You read that a statistical test at the a 0. 01 level has probability 0. 14 of making a type ii error when a specific alternative is true. What is the power of the test against this alternative?

Answers

Answer 1
Answer:

The power of the test against the specific alternative is given by 1 minus the probability of making a Type II error. Therefore, the power is 0.86= 86%

In statistical hypothesis testing, the power of a test is the probability that it correctly rejects a null hypothesis when a specific alternative hypothesis is true. In this case, we are given that the test has a significance level of α = 0.01, which means that the test rejects the null hypothesis if the probability of obtaining the observed result, or one more extreme, under the null hypothesis is less than 0.01.

However, we also know that when a specific alternative hypothesis is true, the test has a probability of making a Type II error of 0.14. This means that there is a 14% chance that the test fails to reject the null hypothesis, even though the alternative hypothesis is true.

Therefore, the power of the test against this specific alternative hypothesis is given by 1 minus the probability of making a Type II error, which is:

Power = 1 - P(Type II error) = 1 - 0.14 = 0.86

So, the power of the test against the specific alternative hypothesis is 0.86 or 86%. This means that when the alternative hypothesis is true, the test correctly rejects the null hypothesis 86% of the time.

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Which relationships hold true for the sum of the magnitudes of vectors u and v, which are perpendicular? a. ||u+v||=||u||+||v|| b. ||u+v||=sq rt(||u||^2+||v||^2) c. ||u+v||

Answers

The perpendicular are B) ||u+v|| = sqrt ||u||^2 + ||v||^2 and D) ||u+v|| less than ||u||+||v||

We have given that,

The relationships hold true for the sum of the magnitudes of vectors u and v,

We have determined which are perpendicular.

What is the magnitude of the vector?

The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.

B) ||u+v|| = sqrt ||u||^2 + ||v||^2

AND

D) ||u+v|| less than ||u||+||v||

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it is

B) ||u+v|| = sqrt ||u||2 + ||v||2

AND

D) ||u+v|| less than ||u||+||v||

The data set represents a progression of hourly temperature measurements. Use a graphing calculator to determine the quadratic regression equation for this data set.I've tried all of these answers but none of them seemed correct

Answers

Answer:

b

Step-by-step explanation: I had this question before

Answer:

b

Step-by-step explanation:

Given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line.

Answers

Here, 2x - 3y - 5 = 0

3y = 2x - 5

Divide the equation by 3, 
y = 2/3x - 5/3

Compare it with,y = mx + c
So, slope (m) = 2/3

In short,Your Answer would be: 2/3

Hope this helps!

Answer:

2/3

Step-by-step explanation:

Find the distance between the points (5, 7) and (1, 10).

Answers

Answer:

I think it's 2,5 but i'm not really sure

Step-by-step explanation:

Highschool surds maths

Answers

\cfrac{8-√(18)}{√(2)}~~ = ~~a+b√(2) \n\n[-0.35em] ~\dotfill\n\n \cfrac{8-√(18)}{√(2)}\implies \cfrac{8-√(18)}{√(2)}\cdot 1\implies \cfrac{8-√(18)}{√(2)}\cdot \cfrac{√(2)}{√(2)}\implies \cfrac{(8-√(18))(√(2))}{(√(2))(√(2))}

\cfrac{8√(2)-√(18)\cdot √(2)}{√(2^2)}\implies \cfrac{8√(2)-√(18\cdot 2)}{2}\implies \cfrac{8√(2)-√(36)}{2} \n\n\n \cfrac{8√(2)-6}{2}\implies \cfrac{8√(2)}{2}-\cfrac{6}{2}\implies 4√(2)-3\implies -3+4√(2) \qquad \begin{cases} a=-3\n b=4 \end{cases}

What is the value of -4 + 91 + 72?

Answers

Answer:

159

Step-by-step explanation:

-4+91=87

87+72=159

Answer:

159

Step-by-step explanation: