5 example of the 1st , 2nd , 3rd law.
Answers
Answer:
The question seems to refer to Newton's Laws of Motion. Here are examples of the 1st, 2nd, and 3rd laws:
1st Law (Law of Inertia):
- An object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and direction unless acted upon by an external force.
- Example: When a car suddenly stops, passengers continue to move forward due to their inertia until a seatbelt or airbag applies a force to stop them.
2nd Law (Law of Acceleration):
- The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
- Example: When pushing a heavy box and a lighter box with the same amount of force, the lighter box accelerates more because it has less mass.
3rd Law (Law of Action and Reaction):
- For every action, there is an equal and opposite reaction.
- Example: When you push against a wall, the wall pushes back with an equal amount of force.
It's important to note that these laws are foundational principles in classical physics and are widely applicable in understanding the behavior of objects in motion.
Explanation:
Related Questions
What light is NOT in the visible light spectrum
A material that can easily flow is called aa. fluid.b. solid.c. buoyant force.d. hydraulic material.
A space vehicle deploys its re-entry parachute when it's traveling at a vertical velocity of -150 meters/second (negative because the parachute is going down.) It comes to rest at 0 meters/second after 30 seconds. What's the average acceleration of the shuttle during this time span?
two truckers are traveling directly away from each other at the same speed. If one trucker sounds her horn at a frequency of 206 Hz, and the other trucker hears a frequency of 189 Hz, determine the speed of the trucks. Use the speed of sound as 343 m/s. m/s
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Answer:
a) Q1= Q2= 11.75×10^-6Coulombs
b) Q1 =15×10^-6coulombs
Q2 = 38.75×10^-6coulombs
Explanation:
a) For a series connected capacitors C1 and C2, their equivalent capacitance C is expressed as
1/Ct = 1/C1 + 1/C2
Given C1 = 3.00 μF C2 = 7.75μF
1/Ct = 1/3+1/7.73
1/Ct = 0.333+ 0.129
1/Ct = 0.462
Ct = 1/0.462
Ct = 2.35μF
V = 5.00Volts
To calculate the charge on each each capacitors, we use the formula Q = CtV where Cf is the total equivalent capacitance
Q = 2.35×10^-6× 5
Q = 11.75×10^-6Coulombs
Since same charge flows through a series connected capacitors, therefore Q1= Q2=
11.75×10^-6Coulombs
b) If the capacitors are connected in parallel, their equivalent capacitance will be C = C1+C2
C = 3.00 μF + 7.75 μF
C = 10.75 μF
For 3.00 μF capacitance, the charge on it will be Q1 = C1V
Q1 = 3×10^-6 × 5
Q1 =15×10^-6coulombs
For 7.75 μF capacitance, the charge on it will be Q2 = 7.75×10^-6×5
Q2 = 38.75×10^-6coulombs
Note that for a parallel connected capacitors, same voltage flows through them but different charge, hence the need to use the same value of the voltage for both capacitors.
Answers
Answer: The slope of a line on a distance-time graph is- speed of the object.
The slope of a line on a graph refers to rate of change of variable that is presented on Y axis with respect to the variable that is presented on X axis.
For a distance time graph, distance is presented on Y axis and time on the X axis.
As we know that
Therefore, the slope of a line on a distance-time graph represents speed of the object.
Slope of any given curve is defined as
Rate of change in quantity on Y axis with respect to the quantity on x axis.
Here on Y axis if we plot distance and on X axis if time is plotted then
Slope = [tex] \frac{ds}{dt}[/tex}
above expression is rate of change in distance with time which shows apped of object
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Answers
c. a yellow star
b. a main sequence star
d. of average absolute magnitude
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Answer:
part of a binary system
Explanation:
Sun is a yellow star, it is a G-type main sequence star. It is yellow dwarf star. It is white but from our earth, it appears yellow. So it is a yellow star.
As mentioned, yes it is a main sequence star.
It is our main part of solar system so it appears to be huge for our earth, however it stands medium in the size among all other billions of stars in the universe.
Sun is solo star, It has no companion star associated with it (as with other stars which have one or more companion star with them making binary or tertiary etc system).
A) Part of a binary system. There is no evidence to suggest that the Sun has a companion star.
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no matter where the object goes.
The weight of the object is
(mass) x (gravity in the place where the object is) .
On the surface of the Earth,
Weight = (60 kg) x (9.8 m/s²)
= 588 Newtons.
Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to 5R from the center, the gravity out there is
(1R/5R)² = (1/5)² = 1/25 = 0.04 of its value on the surface.
The object's weight would also be 0.04 of its weight on the surface.
(0.04) x (588 Newtons) = 23.52 Newtons.
Again, the object's mass is still 60 kg out there.
___________________________________________
If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink.
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
Answer:
23.5 N
Explanation:
Just wanted to clarify something about the verified answer: Our only given measurement—the mass of the object—has 3 significant digits, so we can only include 3 significant digits in our answer.
23.52 N is NOT the correct answer. Your answer should only have 3 significant digits.
I just did the quiz where this problem came from, so I know that 23.5 N is the correct answer.