The steps in writing f(x) = 18x + 3x2 in vertex form are shown, but a value is missing in the last step. Write the function in standard form. f(x) = 3x2 + 18x Factor a out of the first two terms. f(x) = 3(x2 + 6x) Form a perfect square trinomial. f(x) = 3(x2 + 6x + 9) – 3(9) Write the trinomial as a binomial squared. f(x) = 3(x + ______)2 – 27

Answers

Answer 1

Answer:

To find the vertex form of parabola $y=a(x-x_0)^2+y_0$ given in almost standard form $y=ax^2+bx+c,$ were written following steps:

1. Write the function in standard form:

$y=3x^2+18x.$

2. Factor a out of the first two terms:

$y=3(x^2+6x).$

3. Form a perfect square trinomial:

$y=3(x^2+6x+9-9)=3(x^2+6x+9)-3\cdot 9.$

4. Write the trinomial as a binomial squared:

$y=3(x+3)^2-27.$

The vertex is (-3,-27).

Answer: missing value is 3

Answer 2

Answer:

The function in vertex form is y = 3( x+3)² -9

What is a Function ?

A function is a mathematical statement formed for relating a dependent and in independent variable.

It is given that

f(x) = 18x +3x²

To write it into vertex form

The standard vertex form is given by

y =a(x- h)² +k

y = 18x +3x²

y = 3(x² +6x)

y = 3 (x² + 2.3 x + 9) -9

y = 3( x+3)² -9

Therefore in vertex form the function is y = 3( x+3)² -9

To know more about Function

brainly.com/question/12431044

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