How do u find the approximate radius of a sphere with a volume of 113 cubic centimeters? Explain please
Answers
plug in the numbers 113 cm³=(4/3)*3.14*r³
113 cm³≈4.18*r³
divide 113 by 4.18
27≈r³
∛27 to get r≈3 cm
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The sum of remainders obtained when x3+(k+8)x +k is divided by x-2 and when it is divided by x+1 is 0 fine the value of k
Answers
you know this because when you look at the point (25,75) you should automatically think (x,y) where "x" is what you plug in to the line to get "y" which is your output.
so that being said if you plug in 25 ...
y= 3(25)
you want your answer to be 75. if it is then this point exist on the line if it isnt then it does not exist on this line.
in this case 3*25 does in fact equal 75 so the point (25,75) exist on the line y=3x
Answers
=-3(-w-u)+-1(-5+w)
=-3(-w-u)+(-1)(-5)+-1w
=-3(-w-u)+5+-w
Distribute
=(-3)(-w)+(-3)(-u)+5+-w
=3w+3u+5+-w
Combine like terms
=3w+3u+5+-w
=(3u)+(3w+-w)+(5)
=3u+2w+5
:)
Answers
Answer:
(27x3+9x2-3x-10)/(3x-2)
Final result :
9x2 + 9x + 5
Step by step solution :
Step 1 :
Equation at the end of step 1 :
Step 2 :
Equation at the end of step 2 :
Step 3 :
27x3 + 9x2 - 3x - 10
Simplify ————————————————————
3x - 2
Checking for a perfect cube :
3.1 27x3 + 9x2 - 3x - 10 is not a perfect cube
Answers
Answer:
hello :
the perimeter is : p = 2 ( w + l )
The area is : A= w ×l w : width l : length w ?
2 ( w + l ) = 76
w ×l = 336
you have the system :
w + l = 38 ...(1)
w ×l = 336...(2)
by (1) : l = 38 - w
subst in (2) : w ( 38 - w ) =336
38w - w²= 336
w² - 38w +336 = 0
delta = b² -4ac when : a = 1 and b= -38 c = 336
delta = (-38)² -4(1)(336) = 1444 - 1344 = 100 = 10²
w1 = (38-10)/2 = 14( the shorter sides length)
w2 = (38+10)/2 = 24( refused )
The shorter side's length of the rectangle is 24 inches. This is determined by solving the system of equations derived from the area (336 square inches) and perimeter (76 inches) constraints, resulting in a quadratic equation with two possible solutions, and the shorter side being 24 inches.
- To find the shorter side's length of a rectangle with an area of 336 square inches and a perimeter of 76 inches, we'll use a system of equations.
- Let's denote:
- Length of the rectangle as L (in inches).
- Width of the rectangle as W (in inches).
- We have two pieces of information:
- The area of the rectangle is 336 square inches:
- L * W = 336
- The perimeter of the rectangle is 76 inches:
- 2L + 2W = 76
- Now, we can solve this system of equations for L and W.
- First, isolate L in the perimeter equation:
- 2L + 2W = 76
- 2L = 76 - 2W
- L = (76 - 2W) / 2
- L = 38 - W
- Now, substitute this expression for L into the area equation:
- (38 - W) * W = 336
- Expand and rearrange the equation:
- 38W - W^2 = 336
- Move all terms to one side to create a quadratic equation:
- W^2 -
- Now, we can solve this quadratic equation for W. We can either factor it or use the quadratic formula. In this case, let's use the quadratic formula:
- W = (-b ± √(b² - 4ac)) / (2a)
- Where:
- a = 1 (coefficient of W^2)
- b = -38 (coefficient of W)
- c = 336
- W = (-(-38) ± √((-38)² - 4 * 1 * 336)) / (2 * 1)
- W = (38 ± √(1444 - 1344)) / 2
- W = (38 ± √100) / 2
- W = (38 ± 10) / 2
- Now, we have two possible values for W:
- W = (38 + 10) / 2 = 48 / 2 = 24 inches (shorter side)
- W = (38 - 10) / 2 = 28 / 2 = 14 inches (longer side)
- So, the shorter side's length is 24 inches.
For more questions on perimeter -
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5 times 2 over 3 equals s
Answers
Multiply 3 to the numerator and keep the denominator:
5 * 3 = 15
15/2
7.5 or 7 1/2
20 + g = 25
Answers
20+5=25
Hope its correct ad definitely hope it helps:)