To play on the football team, a seventh grader must weigh no more than 110 pounds. your neighbor is in seventh grade and weighs 94 pounds. Write and solve an inequality that represents how much weight your neighbor can gain and still meet the requirement. (: Please help, I'm in Middle School..

Answers

Answer 1
Answer: Let x represent the number of pounds the neighbor can gain and still be able to meet the requirement
No more than is the same as less than or equal to, which is represented by the 
sign.
So the inequality will be:
94 + x ≤ 110
To solve :
94 + x ≤ 110
-94         -94
--------------
x     ≤  16
Check (you should always do this, even if the problem doesn't say so)
x = 0             pick a number that should satisfy the inequality
                     because 0 is a special number (nothing) AND it is very easy to use                          AND it is very easy to plug in, it is an ideal number for check
                     (0 and 1 are the easiest numbers)
94 + 0 ≤ 110
94      ≤  110 √  <-- that's a check sign, NOT square root

Your neighbor can gain no more than 16 pounds to still be able to meet the football team requirement

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A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced, then a second marble is drawnA. What is the probability of selecting a purple marble and then a white marble?
B. What is the probability of selecting 2 white marbles?
C. Is there a greater chance of selecting 2 white marbles in a row or 2 purple marbles in a row? Show your work!

Hallie is trying to win the grand prize on a game show. Should she try her luck by spinning a wheel with 6 equal sections labeled from 1 to 6 and hope she gets a 5, or should she roll two number cubes and hope she gets the same number on both cubes. Show your work?

Answers

A. likely

B. unlikely

C. There is a greater chance in picking to purple marbles because there are less of the white and more purple.

Hallie should spin the wheel because u have a greater chance of landing on a 5 then rolling two number cubes and hoping both number cubes come to equal 5.

two white marbles: probability first is white is \frac{2}{9} probability second is white given that the first is white is \frac{1}{8} again probability both happen is \frac{2}{9}\times \frac{1}{8}

Hope this helps.

What is the rule?: 12, 24, 72, 288,1440

Answers

Answer:

12 x 2 = 24

24 x 3 = 72

72 x 4 = 288

288 x 5 = 1440

The result of each multiplication is being multiplied by the next consecutive number so the pattern is = x2,x3,x4,x5.

Step-by-step explanation:

Boom

A radio station had 300 tickets to a concert. They gave away 5 times as many tickets to listeners as to employees. How many tickets did they give away to employees?

Answers

There has to be 60 tickets because if you divide 300 by 5 and then subtract that number from 300 you get the about for the listeners and the other number is for the employees.

A bus goes from town A to B in an exact time. If the bus goes at the rate of 50km/h, then it will arrive B 42min later than it had to and if it increases its speed 5.5/9 m/sec., it will arrive B 30min earlier. Find:A) The distance between the two towns;
B) The exact time that it takes to arrive town B
C) The speed of the bus(by schedule) for the exact time.

Answers

Let the speed of bus for the exact time = x km/h
the distance between the cities = y km
then the exact time would be, t hours = (y/x) hours

 If the bus goes at the rate of 50km/h, then it will arrive B 42min later,
speed = 50 km/h
42 minutes = 42/60 hours = 7/10 hours = 0.7 hours
time taken = t+0.7
distance = speed
×time
⇒ y = 50×(t+0.7)
⇒ y = 50t + 35     ---------------------(1)

it increases its speed 5.5/9 m/sec, it will arrive B 30min earlier.
5.5/9 m/s = (5.5/9)×(18/5) km/h = 2.2 km/h
30 minutes = 30/60 = 0.5 hour
speed = (x+2.2) km/h
time = (t - 0.5) hours

distance = speed×time
⇒ y = (x+2.2)×(t-0.5)
⇒ y = ((y/t) +2.2)×(t-0.5)               (t = y/x)
⇒ y = y - 0.5 (y/t) + 2.2t - 1.1
⇒ 0.5 (y/t) - 2.2t + 1.1 = 0           (subtracting y from both sides)
⇒ (y/t) - 4.4t - 2.2 = 0                (dividing both sides by 0.5)
⇒ y - 4.4t² - 2.2t = 0                  (multiplying both sides by t)
⇒ 50t + 35 - 4.4t² - 2.2 t = 0      (from equation 1)
⇒ -4.4t² + 35 + 47.8t = 0
⇒ 4.4t² - 47.8t - 35 = 0

solving the quadratic equation, we get t = 11.55 hours
y = 50t + 35 = 612.5 km
x = 612.5/11.55 = 53 km/h

A) 612.5 km
B) 11.55 hours
C) 53 km/h
The Logic Defined:

1 Minute=t, (a unit of time)

Time (By schedule)=nt, (n>0), nt=number of minutes

Metre(s)=m

Speed=s (in metres per minute), s=[distance in metres]/[time in minutes]

Distance=d (in metres), d=[speed in metres per minute]*[time in minutes]

---------------------------------------------

Statement (1):

"If the bus goes at the rate of 50km/h, then it will arrive B 42min later than it had to."

Conclusion 1:

\frac { 50km }{ h } =\frac { 50,000m }{ 60t } =\frac { 2,500m }{ 3t } \n \n \therefore \quad \frac { 2,500m }{ 3t } =nt+42t\n \n \frac { 2,500m }{ 3t } =t\left( n+42 \right)

\n \n 2,500m=3{ t }^( 2 )\left( n+42 \right) \n \n m=\frac { 3{ t }^( 2 )\left( n+42 \right)  }{ 2,500 }

Statement (2):

"
if it increases its speed 5.5/9 m/sec., it will arrive B 30min earlier."

Conclusion 2:

\frac { 5.5m }{ 9\quad seconds } =\frac { 5.5m }{ \frac { 9 }{ 60 } t } =\frac { 110m }{ 3t }

\n \n \therefore \quad \frac { 110m }{ 3t } =nt-30t\n \n \frac { 110m }{ 3t } =t\left( n-30 \right) \n \n 110m=3{ t }^( 2 )\left( n-30 \right)

\n \n m=\frac { 3{ t }^( 2 )\left( n-30 \right)  }{ 110 }

Conclusion 3, because of conclusion 1 and 2:

\frac { 3{ t }^( 2 )\left( n-30 \right)  }{ 110 } =\frac { 3{ t }^( 2 )\left( n+42 \right)  }{ 2,500 } \n \n 7,500{ t }^( 2 )\left( n-30 \right) =330{ t }^( 2 )\left( n+42 \right) \n \n 7,500\left( n-30 \right) =330\left( n+42 \right)

\n \n 7,500n-225,000=330n+13,860\n \n 7,500n-330n=13,860+225,000\n \n 7,170n=238,860\n \n n=\frac { 238,860 }{ 7,170 } \n \n \therefore \quad n=\frac { 7962 }{ 239 }

Therefore,

Time\quad by\quad schedule=\frac { 7962 }{ 239 } t\n \n Approx:\quad 33.3\quad mins

Now we want to find the distance between the two towns, so we say that:

d=\frac { 2,500m }{ 3t } \cdot \left( \frac { 7962 }{ 239 } t+42t \right) \n \n =\frac { 2,500m }{ 3t } \cdot \frac { 18,000 }{ 239 } t

\n \n =\frac { 45,000,000 }{ 717 } m\n \n Approx:\quad 62,761.5\quad metres\n \n In\quad km\quad (approx):\quad 62.761\quad km

So now you want to know how fast the bus has to travel to get to its destination on time...

Use the formula: s=d/t

Therefore:

s=\frac { \frac { 45,000,000 }{ 717 } m }{ \frac { 7962 }{ 239 } t } \n \n Approx:\quad 1,883.9\quad metres\quad per\quad minute

When the sum of 5 and 6 is subtracted from the product of 5 and 6, what's the difference

Answers

(5 + 6) - (5 x 6) = 19 

hope this helps
5+6=11
5x6=30
30-11+19
answer is 19

15x-37=38 what is the answer to that i really really need it

Answers

15x - 37 = 38
      + 37    + 37
15x        = 75
÷15          ÷15
    x       = 5

To check:
15x - 37 = 38
15(5) - 37 = 38
75 - 37 = 38
38 = 38
Add 37 to each side of the equation to get 75. Now get x alone by dividing 15 on both sides. X gets isolated or by itself and 75 divided by 15 is 2,
so your final answer is: x=5.
Hope this helps:)