Which strategies can be used to solve this problem? Kathleen invited 28 people to her party. She plans to seat 8 people at the dining room table. She will put the rest at round tables with 4 people at each table. What is the fewest number of round tables that Kathleen needs so that each guest will have a seat? Choose all answers that are correct. A. Draw a diagram. Eight people at 1 table, 4 people at round table, 4 people at round table, 4 people at round table, 4 people at round table, 4 people at round table. Count the number of round tables. B. Use logical reasoning. Start with 28 people, subtract 8 people who will sit at the dining room table, that leaves 20 people. Keep subtracting 4 people until you get to 0. Count how many times you subtracted 4 people. C. Translate into an equation. 28 – 8 + 4 + 4 = t D. Work backward. There are 28 people coming to the party. There is one dining table, so subtract 1. Now figure out how many round tables there are and subtract that number.

Answers

Answer 1

Answer: I'm guessing A because 28-8=20 and 20/4=5 round tables needed

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If a sequence is defined recursively by f(0) = 2 andf(n +1) = -2f(n) + 3 for n ≥ 0, then f(2) is equal to

Answers

If you would like to know how much is f(2), you can calculate this using the following steps:

f(0) = 2
f(n+1) = - 2 * f(n) + 3
f(1) = - 2 * f(0) + 3 = - 2 * 2 + 3 = - 4 + 3 = - 1
f(2) = - 2 * f(1) + 3 = - 2 * (-1) + 3 = 2 + 3 = 5

The correct result would be f(2) = 5.

With a principal investment of $19,200, which account will have the greatest value after 5 years? simple interest: I = P • r • t interest compounded annually is A = P (1 + r)t interest compounded quarterly: A = P (1 + )4t A. 3.6% with interest compounded annually B. 3.8% in a simple interest account C. 3.4% with interest compounded annually D. 3.2% with interest compounded quarterly

Answers

It would be a

he could only get 3.6%/per yr because 19200-3.6%=18508.8

A football player weighed 170 2/3 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall practice, he lost 10 1/4 pounds, and during the second week he lost another 3 1/2 pounds. How much did he weigh at that point?A: 182 1/3 lb
B: 181 1/2 lb
C: 182 5/12 lb
D: 183 2/3 lb

Help please?

Answers

We need to find the weight of a person at a certain period of time.

The weight of the person at the required time is A. $182(1)/(3)\ \text{lb}$

Initial weight of person = $170(2)/(3)$ pounds.

Weight gained = $25(5)/(12)$ pounds

Weight lost = $10(1)/(4)+3(1)/(2)$ pounds

So, weight of the person is

$170(2)/(3)+25(5)/(12)-(10(1)/(4)+3(1)/(2))\n =170+(2)/(3)+25+(5)/(12)-(10+(1)/(4)+3+(1)/(2))\n =195+(8+5)/(12)-13-(1+2)/(4)\n =182+(13)/(12)-(3)/(4)\n =182+(13-3)/(12)\n =182+(10)/(12)\n =182+(1)/(3)=182(1)/(3)$

The weight of the person at the required time is A. $182(1)/(3)\ \text{lb}$

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Answer:

182 1/3 lbs

MAY: weight = 170 2/3

Summer: gained 25 5/12

New weight : 170 2/3 + 25 5/12

Get a common denominator of 12

170 2/3 *4/4 + 25 5/12

170 8/12 + 25 5/12 = 195 13/12

The he lost 10 1/4 during the first week of fall practice

195 13/12 - 10 1/4

We need to get a common denominator of 12

195 13/12 - 10 1/4*3/3

195 13/12 - 10 3/12

185 10/12

The he lost another 3 1/2 pound during the second week

185 10/12 - 3 1/2

We need to get a common denominator of 12

185 10/12 - 3 1/2 * 6/6

185 10/12 - 3 6/12

182 4/12

Simplify the fraction

182 1/3 lbs

Hope this helps!

have a great day! :))))))

What is the answer please help

Answers

The answer for the problem is D

A is 24x25= 600
B is 76x77= 5,852
C is 242x243= 58,806
D is 766x767=587,522

So the wall is millimeter squared or LxW the answer is close to C

I need to find x by factoring but I was absent the day we reviewed and forgot from last year: the question is: If x^2+3x = 9x -8 what is the value of x?