What is the gravitational potential energy of a book with a mass of 0.30 kg on a 1.0 m high desk?

Answers

Answer 1
Answer: given,
mass, m = .30kg
height, h = 1 m
gravitational acceleration, g = 9.8 m/s²

PE = mgh = .30kg*9.8m/s²*1m = 2.94 J
Answer 2
Answer:

Answer:

3.0

Same explanation as the person above but the significant figures must be considered in physics.


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"The radius of a sphere is increased by 25%. Find the percentage increase in surface area."

Answers

Answer:

Therefore, when the radius of a sphere is increased by 25%, the surface area increases by approximately 56.25%.

Explanation:

The surface area of a sphere is given by the formula:   Surface Area = 4πr^2   where r is the radius of the sphere.  

To find the percentage increase in surface area when the radius is increased by 25%, we can follow these steps:  

1. Let's assume the initial radius of the sphere is r.

2. If the radius is increased by 25%, the new radius will be 1.25r (since 25% is equivalent to multiplying by 1.25).  

3. Now, we can calculate the initial surface area (A1) using the formula: A1 = 4πr^2.  4.

Similarly, we can calculate the new surface area (A2) using the formula: A2 = 4π(1.25r)^2 = 4π(1.5625r^2) = 6.25πr^2.  

5. The percentage increase in surface area can be calculated as follows:   Percentage Increase = ((A2 - A1) / A1) * 100

 6. Plugging in the values we obtained earlier,

we have:  Percentage Increase = ((6.25πr^2 - 4πr^2) / 4πr^2) * 100  = ((2.25πr^2) / 4πr^2) * 100  = 56.25%  

Jawless fish and ocean reefs were devastated by which extinction? Late Devonian

Ordovician-Silurian

Permian-Triassic

End Triassic

Cretaceous-Tertiary

Answers

Late Devonian (I believe)

The Late Devonian.

If you go back and reach the text, you may find the passage, "Which species did we lose during this extinction (Late Devonian)? About 20% of all animal families and 70-80% of all animal species were lost. Major victims included the following:

....

- Jawless fish"

If you increase the height from which a water droplet falls, will this change the pattern of the ripples produced?

Answers

yes because it is coming from a different height and speed

Using the information from Paul Hewitt's Conceptual Development Practice Page 25-1 and the image below, answer the following question.Image of a wave with two rulers, one vertical and one horizontal, measuring the wave is shown. The wave's first crest aligns from 0 to just less than 4 centimeters on the horizontal ruler and rises from the equilibrium located at 5 centimeters to just before 3 centimeters. The wave's first trough aligns continues to just less than 8 centimeters on the horizontal ruler and goes down from the equilibrium located at 5 centimeters to just before 7 centimeters.What was the measurement of the wavelength and amplitude respectively?

Answers

Answer:

A = 2 cm,   λ = 8 cm

Explanation:

The amplitude of a wave is the maximum height it has, in this case the height is measured by the vertical ruler,

We are told the balance point is in the reading of 5 cm, that the maximum reading is 3 cm and the Minimum reading is 7 cm. Therefore, the distance from the ends of the ridge to the point of equilibrium is

          d = 7-5 = 2 cm

          d = 5-3 = 2 cm

          A = 2 cm

The wavelength is the minimum horizontal distance for which the wave is repeated, that is measured by the horizontal ruler.

The initial reading for 4 cm and the final reading for 8 cm, this distance corresponds to a crest of the wave, the complete wave is formed by two crests whereby the wavelength is twice this value

          Δx = 8-4 = 4 cm

          λ = 2 Δx

          λ = 8 cm

Assume that you have a mass of 50.0kg and earth has a mass of 5.97x10kg.The radius of earth is 6.38x10m.What is the force of gravitational attraction between you and the earth

Answers

The formula for force of attraction between any two bodies in the universe
F  =  GMm / r^2.      (Newton's Universal law of Gravitation).

G = Universal gravitational constant, G = 6.67 * 10 ^ -11  Nm^2 / kg^2.
M = Mass of first object. = 5.97 x 10^24 kg.
m = mass of second object = 50 kg.
r = distance apart, between centers = in this case it is the radius of the earth
   = 6.38 x 10^6 m.
( Sorry I could not assume with the values you gave).
(Actually the force of attraction between an object on the Earth and the Earth is the weight of the object our answer should be around 500N which is from mg = 50 *10 = 500)

So F = ((6.67 * 10 ^ -11)*(5.97 x 10^24)*(50)) / (6.38 x 10^6)^2.
  Punch it all up in your calculator.
F = 489. 135 N.

Remember we said it would be around 500.
So that's our answer.
F = 489. 135 N.    Hurray!!


Final answer:

The force of gravitational attraction between you (of mass 50kg) and the Earth (of mass 5.97x10^24 kg) can be calculated using Newton's Universal Law of Gravitation. Substituting the respective values in the formula, the calculated force is approximately 490.5 N.

Explanation:

The force of gravitational attraction between you and the earth can be calculated using Newton's Universal Law of Gravitation. This law states that the force (F) between two masses (m1 and m2) separated by a distance (r) is given by the formula F = G*(m1*m2/r^2), where G is the gravitational constant and is approximately 6.67x10^-11 N*(m^2/kg^2).

In this case, your mass (m1) is 50 kg, Earth's mass (m2) is 5.97x10^24 kg and the radius of Earth (r) is 6.38x10^6 m. Substituting these values into the formula, we can find the force of gravitational attraction between you and the Earth.

F = (6.67x10^-11 N*(m^2/kg^2)) * ((50 kg) * (5.97x10^24 kg)) / (6.38x10^6 m)^2. After calculating the above equation, you find that F ≈ 490.5 N.

Learn more about Gravitational Force here:

brainly.com/question/18961003

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Why is ammeter connected in series in an electric circuit?

Answers

In order to measure the size of the electrical current flowing in the circuit,
the current must pass through the meter.