoms
D) 2.26x10^24 atoms

Answers

there are 6.022145E+23 atom per one mole.

Calculate the mass in grams of 7.88 mol of RbMnO4

Answers

Molar mass RbMnO₄ = 204.40 g/mol

1 mole ---------- 204.40 g
7.88 mole ------ ?

mass = 7.88 * 204.40 / 1

mass = 1610.672 g

hope this helps!

Atoms of which types of elements tend to gain electrons? Atoms of which types of elements tend to lose electrons?

Answers

Atoms of elements that are nonmetals tend to gain electrons and atoms of metallic elements tend to lose electrons. Metals have few electrons in their valence shells.By losing those electrons, these metals achieve noble gas configuration and satisfy the octet rule.Nonmetals that have close to 8 electrons in their valence shells readily accept electrons to achieve noble gas configuration.An example is the reaction between calcium and oxygen. Calcium is a metal and has 2 valence electrons. Oxygen is a nonmetal and has 6 valence electrons.Calcium gives up its two valence electrons and oxygen accepts them and an ionic bond is established resulting in the formation of anew compound namely calcium oxide.

Final answer:

Nonmetals, such as those in groups 14 and 17, generally gain electrons becoming more stable anions. Metals, like those in group 1, typically lose electrons and form stable cations. An example is in ionic compounds where metal atoms like sodium lose electrons and nonmetal atoms like chlorine gain electrons.

Explanation:

In the context of elements and their atoms, nonmetals, which include elements from group 14 and group 17, tend to gain electrons. This gain in electrons forms negative ions, or anions, which fills their outermost electron shell, making them energetically more stable.

On the other hand, metals like those from group 1, tend to lose electrons. This event makes them energetically more stable by forming positive ions, or cations, and allowing them to achieve an electron configuration similar to noble gases.

For instance, to fill their outermost shells, elements donate or accept electrons. In ionic compound formation, metals like sodium (Na) lose electrons while nonmetals like chlorine (Cl) gain these electrons, achieving a stable configuration.

Learn more about Electron Transfer in Atoms here:

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77. 1 kilograms. What's The mass in grams

Answers

77,100 grams plz give brainliest thanks
The answer is 77,000

How many days are required for 200. grams of radon-222 to decay to 50.0 grams?(1) 1.91 days (3) 7.64 days(2) 3.82 days (4) 11.5 days

Answers

The answer is: 3) 7.64 days.

The most stable isotope of radon (Rn) is radon-222 with a half-life of 3.82 days.

After first half life (3.82 days) = 0.5 · 200 g.

After first half life (3.82 days) = 100 g of radon-222.

After second half life (7.64 days) = 0.5 · 100 g.

After second half life (7.64 days) = 50 g of radon-222.

Half-life is the time required for a quantity (in this example number of radioactive nuclei of radon-222) to reduce to half its initial value and is independent of initial concentration.

The answer is (3) 7.64 days. The remaining mass of radon-222 is one fourth of the original mass, so two half lives have elapsed (because one half time one half equals one fourth). Each half life of radon-222 is about 3.82 days, so the total time elapsed is 3.82 * 2 = 7.64 days