The three basic principals of training that are the foundation for developing a successful personal fitness program are ________________ A. overload , progression and specificity B. Endurance , strength and agility C. overload , frequency and progression D. cardiovascular training , strength training and flexibility

Answers

Answer 1
Answer: Overload, progression and specificity are the three basic principals of training that are the foundation for developing a successful personal fitness program.
Answer 2
Answer:

Final answer:

The three basic principles of a successful personal fitness program are overload, progression, and specificity. This incorporates increasing exercise stress (overload), progressing exercise intensity gradually (progression), and aligning exercises with desired fitness goals (specificity).

Explanation:

The three basic principles of training that lay the groundwork for developing a successful personal fitness program are overload, progression, and specificity. Overload refers to increasing the amount of exercise or stress placed on the body to promote adaptation and improve fitness. Progression implies the gradual increase of the exercise intensity, frequency, or time, ensuring that the body is constantly challenged but not overworked. Specificity denotes the requirement for exercises to be specific to the muscles or fitness component that one desires to improve.

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HELP!!!! FAST!!!! 20 POINTS!!!! You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equalmass (3,000 kg each) were involved in a rear-end accident at a stop sign. Here is what you know:
• Truck 1 started from rest at the top of a 22-meter hill and coasted toward the intersection.
.
Truck 2 was on a flat stretch of road at the bottom of the hill directly in front of Truck 1.
At the bottom of the hill, Truck 1 was going 20 m/s; Truck 2 was going 35 m/s.
.
There were no skid marks left by Truck 2. The collision occurred at the stop sign where Truck 2 had
stopped
• After the collision, both trucks moved together in the same direction at 10 m/s before slowly rolling
to a stop.
You must now push Truck 2, using 1,000 N of force, 8 meters off to the side of the road so no one
else gets hurt.
1. What was the potential energy of Truck 1 at the top of the hill? 2. What was the kinetic energy of each truck before the began braking? 3. A. How much energy did truck 1 lose from the top to the bottom of the hill? B. Where do you suppose that energy went?

Answers

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1,  = = 20 m./s

Velocity of the truck 2, = 35 m./s

1. Kinetic energy of the truck 1:

Kinetic energy of the truck 2:

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height =  

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

\

Final answer:

The potential energy of Truck 1 at the top of the hill is 646,800 J. The kinetic energy of each truck before they began braking is 600,000 J for Truck 1 and 3,712,500 J for Truck 2. The energy lost by Truck 1 from the top to the bottom of the hill is 646,800 J, which is converted into kinetic energy and transferred to Truck 2 during the collision.

Explanation:

1. The potential energy of Truck 1 at the top of the hill can be calculated using the formula PE = mgh, where m is the mass of the truck, g is the acceleration due to gravity, and h is the height of the hill. Plugging in the values, PE = (3,000 kg)(9.8 m/s^2)(22 m) = 646,800 J.

2. The kinetic energy of each truck before they began braking can be calculated using the formula KE = 0.5mv^2, where m is the mass of the truck and v is the velocity. For Truck 1, KE = (0.5)(3,000 kg)(20 m/s)^2 = 600,000 J. For Truck 2, KE = (0.5)(3,000 kg)(35 m/s)^2 = 3,712,500 J.

3.A. The energy that Truck 1 lost from the top to the bottom of the hill can be calculated by subtracting the potential energy at the top from the kinetic energy at the bottom. Therefore, energy lost = PE(top) - KE(bottom) = 646,800 J - 0 J = 646,800 J.

3.B. The energy is converted into kinetic energy and transferred to Truck 2 when they collide. The collision between the two trucks results in an increase in kinetic energy for Truck 2 and a decrease in kinetic energy for Truck 1.

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In a paper on the catalytic activity of an enzyme, in which section would you find detailed information on how the enzyme was prepared and handled in the experiment?A. Discussion
B. Materials and Method
C. Abstract
D. Introduction

Answers

It's B. Materials and Method.

Photosynthesis plays an important role in supplying energy to living things. Considering what the products of photosynthesis are, What is another way in which photosynthesis is vital to life?

Answers

Humans need Oxygen and the process of photosynthesis produces oxygen 

Your _____ indicates that the relative humidity is very high. Rain probably _____ occur. anemometer; will anemometer; won't hygrometer; will hygrometer; won't

Answers

The answer is hygrometer, will.

Your hygrometer indicates that the relative humidity is very high. Rain probably will occur. 
Hygrometer is an instrument used for measuring the relative humidity in the atmosphere. If the relative humidity is very high, then it rain will probably occur and vice versa.
Anemometer is an instrument used for measuring wind speed, thus it cannot be the right answer.

For this assignment from earth science and earth’s weather and climate unit you have to complete the statements shown above.


Answer: Your Hygrometer indicates that the relative humidity is very high. Rain probably will occur.


I hope this helps, Regards.

Use the codon chart to convert this sequence into an amino acid: UCU-CGA-GCC-GUU-GGG-UGA

Answers

The answer is Ser-Arg-Ala-Val-Gly-STOP


It is known that three nucleotide bases on mRNA are called codon and that each codon codes for the specific amino acid. According to the genetic code chart, the following mRNA sequence will code for the following amino acid sequence:

mRNA sequence:       UCU CGA GCC GUU GGG UGA

Amino acid sequence: Ser   Arg    Ala   Val    Gly   STOP

This is late, sorry about that but for future people the answer should be:

Serine (ser), arginine (arg), alanine (ala), valine (val), glycine (gly), stop

According to the de-coding chart for this lab.

The range of cells receiving the content of copied cells is called the ____.

Answers

The range of cells receiving the content of copied cells is called the destination area. The correct option is a.

What is a cell?

The smallest unit of life is a cell. It is composed of biomolecules. Every living thing is composed of several cell units. Different sorts of creatures contain various types of cells.

The cell divides to form the other cell. This process if called cell division. Cell division occurs during mitosis. All eukaryotic cells go through the process.

There are four stages to the process. The cell divides during the procedure. A daughter cell that is identical to the parent cell is created.

The destination region refers to the set of cells that will get copied cell content. The cell copies the full contest for another cell.

Thus, the correct option is a. destination area.

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The question is incomplete. Your most probably complete question is given below:

a. destination area.

b. final cell

c. receiving range

d. receiver cell

The range of cells receiving the content of copied cells is called the "destination area." The cells are receiving the content so that would be the copied cells destination