A recycle machine crushes 175 pounds of cans in 5 minutes. How many pounds of cans will the machine crush in 16 minutes?A) 560
B) 955
C) 1,925
D) 2,805
Answers
*use similar ratios
(175 lbs)/(5 min) = (x)/(16 min)
*find x by multiplying both sides by 16
x = (175 lbs)/(5 min)*(16 min) = 560 lbs
so . . . the answer is . . . A) 560
The answer will be A) 560 because when you divide 175 by 5 is with be 35 then multiply 35 by 16 that will give you 560. Your welcome :)
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The figure below shows triangle STU and some of its transformed images on a coordinate gird which of the four triangles was formed by a translation of triangle STU
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AC and BD are perpendicular bisectors of each other.
=> ABCD is rhombus.
AD = 13
AE = √(13^2 - 12^2) = 5
the perimeter of triangle ADE = 13+12+5 = 30
Answers
Answer:
No, he did not use the radius measure in the formula.
Step-by-step explanation:
i just took the test
Answer:
No, he did not use the radius measure in the formula.
Step-by-step explanation:
Answers
Answer:
2+5
Step-by-step explanation:
When there are two negatives together they combine and turn to a addition sign.
Ex: -(-x)= +x
Hope this helped!
Answers
Answer:
Ok, I'm not the smartest but I think the first one D 2nd = 6,-2 3rd is B 4th= D
and the 5th C
Answer:
Step-by-step explanation:
good
Answers
Answer:
2500g
Step-by-step explanation:
In the Metric Decimal System. Each subunit (to the left) is 10 times higher or 1/10 times lower .
1Kg 1hg 1dag 1g 1dcg 1cg 1 mg
1000g 100g 10g 1g 0.1g 0.01g 0.001g
From the scheme above, we have many relations. The one that answers the question is below followed by a rule of three:
1 kg----1000g
2.5kg-----x
x=2500g
So to go from kilograms to grams, multiply by 1000:
2.5kg*1000= 2500 g
Answer: 2500 g
Answers
Answer:
70.83% entrants will have distances between 150 and 160.
Step-by-step explanation:
This question is incomplete without an attachment; here is the attachment enclosed with the answer.
From the graph attached,
Number of entrants having distances between 150 and 160 feet = 8 + 9 = 17
Number of entrants between 140 and 200 feet = 8 + 9 + 4 + 2 + 1 = 24
Percent of entrants having distance between 150 and 160 feet =
=
= 70.83%
Therefore, 70.83% entrants will have distances between 150 and 160.
Final answer:
To find the percent of entrants with distances between 150 and 160 feet in the frequency polygon, calculate the area of the rectangle between the two values and divide it by the total area under the polygon. Multiply the result by 100 to get the percent.
Explanation:
To find the percent of entrants with distances between 150 and 160 feet, we need to look at the area under the frequency polygon between the two values. Since the frequency polygon represents the distribution of distances, we can estimate the percent by calculating the proportion of the area under the polygon between 150 and 160 feet. First, find the total area under the polygon by adding up the areas of all the rectangles formed by the frequency values and the width of each interval. Then, calculate the area of the rectangle between 150 and 160 feet by multiplying the frequency of that interval by its width. Finally, divide the area of the rectangle by the total area under the polygon and multiply by 100 to get the percent.
Example:
- Total area under the polygon = Sum of (Frequency x Width) = (5 x 10) + (10 x 10) + (30 x 10) + (40 x 10) + (15 x 10) = 500
- Area of rectangle between 150 and 160 feet = Frequency x Width = 40 x 10 = 400
- Percent of entrants with distances between 150 and 160 feet = (Area of rectangle / Total area) x 100 = (400 / 500) x 100 = 80%
Learn more about frequency polygon here:
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