Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is how many grams/cubic meter.

Answers

Answer 1

Answer:

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, humidity in grams/cubic meter is 19.5.

What is matter?

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.

So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter.

humidity =30 × 65% =19.5 grams/cubic meter

Therefore, humidity in grams/cubic meter is 19.5.

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Answer 2

Answer:

Answer:19.5 grams/cubic meter

Explanation:30 times 65% search it it equals 19.5

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Which actions would increase the rate at which salt dissolves in water? Stir the water. Crush the salt. Use less water. Heat the water. Cool the salt.

Answers

Answer:

Crushing or grinding increases the surface area of the salt that is exposed to the molecules of water. Stirring increases the speed at which the particles of salt come in contact with the water molecules.

classify each orbital diagram for ground-state electron configurations by the rule or principle it violates.

Answers

The correct answer for the question that is being presented above is this one: see attached picture. Each orbital diagram for ground-state electron configurations by the rule or principle it violates: Aufbau violation, Hand violation, Pauli violation.

Assume that the arrangement as 1 - 5, then
Aufbau Violation = 5 & 2
Hand Violation = 3 & 4
Pauli Violation = 1

The question is incomplete:
Complete question is attached below:
.......................................................................................................................
Answer 1:
In the first case, two electrons in the 1st 2p sub-shell has both the electrons with same electron spin. This is a violation of Pauli's exclusion principle, according to which, orbital can contain a maximum of only two electrons, the two electrons must have opposing spins.

Answer 2:
In the second case, 3s and 3p orbital is incompletely filled. This is a violation of Hund's rule. According to Aufbau Principle, orbitals of lower energy get filled first and than orbital of higher energy. Hence, in present case, 3s orbital must be completely filled first and then electron must 3p orbital.

Answer 3:
In the 3rd case, the first sub-shell of 2p orbital has two electrons, while all other sub-shell is empty. This is a violation of Hund's rule, according to which all orbitals will be singly occupied before any is doubly occupied. Hence, in present case, there should be one electron present in each sub-shell of 2p orbital.

Answer 4:
In the forth case, 4s and 4p orbital are filled first and 3d orbital is filled. This is a violation of Aufbua principle. Because, according to Aufbua principle orbital of lower energy are filled first. In present case, 3d orbital has lower energy as compared to 4s and 4p orbital.

What is electropositivity and electronegativity? Between group 1 and group 17, which is electropositive and electronegative?

Answers

Electopositivity is the measure of the ability of elements to donate electrons to form positive ions. Whereas the Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons. Group 1 is more electropositive than group 17 and group 17 is more electronegative than group 1.

which of the following is an example of how research into the effects of a chemical has changed how it is used

Answers

Answer: Finding out that asbestos is dangerous and limiting its use in building materials

Explanation:

What occurs when an atom loses an electron?(1) The atom’s radius decreases and the atom becomes a negative ion.
(2) The atom’s radius decreases and the atom becomes a positive ion.
(3) The atom’s radius increases and the atom becomes a negative ion.
(4) The atom’s radius increases and the atom becomes a positive ion.

Answers

When an atom loses an electron, it becomes a positive ion and the radius of the atom decreases. The correct answer is option 2.

An atom is the basic unit of matter that consists of a nucleus, which contains positively charged protons and uncharged neutrons, surrounded by a cloud of negatively charged electrons.

The valence shell determines the size of the atom, and when an electron is removed from this shell, the size of the atom decreases. The loss of an electron from an atom creates a positively charged ion, called a cation.
The cation has a smaller radius than the neutral atom because the positive charge on the cation attracts the remaining electrons more strongly, pulling them closer to the nucleus.

Therefore, option 2. The atom’s radius decreases, and the atom becomes a positive ion is the correct answer.

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Answer:

When an atom loses an electron, the atom's radius decreases and the atom becomes a positive ion.

Which electron configuration represents the electrons in an atom of chlorine in an excited state?(1) 2-7-7 (3) 2-8-7
(2) 2-7-8 (4) 2-8-8

Answers

Final answer:

The electron configuration that represents the atoms of chlorine in an excited state is 2-7-8. This is because in the excited state, an electron has moved from the second energy level to the third

Explanation:

The electron configuration represents the distribution of electrons in an atom's energy levels. The standard electron configuration for a ground state (normal state) chlorine atom is 2-8-7. However, when an atom is in an excited state, one or more electrons have moved to a higher energy level. In the case of chlorine, an electron from the second energy level could be excited to the third energy level. So, the electron configuration representing an atom of chlorine in an excited state would be option (2) 2-7-8.

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