Triangle UVW is drawn with vertices at U(−1, 1), V(0, −4), W(−4, −1). Determine the coordinates of the vertices for the image, triangle U′V′W′, if the preimage is rotated 90° counterclockwise

Answers

Answer 1

Answer:

The coordinates of the vertices for the image, triangle U′V′W′, if the preimage is rotated 90° counterclockwise include the following:

U' = (1, 1).

V' = (-4, 0).

W' = (-1, 4).

What is a rotation?

In Mathematics and Geometry, the rotation of a point 90° about the center (origin) in a counterclockwise (anticlockwise) direction would produce a point that has these coordinates (-y, x).

By applying a rotation of 90° counterclockwise to the vertices of triangle UVW, the coordinates of the vertices of the image are as follows:

(x, y) → (-y, x)

Ordered pair U = (-1, 1) → Ordered pair U' = (1, -(-1)) = (1, 1).

Ordered pair V = (0, -4) → Ordered pair V' = (-4, -(0)) = (-4, 0).

Ordered pair W = (-4, -1) → Ordered pair W' = (-1, -(-4)) = (-1, 4).

Read more on rotation here: brainly.com/question/28854313

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Choose the correct simplification of the expression (3x − 6)(2x2 − 4x − 5).6x3 − 24x2 + 9x − 30
6x3 + 9x + 30
6x3 − 24x2 + 9x + 30
6x3 − 24x2 + 39x + 30

Answers

Answer:

Option 3rd is correct

$6x^3-24x^2+9x+30$

Step-by-step explanation:

Given the expression:

$(3x-6)(2x^2-4x-5)$

Multiply the first term of the first expression with second expression and second term of the first expression with second expression we have;

$3x(2x^2-4x-5)-6(2x^2-4x-5)$

using distributive property we have;

$6x^3-12x^2-15x-12x^2+24x+30$

Combine like terms we have;

$6x^3-24x^2+9x+30$

therefore, the correct simplification of the given expression is, $6x^3-24x^2+9x+30$

The answer is C: 6x^3 - 24x^2 + 9x + 30

Write the equation of the line in standard form that passes through the point (1, 7) and has a slope of 2.

Answers

Answer:

y=2x+5

Step-by-step explanation:

The diagram shows three squares that are joined at vertices to form a right triangle. Which statement is true? A. The sum of the areas of Square N and Square L is equal to the area of Square K.
B. The sum of the areas of Square N and Square L is greater than the area of Square K.
C. The sum of the areas of Square N and Square K is equal to the area of Square L.
D. The sum of the areas of Square N and Square K is less than the area of Square L.

Answers

The sum of the areas of Square N and Square L is equal to the area of Square K and this can be determined by using the Pythagorean theorem.

Given :

The diagram shows three squares that are joined at vertices to form a right triangle.

The following steps can be used in order to determine which statement is true:

Step 1 - The Pythagorean theorem can be used in order to determine which statement is true.

Step 2 - According to the Pythagorean theorem, the sum of the square of the shorter sides is equal to the square of the longer side.

Step 3 - So, from the above steps, it can be concluded that the sum of the areas of Square N and Square L is equal to the area of Square K.

Therefore, the correct statement is given by option A).

For more information, refer to the link given below:

brainly.com/question/25277954

answer:

a) the sum of the areas of square n and square l is equal to the area of square k.

step-by-step explanation:

https://quiz izz.com/admin/quiz/5ecffa4789713d001cea9223/2019-8th-grade-staar

good luck :)

i hope this helps

have a nice day!

Determine the slope of the line that passes through each pair of points.1.(5,1) and (2,7)
2.(5,3)and(-2,3)

Answers

$1.)\n\n(5,1) \ \ and \ \ (2,7)\n\nFirst \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \n \nm=( 7-1)/(2-5) = (6)/(-3)=-2 \n \n Use \ point \ form \ of \ a \ line\ with \ one \ point: \n \n y-y_(1) =m(x-x _(1)) \n \nm=-2 , \ \x_(1)=5, \ \ y_(1)=1 \n \ny-1 = -2(x-5 ) \n\ny=-2x+10+1 \n \ny=-2x+11$

$2.)\n\n(5,3)\ \ and \ \ (-2,3)\n\nFirst \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \n \nm=( 3-3)/(-2-5) = (0)/(-7)=0\n \n Use \ point \ form \ of \ a \ line\ with \ one \ point: \n \n y-y_(1) =m(x-x _(1)) \n \nm=0 , \ \x_(1)=5, \ \ y_(1)=3 \n \ny-3 = 0\cdot (x-5 ) \n\ny-3=0 \n \ny=3$

The Drama Club is showing a video of their recent play. The first showing begins at 3:45 p.M. The second showing is scheduled at 6:25 p.M. With a 1 2 −hour break between the showings. How long is the video in hours and minutes? Pt. 2 The second showing started 20 minutes late. Will the second showing be over by 8:45 p.M.?

Answers

Answer:

the movie is 2 hours and 10 min long

no it will not be over by 8:45pm

Step-by-step explanation:

if the movie begins at 3:45 pm and the next begins at 6:25pm with a half hour break you need to take 30 min from 6:25 to see what time the movie ended which is 5:55pm then you figure the time between 3:45pm and 5:55pm which is 2hours and 10 min.

since thw movie is starting 20 min late from 6:25pm that is now a start time of 6:45pm if the movie is 2hours and 10 min it will not be over by 8:45pm since that is only 2 hours

• a baseball player went up to bat 250 times in a season. he hit the ball 100 times. find the rate of balls hit to times at bat. express as a simplified fraction. 0 } 0 2 5 о

Answers

Answer:

2 / 5

Step-by-step explanation:

He hit 100 times out of 250 times.

100 / 250

= (100 /50) / (250 /50)

= 2 / 5

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