PHYSICS HIGH SCHOOL

A motor with a power of 7.0 × 104 watts lifts a loaded elevator to a height of 20.00 meters for 40 seconds. What is the force exerted by the motor on the elevator?

Answers

Answer 1

Answer:

$1.4\cdot 10^5 N$

Explanation:

First of all, we can find the work done as follows:

$W=Pt$

where P is the power and t is the time taken. In this problem, $P=7.0\cdot 10^4 W$ and $t=40 s$ , so the work done is

$W=Pt=(7.0\cdot 10^4 W)(40 s)=2.8\cdot 10^6 J$

The work done is equal to the force applied F times the displacement d:

$W=Fd$

since we know d=20.0 meters, we can re-arrange the equation to find the force exerted:

$F=(W)/(d)=(2.8\cdot 10^6 J)/(20.0 m)=1.4\cdot 10^5 N$

Answer 2

Answer:

Answer:

C) 1.4 × 105 newtons

Explanation:

Correct answer on plato/edmentum

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