A skateboarder on a half-pipe changes his velocity from 6.0 m/s forwards to 4.0 m/s backward in 5.0 s. What is the acceleration of the skateboarder?

Answers

Answer 1

Answer: the change in velocity is 10 m/s in 5 seconds.

sinces a = change in velocity/time

a= 10/5

a=2

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What two factors affect the amount of friction that act on a moving object?

Answers

The types of surfaces and the amount of pressure being put on them.

How hard the surfaces push together and the type of surface it is rubbing against. Refer to this practice packet

How do you calculate the initial speed given time and displacement?The question is: The longest kick in CFL history was 83.2m. If the ball remained in the air for 4.12s, determine its initial speed.
I calculated it several times and got the same answer, 40.38m/s, but the textbook says it's 28.6m/s.

Answers

Let's first find the velocity in the x-direction which is constant.
$d = vt \n v = (d)/(t) \nv = (83.2m)/(4.12s) \n v= 20.2m/s$

Now, we need the velocity in the y-direction
$d = v_(o)t + (1)/(2)a t^(2) \n d - (1)/(2)at^(2) = v_(o)t\nv_(o) = (0 - (1)/(2)(-9.81)(4.12)^(2))/(4.12)\nv_(o) = 20.2m/s$

Finally, we need to put the two velocities together using pythagorean theorem
$v_(t)^(2) = v_(x)^(2) + v_(y)^(2)$
$v_(t) = \sqrt{20.2^(2) + 20.2^(2)}$
v = 28.6m/s

a boy on a bicycle is resting at the top of a hill then he rides his bicycle down the hill describe how the boy potential and kineti energy differ at the top middle and bottom of the him

Answers

Answer:

Explanation:

As the boy is riding from top to bottom of the hill his Potential energy gradually decreasing and simultaneously converting into the Kinetic energy.

At the top, his Potential Energy is maximum and kinetic energy is minimum i.e. zero

In the middle of the hill, he possesses both Potential and kinetic energy with equal magnitude.

At the bottom whole Potential energy is converted into Kinetic energy.

Thus Potential Energy is maximum at the top while Kinetic energy is maximum at the bottom.

Chanel has some cotton candy that came in a cloudy shape. She wants to make it more dense. Which describes the candy before and after Chanel manipulated it?

Answers

Answer:

The candy before was fluffy, and the candy after was compacted.

Explanation:

Final answer:

The cloudy cotton candy was light and fluffy due to the air incorporated in it. After Chanel made it dense, the candy became compact and heavier, as she decreased the volume and maintained or increased the amount of sugar.

Explanation:

The cotton candy that Chanel had originally was described as being in a cloudy shape. This suggests that it was light, fluffy, and probably had a lot of air incorporated into it, which is why it was able to maintain such a shape. After she manipulated it to make it more dense, the cotton candy would have lost its cloudy appearance. Instead, it would have become heavier and more compact, because decreasing the amount of air in it increases its density. In other words, the volume of the cotton candy has decreased, but the amount of sugar within that volume has remained the same or increased.