How much heat (in kJ) must be added to 1.34 kg of ice at O'C to convert it to water to

Answers

Answer 1
Answer:

To change 1.34 kg of ice at 0°C to water, you would need to add approximately 448 kJ of heat.

To calculate the amount of heat needed to convert ice at 0°C to water, we use the formula Q = m * Lf. Where Q is the Heat Transfer, m is the mass of the substance (ice in this case), and Lf is the heat of fusion for ice, which is 334 kJ/kg.

Plugging in the values we have: Q = 1.34 kg * 334 kJ/kg = 447.56 kJ.

Therefore, you would need to add approximately 448 kJ of heat to convert 1.34 kg of ice at 0°C to water at the same temperature.

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Answer 2
Answer:

The heat required to convert 1.34 kg of ice at 0°C to water at 0°C is approximately 450.24 kJ.

When the substance freezes (changes from liquid to solid), the same amount of energy is released back into the surroundings. When a substance changes its phase (solid to liquid or liquid to gas) at a constant temperature, the heat required for this process is known as the heat of fusion.

For ice at its meltingpoint (0°C), the heat of fusion is approximately 336 kJ/kg. Thus for 1.34 kg of ice, we can calculate the heat required by using the formula below:

Heat = mass × heat of fusion

Heat = 1.34 kg × 336 kJ/kg

Heat = 450.24 kJ.

Learn more about mass here:

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The complete question is -

How much heat (in kJ) must be added to 1.34 kg of ice at 0°C to convert it to water at 0°C


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Which hybrid orbitals would be formed if one s orbital and three p orbitals combined? sp sp2 sp3 sp4

Answers

Answer: Four sp^3 hybridized orbitals will formed when one s-orbital and three p-orbitals combines.

Explanation:

  • When ever one s-orbital combines with three p-orbitals it gives four sp^3 hybridized orbitals.
  • In which there is 25% of s character and 75% of p character.
  • The shape of the sp^3 hybridized orbitals is Tetrahedral. As shown in image attached.

sp3 
it's just adding the number of s and p together 
example of sp3 hybridization = CH4 
with 1 s orbital of H and 3 p orbital of C

For metalloids on the periodic table, how do the group number and the period number relate? A. The lower the group number, the lower the period numbers, so the metalloids are found in a diagonal moving down from left to right.
B.The lower the group number, the higher the period numbers, so the metalloids are found in a diagonal moving up from left to right.
C.The higher the group number, the lower the period numbers, so the metalloids are found in a diagonal moving down from left to right.
D.The higher the group number, the higher the period numbers, so the metalloids are found in a diagonal moving up from left to right.

Answers

Answer : The correct option is A.

Explanation :

Metalloid : Metaloids are the elements whose properties lie between the metals and non-metals.

There are six commonly elements which are boron, silicon, germanium, arsenic, antimony and tellurium. The rare elements are polonium and astatine.

The relation between the group number and period number of metalloid is that the lower the group number, the lower the period numbers and the metalloids are found in a diagonal moving down from left to right in the periodic table.

Answer:

(A) The lower the group number, the lower the period numbers, so the metalloids are found in a diagonal moving down from left to right.

Explanation:

Search up a periodic table and you will see.

I also took the quiz and got 100.

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What is the study of the spectra produced from the emission and absorption of electromagnetic radiation? study of absorption spectrums study of emission spectrum nanotechnology spectroscopy

Answers

Answer the correct answer out of the four is option c spectroscopy

Explanation- The interaction between electromagnetic radiation and matter studied. This study is commonly known as spectroscopy. It can also be named as study of absorption spectra or emission spectra.

The former spectrum is formed when energy is absorbed from Photons or light energy by electrons while the latter spectrum is formed due to a wavelength of light that is released when electrons jump from higher to lower level.  

Answer:

D spectroscopy

Explanation:

Which statement is true about the use of radiation to treat cancer?Only weak X-rays can be used.
Only powerful X-rays can be used.
Only beta particles can be used.
Only alpha particles can be used.

Answers

The statement that is true about the use of radiation to treat cancer is that only powerful X-rays can be used. The radiation used for cancer treatment is known as ionizing radiation. These forms ions in the cells which could kill or stop them from growing. This type of radiation is have more energy than radio waves, microwaves and visible light.

Answer:

Only powerful x-rays can be used

Explanatijust did it and read it

The strength of a weak base is indicated by its "ionization constant Kb." The greater the value of Kb, the _____ the base. a) Weaker b) Stronger c) More neutral d) Less reactive

Answers

Kb is known as the base dissociation constant and the larger the value of kb the stronger the base. However, at times the values of kb are very small when dealing with calculations of weak bases. Hence, pKb is often used. Pkb = -lg(Kb)

A gas occupies 900.0 mL at a temperature of 27.0 . What is the volume at 132.0 °C?

Answers

V₁ = 900.0 mL

T₁ = 27.0ºC + 273 = 300 K

V₂ = ?

T₂ = 132.0 + 273 = 405 K

V₁ / T₁ = V₂ / T₂

900.0 / 300 = V₂ / 405

300 x V₂ = 405 x 900.0

300 x V₂ = 364500

V₂ = 364500 / 300

V₂ = 1215 mL

hope this helps!