How does matter and energy move through the water cycle

Answers

Answer 1

Answer: energy moves through an ecosystem when an organism is eaten. As you go up each trophic level, 10% of energy is transferred up. Matter on the other hand, is neither lost or gained. so it just moves up the trophic levels

Answer 2

Answer: I have attached a photo to explain. (:

Related Questions

Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. The length l of the bar obeys the following relation: l=1.0000+2.4×10−5T, where T is the number of degrees Celsius above room temperature. What is the change of the bar's length if the temperature is raised to 14.1 ∘C above room temperature?
What is the purpose of sensory adaptation
Alice and Tom dive from an overhang into the lake below. Tom simply drops straight down from the edge, but Alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. Neither person experiences any significant air resistance. Just as they reach the lake below.A) Alice reaches the surface the lake first. B) Tom of reaches the surface of the first. C) Alice and Tom will reach the surface of the lake at the same time. D) Information is not enough
Calculate surface tension of an enlarged radius of 4cm to 6cm and amount of work necessary for enlargement was 1.5×10^-4 joules
When baking soda and vinegar react, the product includes bubbles. What has most likely occurred? would it be a gas formation, exothermic reaction or precipitate formtion

If 2.0 x 10^-4 C charge passes a point in 5.0 x 10^-5 s, what is the rate of current flow?4.0 x 10^-1 A
1.0 x 10^2 A
1.0 x 10^-10 A
4.0 x 10^0 A

Answers

Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:

I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
I = 4 A or 4.0 x 10^0 A

Answer:

Explanation:

Which one of the following temperatures is equal to 5°C? A. 465 K
B. 0 K
C. 41 K
D. 278 K

Answers

Answer : The correct option is, (D) 278 K

Explanation :

We are given temperature $5^oC$ .

Now the conversion factor used for the temperature is,

$K=^oC+273$

where, K is kelvin and $^oC$ is Celsius.

Now put the value of temperature, we get

$K=5^oC+273=278K$

Therefore, the temperature 278 K is equal to the $5^oC$

Which of these components is not necessary for current to flow in a series or parallel circuit?A. wire
B. switch
C. resistor
D. All of these are needed.

Answers

Current requires only an EMF source ... like a battery, or a current already flowing ... and a conducting path ... like wire, ionized air, or something dissolved in water. A switch isn't needed unless you want a quick, easy way to STOP the current. A resistor isn't needed unless you want to be able to dissipate some energy from the current, or limit its magnitude.

do you think that this method of identifying unknowns would be effective for identifying any unknown element?

Answers

Unknowns, represented by variables, are effective for identifying the value. They stand for a certain amount, and solving for them would uncover values, like force etc.

A periodic wave has a fixed pattern that is repeated. What is one completion of the wave pattern called?a) period
b) frequency
c) amplitude
d)cycle
e) phase

Answers

It is called cycle. Letter D

Answer:

cycle. d

Explanation:

plato

If a platinum wire has a resistance of 15 Ω and is connected across the terminals of a 3.0 V flashlight battery, how much current is in the wire?

Answers

The voltage is presented by the equation V = IR where V is voltage in V, I is current in amperes ad R is resistance in ohms. If a platinum wire has a resistance of 15 Ω and is connected across the terminals of a 3.0 V flashlight battery, the current can be solved through V= IR, 3.0 V = I (15 Ω), and the current is 0.2 A.

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Can you help me with this pls