CHEMISTRY HIGH SCHOOL

Given that there are 1000mL in 1L how many liters are there in 0.0200mL

Answers

Answer 1

Answer:

Answer:

2×10^-5L

Explanation:

Since there are

1000mL in 1L

0.0200mL will give us

0.0200/1000

= 2×10^-5L

Answer 2

Answer:

Final answer:

To convert 0.0200mL to liters, we use the conversion factor 1L = 1000mL. The calculation becomes 0.0200mL divided by 1000, which equals to 0.00002L.

Explanation:

The given question asks, how many liters are there in 0.0200mL given the conversion factor that there are 1000mL in 1L. To calculate this, we will use the known conversion factor and divide 0.0200mL by 1000. Here are the steps:

Identify the conversion factor. We know that 1L = 1000mL.
Set up the calculation to convert mL to L. This will be: mL/1000 = L.
Substitute 0.0200mL into the equation: 0.0200mL/1000 = 0.00002L.

So there are 0.00002 liters in 0.0200mL.

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Fill in the missing reactant: NaOH + _____ → NaClO₂ + H₂O a. Cl₂
b. HCl
c. HClO
d. HClO₂
e. HClO₃

Answers

THE ANSWER IS OPTION D HClO2

The equation below shows the decomposition of lead nitrate. How many molecules of PbO are produced when 11.5 g NO2 is formed?2Pb(NO3 )2 (s) → 2PbO(s) + 4NO2 (g) + O2 (g)

Answers

Answer is in the file below

Which group tends to have the highest ionization energy? The lowest?a) Halogens; Alkaline earth metals
b) Alkali metals; Noble gases
c) Noble gases; Alkali metals

Answers

Final answer:

The group with the highest ionization energy is(option c) noble gases due to their full electron shell, making it difficult to remove an electron. The group with the lowest ionization energy is(option c) alkali metals because they have only one electron in their outermost shell, which can be easily removed.

Explanation:

The answer to the question is (c) Noble gases; Alkali metals. Ionization energy is the energy required to remove an electron from an atom or ion. A higher ionization energy means it is harder to remove an electron.

Noble gases have the highest ionization energies because they have a full electron shell, so they do not readily give up an electron. On the other hand, alkali metals have the lowest ionization energy, because they have only one electron in their outer shell, which is relatively easy to remove.

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Consider the following equilibrium:4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g)

Which of the following is a correct equilibrium expression?

A.
`"K"_("eq") = (["KOH"]^4["O"_2]^3)/(["KO"_2]^4["H"_2"O"]^2)`

B.
`"K"_("eq") = (["H"_2"O"]^2)/(["O"_2]^3)`

C.
`"K"_("eq") = (["KO"_2]^4["H"_2"O"]^2)/(["KOH"]^4["O"_2]^3)`

D.
`"K"_("eq") = (["O"_2]^3)/(["H"_2"O"]^2)`

Answers

Answer:

Answer is option D

Explanation:

The explanation is embedded in the word document attached

Answer:

Keq= [KOH]^4 [O2]^3/[[KO2]^4

Explanation:

4KO2(s) + 2H2O(l) → 4KOH(s) + 3O2(g)

Looking at the equation, the correct equilibrium expression is shown in the answer. The equilibrium constant for a reaction is given by the active masses of species involved in the reaction. The relative molar coefficients of species are raised to the power of their molar concentrations to give the active mass of each specie. This active mass now goes into the equilibrium equation.

Water is not included in the equilibrium equation because, as a solvent, it is present in large excess.

How do you find a Oxidation number

Answers

An oxidation number is the charge of the ion that would form if a covalent molecule was ionic. Oxidation numbers exist for covalent compounds, as ions are not formed.

The oxidation number is determined by the respective electronegativity of the atoms involved. A more electronegative element will always have a negative oxidation number. In the compound, all the oxidation numbers must add up to 0. Oxidation numbers of elements can vary between compunds.

A few rules to follow about oxidation numbers
Fluorine will always be -1
Oxygen will be -2 unless in a compound with fluorine
Hydrogen is usually +1

A few examples
HF (Hydrogen flouride) Oxy number of H= +1 and F = -1

H2O Oxy number of H = +1 and O= -2

NH3 Oxy of H= +1 and since there are 3 Hydrogens each with an oxidation number of +1 N must have an oxy number of -3 for the overall oxidation number of the compound to be 0.

H2SO4 Oxy number of H= +1 O=-2 When adding up the hydrogen and oxygen oxidation numbers ( 1 + 1 -2 - 2 -2 -2) we are left with -6 thus S must have an oxidation number of +6 for the overall number to be 0.

NO2 Oxidation number of O= -2 there are 2 oxygens leaving us with -4 thus N must have an Oxy number of +4 for the overall number to be 0.

In the doorbell configuration, describe what is initiated when someone presses the button outside your home.

Answers

Answer:

When the bell is rung the switch closes allowing electricity to flow making the hammer hit the bell, making the sound to alert people in the house.

Explanation:

Other Questions

1. The following reaction does not proceed to form a product: H2O + Au---> no reaction. Why is that?A) Gold has a higher activity than hydrogen and cannot replace it. B) Gold has a lower activity than hydrogen and cannot replace it. C) The reaction cannot occur because water is a reactant. D) The reaction proceeds too slowly to create products. 2. Which of the following is the balanced form of the equation C2H6 + O2 --> CO2 + H2O? answer choices are attached A,B,C,D top to bottom 3. The equation 2NaNO3 + CaCl2 ---> 2NaCl + Ca(NO3)2 is balanced. How many atoms of sodium (Na) are there on either side of the equation? A) one B) two C) four D) six 4. All single-displacement reactions can be classified as another type of reaction as well. What type of reaction is that? A) combustion B) redox C) synthesis D) decomposition 5. If ions change places and a gas is formed, then what type of reaction is indicated? A) double-displacement B) synthesis C) decomposition D) single-displacement

1. Ozone in Earth’s atmosphere is important because itA)absorbs harmful pollution.B)absorbs harmful radiation.C)helps clouds form.D)causes rain to fall.2.A. aB. bC. cD. d

Using the half-reaction method, balance the following redox reaction occurring in acidic solution:Ag + NO3- -> Ag+ + NO

A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?(1) 0.168 M (3) 0.620 M (2) 0.480 M (4) 0.801 M