CHEMISTRY HIGH SCHOOL

Metals lose electrons under certain conditions to attain a noble-gas electron configuration. how many electrons must be lost by the element mg?

Answers

Answer 1
Answer: a noble gas electron configuration follows the octet rule in which the configuration is composed of electrons. the charge of a neutral atom is zero. meanwhile, a magnesium atom bears a + 2 charge which means in order to be stable, it has to gain two electrons to be stable.
Answer 2
Answer:

Explanation:

It is known that metals are the species which easily lose an electron to acquire stability.

For example, atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2.

Hence, in order to attain stability it will readily lose two electrons. As a result, it will form Mg^(2+) ions.

Thus, we can conclude that 2 electrons must be lost by the element Mg.

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The most stable group of elements on the periodic table is the?A) halogens
B) noble gases
C) alkali earth metals
D) alkaline earth metals

Answers

The most stable because they can contain the most valence electrons in their outer shell. The correct option is B.

Thus, The group of elements on the periodic table known as noble gases, commonly referred to as inert gases, is thought to be the most stable.

They are radon (Rn), krypton (Kr), xenon (Xe), neon (Ne), helium (He), and argon (Ar). Noble gases are extremely stable and less likely to combine chemically with other elements because they contain entire valence electron shells.

Their full electron configurations, which result in low reactivity, are the cause of this stability.

Thus, The most stable because they can contain the most valence electrons in their outer shell. The correct option is B.

Learn more about Valence electrons, refer to the link:

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B) Noble gases
Most stable because they have the maximum number of valence electrons their outer shell can hold

If the system 2CO(g)+O2(g) 2CO2(g) has come to equilibrium and then more CO(g) is added,

Answers

If more CO is added the reaction will shift to the right and produce more products to maintain the equilibrium constant. This can be explained through Le Chatlier principles. I hope this helps. Let me know if anything is unclear.

If you determined that the volume of a silver bar is 100.mL,how many atoms of silver would be in the bar? The density of silver is 10.5g/mL. 271

Answers

There are approximately 5.86 \ * \ 10^(24) atoms of silver in the 100 mL silver bar.

To determine the number of atoms in a silver bar, you can follow these steps:

Calculate the mass of the silver bar:

Mass (g) = Volume (mL) x Density (g/mL)

Mass = 100 mL x 10.5 g/mL = 1050 g

Calculate the molar mass of silver (Ag):

The molar mass of silver (Ag) is approximately 107.87 g/mol.

Calculate the number of moles of silver in the bar:

Moles = Mass (g) / Molar Mass (g/mol)

Moles = 1050 g / 107.87 g/mol ≈ 9.73 moles

Calculate Avogadro's number:

Avogadro's number is approximately 6.022\ * \ 10^(23) atoms/mol.

Calculate the number of silver atoms in the bar:

Number of atoms = Moles x Avogadro's number

Number of atoms = 9.73\ moles \ * \ 6.022 \ * \ 10^(23) \ atoms/mol \approx 5.86 \ * \ 10^(24) atoms

Thus, there are approximately 5.86 \ * \ 10^(24) atoms of silver in the 100 mL silver bar.

For more such questions on silver:

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10.5 g/mL * 100 mL = 1050 g of silver

1050 g silver * ( 1 mol silver/107.8682g) = 9.734 mol silver

9.734 moles silver * 6.022E23 atoms/ mole = 5.861E24 atoms of silver

Where molar mass if silver = 107.8682g/mol
Avogadro's number = 6.022E23 atoms/moles

A 133.8-gram sample of bronze was 10.3% tin by mass. Determine the total mass of tin in the sample.

Answers

You just need to multiply the total mass by the decimal value of the part that is tin. 133.8*0.103=13.8g (following the rules of significant figures).

What is the van't hoff factor of C7H7NO?

Answers

Answer:

i = 1

Explanation:

Van't Hoff factor (i) is explained as the number of ions dissolved in solution.

It is needed to determine colligative properties which depend on the amount of solute.

C₇H₇NO is an organic compound → benzamide

All the organic compound have 1, as Van't Hoff factor.

In order to predict i, you consider ionic salts. For example:

AlCl₃

CaCl₂

NH₄NO₃

When you dissociate them, you determine i:

AlCl₃ →  Al³⁺  +  3Cl⁻                   i =4

CaCl₂ →  Ca²⁺  +  2Cl⁻            i = 3

NH₄NO₃  →  NH₄⁺  +  NO₃⁻        i =2

In a hydrocarbon-based combustion reaction, what two molecules are most likely to be products?

Answers

The two molecules that are always produced in combustion reactions are water (H₂O) and carbon dioxide (CO₂).

I hope this helps.  Let me know if anything is unclear.
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