4Fe + 3O2à 2Fe2O3 is a balanced equation. What is the charge on each iron (Fe) ion in hematite (Fe2O3)?A. +1
B. +2
C. +3
D. +4

Answers

Answer 1
Answer:

Answer: The correct answer is Option C.

Explanation:

Oxidation state is the number which is assigned to an element when it gains or looses electrons. If the element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

We take the oxidation state of iron atom be 'x'.

Oxidation state of oxygen atom = -2

Evaluating the oxidation state of iron atom in Fe_2O_3:

2x+3(-2)=0\n\nx=+3

Hence, the correct answer is Option C.

Answer 2
Answer: +3 I would say, in Fe2O3. O3=-6 Fe=+6 balances to 0


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Answers

the answer is in the picture.

Which is true about the dissolving process in water?

Answers

Water molecules that move throughout the solute.
When you put a solvent in the water, the water molecule will start to surrounds every small particles of the solute to dissolve it. solute is not actually gone, it just mixes with the water molecules.

If you were asked to convert 25 kg to the unit mg, which of the following would be the first fraction used in the conversion?

Answers

divide twenty-five by one thousand

During diffusion, when the concentration of molecules on both sides of a membrane is the same, the molecules will (1 point).

move across the membrane to the outside of the cell.
stop moving across the membrane.
continue to move across the membrane in both directions.
move across the membrane to the inside of the cell.

Answers

During the diffusion process, when the concentration of molecules on both sides of a membrane is the same, the molecules will continue to move across the membrane in both directions. 

will continue to move across the membrane in both directions.  

i hope this helps you ( c )

have a wonderful day

~hailey lee~

ure carbon tetrachloride, CCl4, freezes at-23.00 ⁰C and has a kf of 29.8⁰C/m. The latest lot has a freezing point of-23.43⁰C. What is the molality of impurities in thesolvent? If the impurity is largely hexachloroethane, C2Cl6, how many grams of this impurity arethere per kg of CCl4?Once the mass of the impurity is determined, calculate the mass % purity:

Answers

Answer:

a) grams of this impurity per kg of CCl4 = 3.416 g/kg of solvent.

b) mass purity % = 99.66%

Explanation:

Given, the freezing point of pure CCl₄ = - 23°C

Presence of impurities lowers the freezing point to - 23.43°C

The freezing point depression constant, Kբ = 29.8°C/m

The lowered freezing point is related to all the parameters through the relation

ΔT = i Kբ × m

where ΔT is the lowered freezing point, that is, the difference between freezing point of pure substance (T⁰) and freezing point of substance with impurities (T).

i = Van't Hoff factor which measures how much the impurities influence/affect colligative properties (such as freezing point depression) and for most non-electrolytes like this one, it is = 1

Kբ = The freezing point depression constant = 29.8°C/m

m = Molality = ?

T⁰ - T = i Kբ m

- 23 - (-23.43) = 1 × 29.8 × m

m = 0.43/29.8 = 0.0144 mol/kg

Them we're told to calculate impurity of the CCl₄

we convert the Molality to (gram of solute)/(kg of solvent) first

Solute = C₂Cl₆

Molar mass = 236.74 g/mol

So, (molality × molar mass) = (gram of solute)/(kg of solvent)

(gram of solute)/(kg of solvent) = 0.0144 × 236.74 = 3.416 (gram of solute)/(kg of solvent)

Mass purity % = (1000 g of pure substance)/(1000 g of pure substance + mass of impurity in 1000 g of pure substance)

1000 g of solvent contains 3.416 grams of impurities

Mass purity % =100% × 1000/(1003.416)

Mass purity % = 99.66 %

The acid-dissociation constant, Ka, for benzoic acid is 6.5 × 10-5. Which will you use to calculate the base-dissociation constant, Kb, for the conjugate base of benzoic acid?

Answers

Answer:

The base-dissociation constant, Kb,for the conjugate base of benzoic acid is :

K_(b)=1.54* 10^(-10)}

Explanation:

The product of acid dissociation constant and base dissociation constant is equal to the water dissociation constant.The general formula for the reaction is:

K_(w)=K_(a)K_(b)

For the acid dissociation reaction:

HA + H_(2)O\rightleftharpoons H^(+)+A^(-)

The conjugate base for the acid is A-

The acid is HA . and its Ka is given.

The value of Kw is fixed  at a given  temperature , which is equal to:

K_(w)=10^(-14)

K_(a)=6.5* 10^(-5)

K_(b)=(10^(-14))/(6.5* 10^(-5))

K_(b)=1.54* 10^(-10)}

Answer:

Ka*kb=kw

Explanation:Got it right