Solve the ecuation: $x=\frac{[x]+2012}{\{x\}+2013}$

where [x] is the whole part of the number x and {x} is the fractional part of the number x.

Answers

Answer 1

Answer: Scrii x = [ x ] + { x } ;
Folosesti proprietatea fundamentala a proportiilor;
Apoi, exprimi [ x ] in functie de { x }, si obtii ca :
[ x ] = ( 2012 - { x } ^2 - 2013{ x } ) / ( 2012 + { x } ) ;
Fie { x } = t ∈ [ 0 , 1 ) ;
Obtii ca [ x ] = - t - 1 + 4024 / ( t + 2012 ) ;
Stim ca [ x ] ∈ Z ;
Atunci t = 0 sau t = 2012 ;
Convine numai t = 0 => x = [ x ] ;
Ecuatia originala va avea solutia 1.

Bafta!

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Help me real quick. please.! !!!

Answers

Y=x times x/ x squared plus 1

y=x²+1

hope this helps :)

I have no idea how to use this site yet, so I'm just gonna put my algebra problem here. Thanks for any help!Graph system of equation:
x-2y=2
3+y=6

Answers

I have a hard times putting graphs so I'll just put the answers and say how to graph with paper
so we notice that if we solve the second equation (3+y=6), we get a value for y and no value for x so just draw a horizonal line at the point 3 on the y axis

then make the second equation into slope inercept form y=mx+b
x-2y=2
2y-x=-2
2y=x+2
y=1/2x+1
just put in values for x and get y values, then plot points and get line
find where the line inercepts/crosses the first line (3+y=6) and that is the solution

OR

so a the solution is when both equations are true so just assume both are true and solve for x and y

x-2y=2
3+y=6

first of all the second equation is easy
3+y=6
subtract 3 from both sides
y=3

so we subsitute 3 for y in first equation
x-2(3)=2
x-6=2
add 6 to both sides
x=8
y=3
the solution is the point (8,3)

Evaluate the floor function f(x) = ⌊x⌋ for the given input values. f(2) = f(6.8) = f(–3.3) =

Answers

Answer:

f(2) = 2 , f(6.8) = 6 and f(-3.3) = -4.

Step-by-step explanation:

We are given,

Floor function is $f(x)=\left \lfloor x \right \rfloor$ .

That is, the function have value,

$f(x)=n$ when $n\leq x< n+1$ .

So, we get,

For $2\leq x< 3$ , we have f(2) = 2

For $6\leq x< 7$ , we have f(6.8) = 6

For $-4\leq x< -3$ , we have f(-3.3) = -4

Thus, we have the values,

f(2) = 2 , f(6.8) = 6 and f(-3.3) = -4.

Answer:

The correct answers on edge .. yw have a great dayy

Step-by-step explanation:

f(2) =

f(6.8) =

f(–3.3) =

-4

about 60% of the normal human beings body weight is composed is water. How much of a 125 pound person is water weight?

Answers

60% of weight 60%=0.6 'of' means multipy 60% of 125 means 0.6 times 125=75 75 pounds

u do .6 x 125 = 75
Hope it right! and it helps u out!

What is the completely factored form of f(x) = 6x3 – 13x2 – 4x + 15?(x + 1)(6x2 – 19x + 15)
(x + 1)2(2x – 3)
(x + 1)(3x – 2)(5x – 3)
(x + 1)(2x – 3)(3x – 5)

Answers

We have to determine the complete factored form of the given polynomial

$f(x)=6x^3-13x^2-4x+15$ .

Let x= -1 in the given polynomial.

So, $f(-1)= 6(-1)^3-13(-1)^2-4(-1)+15 = -6-13+4+15 = 0$

So, by factor theorem

(x+1) is a factor of the given polynomial.

So, dividing the given polynomial by (x+1), we get quotient as $6x^2-19x+15$ .

So, $6x^3-13x^2-4x+15$ = (x+1) $6x^2-19x+15$ .

= $(x+1)(6x^2-10x-9x+15)$

= $(x+1)[ 2x(3x-5)-3(3x-5)]$

= $(x+1)(2x-3)(3x-5)$ is the completely factored form of the given polynomial.

Option D is the correct answer.

Answer:

D) (x + 1)(2x – 3)(3x – 5)

Step-by-step explanation:

Nina wants to download games for her video game console. Older games cost 100 points and new releases cost 200 points to use. The equation 100a+200b=4000, where a is the number of der games and b is the number of new releases, models the situation. How many older games can she download if she downloads 4 new games? 5 new games?

Answers

Replace b with 4: 100a+200(4)=4000. 100a+800=4000. Combine like terms: 100a=3,200. Get the unknown by itself: A=32. She can download 32 old games if she downloads 4 new ones. Same steps: 100a+200(5)=4000. 100a+1000=4000. 100a=3000. A=30. She can download 30 old games if she downloads 5 new ones. :)

Final answer:

If Nina downloads 4 new games, she can additionally download 16 older games. If she downloads 5 new games, she can download 15 older games.

Explanation:

The problem can be solved by substituting the number of new games into the equation and solving for 'a' which represents the number of older games.

For 4 new games, the equation becomes 100a+200*4=4000. Solving this, we get 'a' as 16. Hence, Nina can download 16 older games.

For 5 new games, the equation becomes 100a+200*5=4000. Solving this, we get 'a' as 15. Hence, Nina can download 15 older games when she downloads 5 new games.