Explain how the rabbit depend on energy from the sun.

Answer:

AgCl + NaNO₃

Explanation:

• The reaction between silver nitrate and sodium chloride is an example of a double displacement reaction.
• In a double displacement reaction compounds or salts reacts and exchange cations or anions to form new compounds or salts.
• In this case, silver nitrate and sodium chloride exchange anions and cations to form silver chloride and sodium nitrate.

• Therefore, the complete reaction is given by;

AgNO3 + NaCl → AgCl + NaNO₃

• But since silver chloride is a precipitate, the reaction may also be an example of a precipitation reaction.

Answer:

statement 2

Explanation:

Unlike metals, many non-metals are malleable and ductile. Thus, the correct option is B.

What are non-metals?

Non-metals are those metals which lack all the metallic attributes which are found in metallic elements. The non-metals are good insulators of heat and electricity. They are mostly gases and sometimes also liquid. Some of the elements then are even solid at room temperature include Carbon, sulphur and phosphorus.

A malleable material is the material in which a thin sheet can be easily formed through hammering. Gold is the most malleable metal found in nature. In contrast, ductility can be defined as the ability of a solid material to deform under the tensile stress.

Therefore, the correct option is B.

Learn more about Non-metals here:

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Answer:

a) 9.99 s

b) 538 m

c) 20.5 s

d) 1160 m

Explanation:

Given:

x₀ = 0 m

y₀ = 49.0 m

v₀ = 113 m/s

θ = 60.0°

aₓ = 0 m/s²

aᵧ = -9.8 m/s²

a) At the maximum height, the vertical velocity vᵧ = 0 m/s.  Find t.

vᵧ = aᵧ t + v₀ᵧ

(0 m/s) = (-9.8 m/s²) t + (113 sin 60.0° m/s)

t ≈ 9.99 s

b) At the maximum height, the vertical velocity vᵧ = 0 m/s.  Find y.

vᵧ² = v₀ᵧ² + 2aᵧ (y − y₀)

(0 m/s)² = (113 sin 60° m/s)² + 2 (-9.8 m/s²) (y − 49.0 m)

y ≈ 538 m

c) When the projectile lands, y = 0 m.  Find t.

y = y₀ + v₀ᵧ t + ½ aᵧ t²

(0 m) = (49.0 m) + (113 sin 60° m/s) t + ½ (-9.8 m/s²) t²

You'll need to solve using quadratic formula:

t ≈ -0.489, 20.5

Since negative time doesn't apply here, t ≈ 20.5 s.

d) When the projectile lands, y = 0 m.  Find x. (Use answer from part c).

x = x₀ + v₀ₓ t + ½ aₓ t²

x = (0 m) + (113 cos 60° m/s) (20.5 s) + ½ (0 m/s²) (20.5 s)²

x ≈ 1160 m